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\(\frac{2006\times2005-1}{2004\times2006+2005}=\frac{2006\times\left(2004+1\right)-1}{2004\times2006+2005}=\frac{2006\times2004+2006\times1-1}{2004\times2006+2005}=\frac{2006\times2004+2005}{2006\times2004+2005}=1\)
\(\frac{2006\times2005-1}{2004\times2006+2005}=\frac{2006\times\left(2004+1\right)-1}{2004\times2006+2005}=\frac{2004\times2006+2006\times1-1}{2004\times2006+2005}\)
\(=\frac{2004\times2006+2005}{2004\times2006+2005}=1\)
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2006 x 2005 - 1/2004 x 2006 + 2005
= 2006 x ( 2004 + 1 ) - 1/2004 x 2006 + 2005
= 2006 x 2004 + 2006 x 2005/2004 x 2006 + 2005
= 2006 x 2004 + 2005 / 2004 x 2006 + 2005
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\(\frac{2006.2005-1}{2004.2006+2005}\)
\(=\frac{2006\left(2004+1\right)-1}{2004.2006+2005}\)
\(=\frac{2006.2004+2006-1}{2004.2006-2005}\)
\(=\frac{2006.2004+2005}{2004.2006+2005}=1\)
nha
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A=\(\frac{2006x\left(2004+1\right)-1}{2006x2004+2005}=\frac{2006x2004+2006-1}{2006x2004+2005}\)
= \(\frac{2006x2004+2005}{2006x2004+2005}=1\)
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11
a , x+6=49-3-13
x+6=a
x=a-6
x=n
b,231-(x-6)=n
x-6=231-n
x-6=a
x=a+6
x=m
B1:
a)49-3.(x+6)=13
3.(x+6)=49-13
3.(x+6)=36
x+6=36/3
x+6=12
x=12-6
x=6
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a, 27.5 x 5.43 + 4.57 x 27.5
= 27.5 x ( 5.43 + 4.57 )
= 27.5 x 10
= 275
c,\(\frac{2006x2005-1}{2004x2006+2005}\)
= \(\frac{2006x\left(2004+1\right)-1}{2004x2006+2005}\)
= \(\frac{2006x2004+2006-1}{2004x2006+2005}\)
= \(\frac{2006x2004+2005}{2004x2006+2005}\)
= 1.
Mình chỉ biết từng nấy thôi.
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Ta chỉ việc tách ra thôi VD ta thấy L
2006x2005 = 2006x2004+2006x 1
Vây ta sẽ có cách làm như sau :
\(\frac{2006\cdot2005-1}{2004\cdot2006+2005}\)
\(=\frac{2006\cdot2004+2006\cdot1-1}{2004\cdot2006+2005}\)
\(=\frac{2006\cdot2004+2006-1}{2006\cdot2004+2005}\)
\(=\frac{2006\cdot2004+2005}{2004\cdot2006+2005}=1\)
\(\frac{2006\cdot2005-1}{2004\cdot2006+2005}=\frac{2006\cdot\left(2004+1\right)}{2004\cdot2006+2005}=\frac{2006\cdot2004+2006\cdot1-1}{2004\cdot2006+2005}=\frac{2006\cdot2004+2005}{2004\cdot2006+2005}=1\)