D = 1/5 + 1/5^2 + .. + 1/5^2022
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Câu 1: phương án B và D không có dấu = nên không xác định được đúng hay sai nên xem lại đề
![](https://rs.olm.vn/images/avt/0.png?1311)
\(S=-\dfrac{1}{5}+\dfrac{1}{5^2}-\dfrac{1}{5^3}+...+\dfrac{1}{5^{2022}}-\dfrac{1}{5^{2023}}\)
\(\Rightarrow\dfrac{25}{5}=-1+\dfrac{1}{5}-\dfrac{1}{5^2}+...+\dfrac{1}{5^{2021}}-\dfrac{1}{5^{2022}}\)
\(\Rightarrow5S+S=\left(-1+\dfrac{1}{5}-\dfrac{1}{5^2}+...+\dfrac{1}{5^{2021}}-\dfrac{1}{5^{2022}}\right)+\left(-\dfrac{1}{5}+\dfrac{1}{5^2}-...+\dfrac{1}{5^{2022}}-\dfrac{1}{5^{2023}}\right)\)
\(\Rightarrow6S=-1+\dfrac{1}{5}-\dfrac{1}{5^2}+...+\dfrac{1}{5^{2021}}-\dfrac{1}{5^{2022}}-\dfrac{1}{5}+\dfrac{1}{5^2}-...+\dfrac{1}{5^{2022}}-\dfrac{1}{5^{2023}}\)
\(\Rightarrow6S=-1-\dfrac{1}{5^{2023}}\)
\(\Rightarrow S=\dfrac{-1-\dfrac{1}{5^{2023}}}{6}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
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\(a,50\%+\dfrac{7}{12}-\dfrac{1}{2}\\ =\dfrac{1}{2}+\dfrac{7}{12}-\dfrac{1}{2}\\ =\left(\dfrac{1}{2}-\dfrac{1}{2}\right)+\dfrac{7}{12}\\ =\dfrac{7}{12}\\ b,2022\times67+2022\times43-2022\times10\\ =2022\times\left(67+43-10\right)\\ =2022\times100\\ =202200.\\ c,125-25:3\times12\)
\(=25\times5-25:3\times12\\ =25\times\left(5-\dfrac{1}{3}\right)\times12\\ =25\times\dfrac{14}{3}\times12\\ =1400\)
a,50%+127−21=21+127−21=(21−21)+127=127b,2022×67+2022×43−2022×10=2022×(67+43−10)=2022×100=202200.c,125−25:3×12
![](https://rs.olm.vn/images/avt/0.png?1311)
\(A=1+5+5^2+...+5^{2022}\)
\(5A=5+5^2+5^3+...+5^{2023}\)
\(5A-A=5+5^2+5^3+...+5^{2023}-\left(1+5+5^2+...+5^{2022}\right)\)
\(4A=5^{2023}-1\)
\(A=\dfrac{5^{2023}-1}{4}\)
A = 1 + 5 + 5² + ... + 5²⁰²²
⇒ 5A = 5 + 5² + 5³ + ... + 5²⁰²³
⇒ 4A = 5A - A
= (5 + 5² + 5³ + ... + 5²⁰²³) - (1 + 5 + 5² + ... + 5²⁰²²)
= 5²⁰²³ - 1
⇒ A = (5²⁰²³ - 1) : 4
![](https://rs.olm.vn/images/avt/0.png?1311)
(1/2 +1/3+1/4+...1/2022)x(5/6 -1/3:2/5)
=(1/2 +1/3+1/4+...1/2022)x 0
= 0
Tham khảo:
(1/2 +1/3+1/4+...1/2022)x(5/6 -1/3:2/5)
=(1/2 +1/3+1/4+...1/2022)x 0
= 0
bài 7:a thực hiện phép tính .81 x 2022 + 25 x 2022 - 6 x 2022 .B Tìm x biết ( x - 1 ) 2/3 - 1/5= 2/5
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,81\cdot2022+25\cdot2022-6\cdot2022=2022\cdot\left(81+25-6\right)=2022\cdot100=202200\)
\(b,\left(x-1\right)\cdot\frac{2}{3}-\frac{1}{5}=\frac{2}{5}\)
\(\left(x-1\right)\cdot\frac{2}{3}=\frac{3}{5}\)
\(x-1=\frac{9}{10}\)
\(x=\frac{19}{10}\)
Vậy \(x=\frac{19}{10}\)
( Nếu phần b là hỗn số thì mình làm thế kia , còn nếu là nhân thì bạn tham khảo Câu hỏi của lương bảo ngọc - Toán lớp 5 - Học trực tuyến OLM nhé )
81 x 2022 + 25 x 2022 - 6 x 2022
= ( 81 + 25 - 6 ) x 2022
= 100 x 2022
= 202 200
b) \(\left(\text{x - 1}\right)\frac{\text{2}}{\text{3}}-\frac{\text{1}}{\text{5}}=\frac{\text{2}}{\text{5}}\)
\(\frac{\text{3 x }\text{( x - 1 ) }+\text{2}}{\text{3}}=\frac{\text{1}}{\text{5}}+\frac{\text{2}}{\text{5}}=\frac{\text{3}}{\text{5}}\)
=> \(\text{3 x ( x - 1 ) }+\text{2}=\frac{\text{3}}{\text{5}}\text{ x 3 = }\frac{\text{9}}{\text{5}}\)
=> \(\text{3 x ( x - 1 ) }=\frac{\text{9}}{\text{5}}-\text{2}=\frac{\text{-1}}{\text{5}}\)
=> \(\text{ x-1}=\frac{\text{-1}}{\text{5}}:3=\frac{\text{-1}}{\text{15}}\)
=> \(\text{x}=\frac{\text{-1}}{\text{15}}+\text{1 = }\frac{\text{14}}{\text{15}}\)
\(\dfrac{1}{5^2}\)hay(\(\dfrac{1}{5}\))2
\(5D=1+\dfrac{1}{5}+...+\dfrac{1}{5^{2021}}\Rightarrow5D-D=1+\dfrac{1}{5}+...+\dfrac{1}{5^{2021}}-\dfrac{1}{5}-\dfrac{1}{5^2}-...-\dfrac{1}{5^{2022}}\)
\(4D=1-\dfrac{1}{5^{2022}}\Rightarrow D=\dfrac{1-\dfrac{1}{5^{2022}}}{4}\)