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2 tháng 7 2022

`0,5 + 1/3 + 0,4 + 5/7 + 1/6 - 4/35`

`=1/2 + 1/3 + 2/5 + 5/7 + 1/6 - 4/35`

`=(1/2 + 1/3 + 1/6) + ( 2/5 - 4/35 + 5/7)`

`= (3/6 + 2/6 + 1/6) + ( 14/35 - 4/35 + 25/35)`

`=((3+2+1)/6) + (( 14-4+25)/35)`

`= 6/6+ 35/35`

`=1+1`

`=2`

2 tháng 7 2022

\(0,5+\dfrac{1}{3}+0,4+\dfrac{5}{7}+\dfrac{1}{6}-\dfrac{4}{35}\)

\(=\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{2}{5}+\dfrac{5}{7}+\dfrac{1}{6}-\dfrac{4}{35}\)

\(=\left(\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{6}\right)+\left(\dfrac{5}{7}+\dfrac{2}{5}-\dfrac{4}{35}\right)\)

\(=1+\dfrac{39}{35}-\dfrac{4}{35}\)

\(=1+1=2\)

3 tháng 4 2019

Ta có 

C=\(\frac{1}{2}+\frac{1}{3}+\frac{2}{5}+\frac{5}{7}+\frac{1}{6}-\frac{4}{35}+\frac{1}{41}\)

\(\left(=\right)C=\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{6}\right)+\left(\frac{2}{5}+\frac{5}{7}-\frac{4}{35}\right)+\frac{1}{41}\)

\(\left(=\right)C=\left(\frac{3}{6}+\frac{2}{6}+\frac{1}{6}\right)+\left(\frac{14}{35}+\frac{25}{35}-\frac{4}{35}\right)+\frac{1}{41}\)

\(\left(=\right)c=1+\left(-1\right)+\frac{1}{41}=\frac{1}{41}\)

vì viết dưới dạng phân số chưa quen nên bn thông cảm cho mk nhé!

C = 0,5 + 1/3 + 0,4 + 5/7 + 1/6 - 4/35 + 1/41

= 5/10 + 1/3 + 4/10 + 5/7 + 1/6 - 4/35 + 1/41

= 1/2 + 1/3 + 2/5 + 5/7 + 1/6 - 4/35 + 1/41

= (1/2 + 1/3 + 1/6) + (2/5 + 5/7 - 4/35) +1/41

= (3/6+ 2/6 + 1/6) + ( 14/35 + 25/35 - 4/35) + 1/41

= 6/6 + 35/35 + 1/41

= 1 + 1 + 1/41 = 2 + 1/41 = 2/1 + 1/41

= 43/41 + 1/41 = 44/41

chúc bn học tốt

14 tháng 9 2021

a. \(\dfrac{-2}{3}+\dfrac{-1}{5}+\dfrac{3}{4}-\dfrac{5}{6}-\dfrac{7}{10}\)

\(\dfrac{-4}{6}+\dfrac{-2}{10}+\dfrac{3}{4}-\dfrac{5}{6}-\dfrac{7}{10}\)

\(\dfrac{-3}{2}+\dfrac{1}{2}+\dfrac{3}{4}\)

= (-1) + \(\dfrac{3}{4}\)

\(\dfrac{-4}{4}+\dfrac{3}{4}\)

\(\dfrac{-1}{4}\)

23 tháng 7

b; 0,5  + \(\dfrac{1}{3}\) + 0,4 + \(\dfrac{5}{7}\) + \(\dfrac{1}{6}\) - \(\dfrac{4}{35}\)

= (\(\dfrac{1}{3}\)\(\dfrac{1}{6}\) + \(\dfrac{1}{2}\)) + (\(\dfrac{5}{7}\)\(\dfrac{4}{35}\)+ \(\dfrac{2}{5}\))

= ( \(\dfrac{1}{2}\) + \(\dfrac{1}{2}\)) + (\(\dfrac{3}{5}\) + \(\dfrac{2}{5}\))

= 1 + 1 

= 2

\(=\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{6}+\dfrac{2}{5}+\dfrac{5}{7}-\dfrac{4}{35}\)

\(=\dfrac{3+2+1}{6}+\dfrac{14+25-4}{35}=1+1=2\)

14 tháng 8 2016

a)

1/12 + 1/6 + 1/2 = (1+2+6)/12 = 9/12 = 3/4 
1/30 + 1/20 = (2+3)/60 = 5/60 = 1/12 
1/56 + 1/42 = 1/7(1/8+1/6) = 1/7 .(3+4)/24 = 1/24 
8/9- 1/72 = (8.8 - 1)/72 = 63/72 = 7/8 
1/12 + 1/24 = (2+1)/24 = 1/8 
7/8 - 1/8 = 6/8 = 3/4 
3/4 - 3/4 = 0 
 

14 tháng 8 2016

b)

\(0,5+\frac{1}{3}+0,4+\frac{5}{7}+\frac{1}{6}-\frac{4}{35}\)

\(=\left(\frac{1}{2}+\frac{1}{3}+\frac{2}{3}+\frac{1}{6}\right)+\left(\frac{5}{7}-\frac{4}{35}\right)\)

\(=\frac{15+10+12+5}{30}+\frac{25-4}{35}\)

\(=\frac{7}{5}+\frac{3}{5}\)

\(=2\)

30 tháng 6 2017

\(0,5+\dfrac{1}{3}+0,4+\dfrac{5}{7}+\dfrac{1}{6}-\dfrac{4}{35}+\dfrac{1}{4}\)

\(=\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{2}{5}+\dfrac{5}{7}+\dfrac{1}{6}-\dfrac{4}{35}+\dfrac{1}{4}\)

\(=\left(\dfrac{1}{2}+\dfrac{1}{4}\right)+\left(\dfrac{1}{3}+\dfrac{1}{6}\right)+\left(\dfrac{2}{5}+\dfrac{5}{7}-\dfrac{4}{35}\right)\)

\(=\dfrac{3}{4}+\dfrac{1}{2}+1\)

\(=\dfrac{9}{4}\)

30 tháng 6 2017

\(0,5+\dfrac{1}{3}+0,4+\dfrac{5}{7}+\dfrac{1}{6}-\dfrac{4}{35}+\dfrac{1}{4}\)

=\(\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{2}{5}+\dfrac{5}{7}+\dfrac{1}{6}-\dfrac{4}{35}+\dfrac{1}{4}\)

=\(\left(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{4}+\dfrac{1}{3}\right)+\left(\dfrac{2}{5}+\dfrac{5}{7}-\dfrac{4}{35}\right)\)

=\(\dfrac{5}{4}+1\)

=\(\dfrac{9}{4}\)

30 tháng 6 2016
  1. C = \(\frac{83}{41}\)
  2. D = \(\frac{-79}{90}\)
20 tháng 4 2016

C=0.5+1/3+0.4+5/7+1/6-4/35+1/41

C=1/2+1/3+2/5+5/7+1/6-4/35+1/41

C=(1/2+1/6+1/3)+(2/5+5/7-4/35)+1/41

C=1+1-1/41

C=2-1/41

=>C=81/41

D=1/90-1/72-1/56-1/42-1/30-1/20--1/12-1/6-1/2

=> D=1/9*10-1/8*9-1/7*8-1/6*7-1/5*6-1/4*5-1/3*4-1/2*3-1/1*2

=>D=-(1/1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7+1/7-1/8+1/8-1/9+1/9-1/10)
=>D=-(1-1/10)

=>D=-9/10

ai k mh mh k lại

5 tháng 3 2018

C.D=18/10 nha

15 tháng 4 2017

\(0,5+\dfrac{1}{3}+0,4+\dfrac{5}{7}+\dfrac{1}{6}-\dfrac{4}{35}+\dfrac{1}{41}\)

\(=\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{2}{5}+\dfrac{5}{7}+\dfrac{1}{6}-\dfrac{4}{35}+\dfrac{1}{41}\)

\(=\left(\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{6}\right)+\left(\dfrac{2}{5}+\dfrac{5}{7}-\dfrac{4}{35}\right)+\dfrac{1}{41}\)

\(=\left(\dfrac{3}{6}+\dfrac{2}{6}+\dfrac{1}{6}\right)+\left(\dfrac{14}{35}+\dfrac{25}{35}-\dfrac{4}{35}\right)+\dfrac{1}{41}\)

\(=\dfrac{3+2+1}{6}+\dfrac{14+25-4}{35}+\dfrac{1}{41}\)

\(=1+1+\dfrac{1}{41}\)

\(=2+\dfrac{1}{41}\)

\(=2\dfrac{1}{41}=\dfrac{83}{41}\)