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8 tháng 3 2022

\(\frac{5}{12}:\frac{3}{4}-\frac{1}{3}=\frac{5}{12}.\frac{4}{3}-\frac{1}{3}=\frac{5.4}{12.3}-\frac{1}{3}=\frac{5}{9}-\frac{1}{3}=\frac{5}{9}-\frac{3}{9}=\frac{2}{9}\)

HT nha 

8 tháng 3 2022

Dấu chấm \(.\)

là nhân nha

13 tháng 7 2021

`a)5/8x+2/5=1/5`

`=>5/8x=1/5-2/5`

`=>5/8x=-1/5`

`=>x=-1/5:5/8=-8/25`

`b)5/7:x+11/7=18/7`

`=>5/7:x=18/7-11/7`

`=>5/7:x=1`

`=>x=5/7`

`c)(-1,2).(-3/24)+(0,4-1 4/15):1 2/3`

`=(-6/5).(-1/8)+(2/5-19/15):5/3`

`=3/20+(-13/15)*3/5`

`=3/20-13/25=-37/100`

13 tháng 7 2021

a)5/8.x+2/5=1/5

5/8.x=1/5 - 2/5

5/8.x=-1/5

x=(-1/5):5/8

x=(-1/5).8/5

x=-8/25.      Vậy x=-8/25

b)5/7:x +11/7=18/7

5/7:x=1

x=5/7:1

x=5/7.      Vậy x=5/7

x-3/-9 = -4/x-3

(x-3)^2=-9.-4=36

=>TH1 x-3= 6

   TH2  x-3 = -6

=> TH1: X= 9

     TH2: X=-3

=>(x-3)^2=36

=>x-3=6 hoặc x-3=-6

=>x=-3; x=9

22 tháng 3 2022

mọi người ơi giúp em vs ạ , e đang rất cần 

 

23 tháng 3 2022

\(1+2+...+n=\dfrac{\left(\dfrac{n-1}{1}+1\right).\left(n+1\right)}{2}=\dfrac{n\left(n+1\right)}{2}\)

\(M=\dfrac{3}{1+2}+\dfrac{3}{1+2+3}+...+\dfrac{3}{1+2+...+2022}\)

\(=3\left(\dfrac{1}{1+2}+\dfrac{1}{1+2+3}+...+\dfrac{1}{1+2+...+2022}\right)\)

\(=3\left(\dfrac{1}{\dfrac{2.\left(2+1\right)}{2}}+\dfrac{1}{\dfrac{3.\left(3+1\right)}{2}}+...+\dfrac{1}{\dfrac{2022.\left(2022+1\right)}{2}}\right)\)

\(=3\left(\dfrac{2}{2.3}+\dfrac{2}{3.4}+...+\dfrac{2}{2022.2023}\right)\)

\(=3.2.\left(\dfrac{1}{2.3}+\dfrac{1}{3.4}+...+\dfrac{1}{2022.2023}\right)\)

\(=6.\left(\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{2022}-\dfrac{1}{2023}\right)\)

\(=6.\left(\dfrac{1}{2}-\dfrac{1}{2023}\right)\)

\(=6.\dfrac{2021}{4046}=3.\dfrac{2021}{2023}=\dfrac{6063}{2023}=\dfrac{18189}{6069}\)

\(\dfrac{10}{3}=\dfrac{20230}{6069}>\dfrac{18189}{6069}=M\)

 

26 tháng 2 2022

\(a.\dfrac{12}{3}=\dfrac{20}{5}=4\\ b.\dfrac{9}{-3}=\dfrac{-15}{5}=-3\)

26 tháng 2 2022

a, Xét \(\dfrac{x}{3}=4\Rightarrow x=12;\dfrac{20}{y}=4\Rightarrow y=\dfrac{20}{4}=5\)

b, \(\dfrac{9}{-x}=-3\Rightarrow-x=-3\Leftrightarrow x=3\)

\(\dfrac{y}{5}=-3\Rightarrow y=-15\)

7 tháng 4 2022

\(x=\dfrac{11}{3}-\dfrac{3}{4}=\dfrac{35}{12}\)

11 tháng 12 2021

x,y∈Z⇒x+1,xy-1∈Z và x+1,xy-1 thuộc Ư(3)

Ta có bảng:

x+113-1-3
xy-131-3-1
x02-2-4
yloại110

Vậy \(\left(x,y\right)\in\left\{\left(2;1\right)\left(-2;1\right);\left(-4;0\right)\right\}\)

 

11 tháng 12 2021

Vì x,y là chữ số nên \(x,y\in\left\{0;1;2;3;4;5;6;7;8;9\right\}\)

Ta có \(\left(x+1\right)\left(xy-1\right)=3=3.1=1.3\)

Với \(\left\{{}\begin{matrix}x+1=3\\xy-1=1\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=2\\y=1\end{matrix}\right.\)

Với \(\left\{{}\begin{matrix}x+1=1\\xy-1=3\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=0\\-1=3\end{matrix}\right.\left(loại\right)\)

Vậy \(\left(x;y\right)=\left(2;1\right)\)

17 tháng 8 2021

TYPE 1

if i have time,i will watch a movie

if we don't hurry up,we will miss our flight

TYPE 2

if i spoke English,i would work in America

if i had a lot of money,i could travel everywhere

if i were you,i wouldn't do that

TYPE 3

If I had studied harder, I would have passed the exam

If it hadn't rained, she would have gone to the beach

She would have been there on time if her car hadn't broken down

If he hadn’t got a job in London ,he would have married Jennie.

 

17 tháng 8 2021

cảm ơn nhaaa :3

24 tháng 8 2023

a) \(...=-\dfrac{1}{4}.\dfrac{4}{17}.\left(-\dfrac{63}{21}\right).\left(-\dfrac{7}{12}\right)\)

\(=-\dfrac{1}{17}.\dfrac{63}{21}.\dfrac{7}{12}\)

\(=-\dfrac{7}{68}\)

b) \(...=-\dfrac{2}{5}.\dfrac{4}{15}-\dfrac{3}{10}.\dfrac{4}{15}\)

\(=\dfrac{4}{15}\left(-\dfrac{2}{5}-\dfrac{3}{10}\right)\)

\(=\dfrac{4}{15}\left(-\dfrac{4}{10}-\dfrac{3}{10}\right)\)

\(=\dfrac{4}{15}.\left(-\dfrac{7}{10}\right)=-\dfrac{14}{75}\)

c) \(...=21-\dfrac{15}{4}:\left(\dfrac{9}{24}-\dfrac{4}{24}\right)\)

\(=21-\dfrac{15}{4}:\dfrac{5}{24}\)

\(=21-\dfrac{15}{4}.\dfrac{24}{5}\)

\(=21-3.6=3\)

d) \(...=\left(-\dfrac{3}{4}+\dfrac{2}{5}\right).\dfrac{7}{3}+\left(\dfrac{3}{5}-\dfrac{1}{4}\right).\dfrac{7}{3}\)

\(=\dfrac{7}{3}\left(-\dfrac{3}{4}+\dfrac{2}{5}+\dfrac{3}{5}-\dfrac{1}{4}\right)\)

\(=\dfrac{7}{3}\left(-\dfrac{3}{4}-\dfrac{1}{4}+\dfrac{2}{5}+\dfrac{3}{5}\right)\)

\(=\dfrac{7}{3}\left(-1+1\right)=0\)