Tìm n biết 27^n : 3^n = 81
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=> (27 : 9)n = 927 : 92
=> 3n = 925
=> 3n = (32)25
=> 3n = 350
=> n = 50
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(3^{a+1}=81\)
\(3^{a+1}=3^4\)
\(a+1=4\)
\(a=3\)
b) \(\left(x-1\right)^3=27\)
\(\left(x-1\right)^3=3^3\)
\(x-1=3\)
\(x=4\)
\(a,3^{a+1}=81\\ \Rightarrow3^{a+1}=3^4\\ \\ \Rightarrow a+1=4\\ \Rightarrow a=3.\\ b,\left(x-1\right)^3=27\\ \Rightarrow\left(x-1\right)^3=3^3\\ \Rightarrow x-1=3\\ \Rightarrow x=4.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(27^n.9^n=9^{27}:81\)
\(3^{3n}.3^{2n}=3^{54}:3^4\)
\(3^{5n}=3^{50}\)
=> 5n = 50
=> n = 10
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{\left(-3\right)^n}{81}=-27\)
=> (-3)n = -27.81
=> (-3)n = -(27.81)
=> (-3)n = -(33.34)
=> (-3)n = -37 = (-3)7
=> n = 7
Vậy n = 7
\(\frac{\left(-3\right)^n}{81}=-27\)
\(\left(-3\right)^n:81=-27\)
\(\left(-3\right)^n=-27\cdot81\)
\(\left(-3\right)^n=-2187\)
\(\left(-3\right)^n=\left(-3\right)^7\)
\(=>n=7\)
![](https://rs.olm.vn/images/avt/0.png?1311)
mk ghi lại đề nha:
27n : 9n = 927 : 81
(27 : 9)n = 927 : 92
\(\Rightarrow\) 3n = 925
\(\Rightarrow\) 3n = (32)25
\(\Rightarrow\) 3n = 350
Vậy n = 50
\(27^n.9^n=9^{27}:81\Rightarrow3^{3n}:3^{2n}=3^{54}:3^4=3^{50}\)
\(\Rightarrow3^{5n}=3^{50}\Rightarrow5n=50\Rightarrow n=\frac{50}{5}=10\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\frac{\left(-3\right)^n}{81}=-27\)
\(\Rightarrow\left(-3\right)^n=-2187\)
\(\Rightarrow\left(-3\right)^n=\left(-3\right)^7\)
\(\Rightarrow n=7\)
Vậy \(n=7\)
b) \(8^n:2^n=4\)
\(8^n:2^n=4^1\)
mà \(8:2=4\)
\(\Rightarrow n=1\)
Vậy \(n=1\)
27n : 3n = 81
(27 : 3)n = 81
9n = 81 = 92
=> n = 2
\(27^n:3^n=81\)
\(\Rightarrow\left(27:3\right)^n=81\)
\(\Rightarrow9^n=81=9^2\)
\(\Rightarrow n=2\)