tìm x : 456x -456 + (-207936) x \(\sqrt{25}\) x 2
giúp mình nha
K
Khách
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Y
31 tháng 5 2023
\(a,50\%x-0,2+x=\dfrac{4}{5}\)
\(\Leftrightarrow\dfrac{1}{2}x-0,2+x=\dfrac{4}{5}\)
\(\Leftrightarrow\dfrac{1}{2}x+x=\dfrac{4}{5}+0,2\)
\(\Leftrightarrow\dfrac{3}{2}x=\dfrac{4}{5}+\dfrac{1}{5}\)
\(\Leftrightarrow\dfrac{3}{2}x=1\)
\(\Leftrightarrow x=\dfrac{2}{3}\)
\(b,\left(x-\dfrac{3}{4}\right):\dfrac{1}{2}+\dfrac{3}{2}=\dfrac{25}{2}\)
\(\Leftrightarrow\left(x-\dfrac{3}{4}\right).2=\dfrac{25}{2}-\dfrac{3}{2}\)
\(\Leftrightarrow\left(x-\dfrac{3}{4}\right).2=\dfrac{22}{2}\)
\(\Leftrightarrow x-\dfrac{3}{4}=11:2\)
\(\Leftrightarrow x=\dfrac{11}{2}+\dfrac{3}{4}\)
\(\Leftrightarrow x=\dfrac{25}{4}\)
7 tháng 3 2022
\(\dfrac{3}{x-5}=\dfrac{-4}{x+2}\left(x\ne5;-2\right).\\ \Leftrightarrow\dfrac{3}{x-5}+\dfrac{4}{x+2}=0.\\ \Leftrightarrow\dfrac{3x+6+4x-20}{\left(x-5\right)\left(x+2\right)}=0.\\ \Rightarrow7x=14.\\ \Leftrightarrow x=2\left(TM\right).\)
12 tháng 9 2021
\(a,M=\left(\dfrac{\sqrt{x}}{\sqrt{x}-1}+\dfrac{\sqrt{x}}{\sqrt{x}+1}\right):\left(\dfrac{2}{x}-\dfrac{2-x}{x\sqrt{x}+x}\right)\left(x>0;x\ne1\right)\\ M=\dfrac{x+\sqrt{x}+x-\sqrt{x}}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}:\dfrac{2\sqrt{x}+2-2+x}{x\left(\sqrt{x}+1\right)}\\ M=\dfrac{2x}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\cdot\dfrac{x\left(\sqrt{x}+1\right)}{\sqrt{x}\left(\sqrt{x}+2\right)}\\ M=\dfrac{2x}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+2\right)}\)
\(b,M=-\dfrac{1}{2}\Leftrightarrow\dfrac{2x}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+2\right)}=-\dfrac{1}{2}\\ \Leftrightarrow-4x=x+\sqrt{x}-2\\ \Leftrightarrow5x+\sqrt{x}-2=0\)
Đặt \(\sqrt{x}=t\)
\(\Leftrightarrow5t^2+t-2=0\\ \Delta=1^2-4\cdot5\left(-2\right)=41\\ \Leftrightarrow\left[{}\begin{matrix}t=\dfrac{-1-\sqrt{41}}{10}\\t=\dfrac{-1+\sqrt{41}}{10}\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{-\left(1+\sqrt{41}\right)^2}{100}=\dfrac{-42-2\sqrt{41}}{100}\\x=\dfrac{\left(\sqrt{41}-1\right)^2}{100}=\dfrac{42-2\sqrt{41}}{100}\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{-21-\sqrt{41}}{50}\left(L\right)\\x=\dfrac{21-\sqrt{41}}{50}\left(N\right)\end{matrix}\right.\\ \Leftrightarrow x=\dfrac{21-\sqrt{41}}{50}\)
12 tháng 9 2021
a: Ta có: \(M=\left(\dfrac{\sqrt{x}}{\sqrt{x}-1}+\dfrac{\sqrt{x}}{\sqrt{x}+1}\right):\left(\dfrac{2}{x}+\dfrac{x-2}{x\sqrt{x}+x}\right)\)
\(=\dfrac{x+\sqrt{x}+x-\sqrt{x}}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}:\dfrac{2\sqrt{x}+2+x-2}{x\left(\sqrt{x}+1\right)}\)
\(=\dfrac{2x}{\sqrt{x}-1}\cdot\dfrac{x}{\sqrt{x}\left(\sqrt{x}+2\right)}\)
\(=\dfrac{2x\sqrt{x}}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-1\right)}\)
H9
HT.Phong (9A5)
CTVHS
27 tháng 8 2023
\(\left|x+1\right|-\left|-2x-2\right|=2\)
\(\Leftrightarrow\left|x+1\right|-\left|-2\left(x+1\right)\right|=2\)
\(\Leftrightarrow\left|x+1\right|-2\left|x+1\right|=2\)
\(\Leftrightarrow-\left|x+1\right|=2\)
\(\Leftrightarrow\left|x+1\right|=-2\)
\(\Leftrightarrow\left|x+1\right|+2=0\)
Mà: \(\left|x+1\right|\ge0\forall x\Rightarrow\left|x+1\right|+2\ge2>0\)
\(\Leftrightarrow\left|x+1\right|+2=0\) (vô lí)
Vậy phương trình vô nghiệm:
\(x\in\varnothing\)
27 tháng 8 2023
=>|x+1|-2|x+1|=2
=>-|x+1|=2
=>|x+1|=-2(vô lý)
Vậy: \(x\in\varnothing\)
NT
3
20 tháng 12 2019
Ta có: X x 456 + X x 544 + X = 12000
X x ( 456 + 544 + 1) = 12000
X x 1001 = 12000
X = 12000/1001
20 tháng 12 2019
\(X\cdot456+X\cdot544+X=12000\)
\(X\cdot\left(456+544+1\right)=12000\)
\(X\cdot1001=12000\)
\(X=\frac{12000}{1001}\)
\(X=11\frac{989}{1001}\)
\(\cdot\)\(Là\)x (nhân) nha
NN
1
NV
Nguyễn Việt Lâm
Giáo viên
21 tháng 8 2021
Đặt \(x+2=t\ne0\Rightarrow x+1=t-1\)
\(A=\dfrac{x+1}{\left(x+2\right)^2}=\dfrac{t-1}{t^2}=-\dfrac{1}{t^2}+\dfrac{1}{t}=-\left(\dfrac{1}{t}-\dfrac{1}{2}\right)^2+\dfrac{1}{4}\le\dfrac{1}{4}\)
\(A_{max}=\dfrac{1}{4}\) khi \(t=2\) hay \(x=0\)
TP
4
= (-207936) + (-207936) x 5 x 2
= (-207936) + (-207936) x 10
= (-207936) x (1 + 10)
= (-207936) x 11
= -2287296
k nha!!
456x-456=(-207936)x\(\sqrt{25}\) x2
=> 456(x-1)=-207936x5x2
=> x-1=-2079360:456
=> x-1=-4560
=> x=-4560+1=-4559