9x3=
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Lời giải của các bạn đều thỏa mãn yêu cầu đề bài là phân tích đa thức thành nhân tử
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a: \(=\dfrac{3}{5}+\dfrac{2}{7}=\dfrac{21+10}{35}=\dfrac{31}{35}\)
b: \(=\dfrac{6}{5}+\dfrac{3}{2}\cdot\dfrac{1}{3}=\dfrac{6}{5}+\dfrac{1}{2}=\dfrac{12+5}{10}=\dfrac{17}{10}\)
c: \(=\dfrac{5\cdot3}{9}=\dfrac{5}{3}\)
d: =5-2/3*6/5
=5-12/15
=5-4/5
=21/5
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\(\Rightarrow x\left(9x^2-2\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=0\\x^2=\dfrac{2}{9}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{\sqrt{2}}{3}\\x=-\dfrac{\sqrt{2}}{3}\end{matrix}\right.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(9\cdot3^3\cdot\dfrac{1}{81}\cdot3^2=\dfrac{3^7}{3^4}=27\)
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\(\left\{{}\begin{matrix}x^2+y^2=9\\x^3+y^3=-27\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}\left(x+y\right)^2-2xy=9\\\left(x+y\right)^3-3xy\left(x+y\right)=-27\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}a^2-2b=9\\a^3-3ab=-27\end{matrix}\right.\left(a=x+y;b=xy\right)\)
\(\Leftrightarrow\left\{{}\begin{matrix}b=\dfrac{a^2-9}{2}\\a^3-\dfrac{3a\left(a^2-9\right)}{2}=-27\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}b=\dfrac{a^2-9}{2}\\a^3-27a-54=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}b=\dfrac{a^2-9}{2}\\\left(a+3\right)^2\left(a-6\right)=0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}b=\dfrac{27}{2}\\a=6\end{matrix}\right.\left(I\right)\) hoặc \(\left\{{}\begin{matrix}b=0\\a=-3\end{matrix}\right.\left(II\right)\)
\(\left(I\right)\Leftrightarrow\left\{{}\begin{matrix}xy=\dfrac{27}{2}\\x+y=6\end{matrix}\right.\Rightarrow\) vô nghiệm
\(\left(II\right)\Leftrightarrow\left\{{}\begin{matrix}xy=0\\x+y=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}\left\{{}\begin{matrix}x=0\\y=-3\end{matrix}\right.\\\left\{{}\begin{matrix}x=-3\\y=0\end{matrix}\right.\end{matrix}\right.\)
Vậy ...
![](https://rs.olm.vn/images/avt/0.png?1311)
\(x^4-9x^3+x^2-9x=0\)
\(\Leftrightarrow x\left(x^2+1\right)\left(x-9\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=9\end{matrix}\right.\)
9x3=27
9*3=27