\(\frac{43}{82}\): \(\frac{5}{3}\)=???? ai nhanh mk tick !!!!
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LL
30 tháng 4 2018
\(\frac{8}{15}+\frac{16}{30}+\frac{3}{5}+\frac{9}{10}+2\frac{3}{5}\)
\(=\frac{8}{15}+\frac{16}{30}+\frac{3}{5}+\frac{9}{10}+\frac{13}{5}\)
\(=\frac{16+16+18+27+78}{30}\)
\(=\frac{155}{30}\)
\(=\frac{31}{6}\)
Hc tốt #
30 tháng 4 2018
\(\frac{8}{15}\)+\(\frac{16}{30}\)+\(\frac{3}{5}\)+\(\frac{9}{10}\)+2\(\frac{3}{5}\)
=\(\frac{16}{30}\)+\(\frac{16}{30}\)+\(\frac{18}{30}\)+\(\frac{27}{30}\)+\(\frac{13}{5}\)
=\(\frac{16+16+18+27}{30}\)+\(\frac{78}{30}\)
=\(\frac{77}{30}\)+\(\frac{78}{30}\)= \(\frac{155}{30}\)
NL
1
HJ
5 tháng 8 2017
a, \(\frac{6+x}{33}=\frac{7}{11}\)
\(\Leftrightarrow\left(6+x\right).11=7.33\)
\(\Leftrightarrow66+11x=231\)
\(\Leftrightarrow11x=231-66\)
\(\Leftrightarrow x=\frac{165}{11}=15\)
Vậy x = 15.
b,\(\frac{12+x}{43-x}=\frac{2}{3}\)
\(\Leftrightarrow3.\left(12+x\right)=2\left(43-x\right)\)
\(\Leftrightarrow36+3x=86-2x\)
\(\Leftrightarrow3x+2x=-36+86\)
\(\Leftrightarrow5x=50\)
\(\Leftrightarrow x=10\)
Vây x = 10.
1 tháng 3 2020
Ta có:\(23\frac{1}{3}:\frac{-1}{2^3}-13\frac{1}{3}:\frac{-1}{2^2}+5.\sqrt{\frac{9}{25}}=\frac{70}{3}:\frac{-1}{8}-\frac{40}{3}:\frac{-1}{4}+5.\frac{3}{5}\)
\(=\frac{70}{3}.\left(-8\right)-\frac{40}{3}.\left(-4\right)+3\)
\(=\frac{10}{3}.\left(-4\right).\left(2.7-4\right)+3\)
\(=\frac{-40}{3}.\left(14-4\right)+3\)
\(=\frac{-40}{3}.10+3\)
\(=\frac{-400}{3}+3\)
\(=\frac{-391}{3}\)
24 tháng 6 2017
\(\frac{\frac{1}{9}-\frac{1}{7}-\frac{1}{11}}{\frac{4}{9}-\frac{4}{7}-\frac{4}{11}}+\frac{\frac{3}{5}-\frac{3}{25}-\frac{3}{125}-\frac{3}{625}}{\frac{4}{5}-\frac{4}{25}-\frac{4}{125}-\frac{4}{625}}\)
\(=\frac{1\left(\frac{1}{9}-\frac{1}{7}-\frac{1}{11}\right)}{4.\left(\frac{1}{9}-\frac{1}{7}-\frac{1}{11}\right)}+\frac{3.\left(\frac{1}{5}-\frac{1}{25}-\frac{1}{125}-\frac{1}{625}\right)}{4.\left(\frac{1}{5}-\frac{1}{25}-\frac{1}{125}-\frac{1}{625}\right)}\)
\(=\frac{1}{4}+\frac{3}{4}=1\)
24 tháng 6 2017
\(\frac{\frac{1}{9}-\frac{1}{7}-\frac{1}{11}}{\frac{4}{9}-\frac{4}{7}-\frac{4}{11}}+\frac{\frac{3}{5}-\frac{3}{25}-\frac{3}{125}-\frac{3}{625}}{\frac{4}{5}-\frac{4}{25}-\frac{4}{125}-\frac{4}{625}}\)
\(=\frac{\frac{1}{9}-\frac{1}{7}-\frac{1}{11}}{4\left(\frac{1}{9}-\frac{1}{7}-\frac{1}{11}\right)}+\frac{3\left(\frac{1}{5}-\frac{1}{25}-\frac{1}{125}-\frac{1}{625}\right)}{4\left(\frac{1}{5}-\frac{1}{25}-\frac{1}{125}-\frac{1}{625}\right)}\)
\(=\frac{1}{4}+\frac{3}{4}\)
=1
L
2
20 tháng 6 2018
\(x\cdot y=20\)\(\Rightarrow x=\frac{20}{y}\)
thay vào biểu thức ta đc
\(\frac{\frac{20}{y}}{5}=\frac{y}{4}\)
\(\frac{20}{y}\cdot4=5y\)
\(\frac{80}{y}=5y\)
\(80=5y^2\)
\(16=y^2\)
\(\Rightarrow y=4\)
\(\Rightarrow x=\frac{20}{4}=5\)
hok tốt
20 tháng 6 2018
\(\frac{x}{5}=\frac{y}{4}\) biết x.y=20
Ta có:\(\frac{x}{5}=\frac{y}{4}=\frac{x.y}{5.4}=\frac{20}{20}=1\)
*\(\frac{x}{5}=1\Rightarrow x=5;\frac{y}{4}=1\Rightarrow y=4\)
9 tháng 9 2017
\(A=\frac{5}{1.2}+\frac{5}{2.3}+...+\frac{5}{7.8}\)
\(\Rightarrow5A=\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{7.8}\)
\(\Rightarrow5A=1.\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-...-\frac{1}{8}\right)\)
\(\Rightarrow5A=1-\frac{1}{8}\)
\(\Rightarrow A=\left(1-\frac{1}{8}\right).\frac{1}{5}=\frac{7}{40}\)
Q
9 tháng 9 2017
\(A=\frac{5}{1.2}+\frac{5}{2.3}+...+\frac{5}{7.8}\)
\(A=5\left(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{5}{7.8}\right)\)
\(A=5\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{7}-\frac{1}{8}\right)\)
\(A=5\left(1-\frac{1}{8}\right)\)
\(A=5.\frac{7}{8}\)
\(A=\frac{38}{8}\)
5 tháng 12 2018
B=-4/5+4/52-4/53+...+4/5200
5B=-4+4/5-4/52+...+4/5201
5B+B=-4+4/5200
6B=-4x5200/5200+4/5200
6B=-4+4x5200/5200
Còn lại bạn tính nốt nha
KN
13 tháng 6 2019
\(\left(\frac{5}{x+3}-2\right).4=7-\left(\frac{9}{x+3}+\frac{1}{2}\right).2\)
\(\Leftrightarrow\frac{20}{x+3}-8=7-\frac{18}{x+3}+1\)
\(\Leftrightarrow\frac{20}{x+3}-8=8-\frac{18}{x+3}\)
\(\Leftrightarrow\frac{20}{x+3}+\frac{18}{x+3}=8+8\)
\(\Leftrightarrow\frac{38}{x+3}=16\)
\(\Leftrightarrow x+3=2,375\)
\(\Leftrightarrow x=-0,625\)
55
13 tháng 6 2019
\(\left(\frac{5}{x+3}-2\right).4=7-\left(\frac{9}{x+3}+\frac{1}{2}\right).2\)
\(\Leftrightarrow\frac{20}{x+3}-8=7-\left(\frac{18}{x+3}+1\right)\)
\(\Leftrightarrow\frac{20}{x+3}-8=7-\frac{18}{x+3}-1\)
\(\Leftrightarrow\frac{20}{x+3}+\frac{18}{x+3}=7-1+8\)
\(\Leftrightarrow\frac{38}{x+3}=14\)
\(\Leftrightarrow\left(x+3\right)14=38\)
\(\Leftrightarrow14x+42=38\)
\(\Leftrightarrow14x=-4\Leftrightarrow x=-\frac{4}{14}=-\frac{2}{7}\)
Vậy \(x=-\frac{2}{7}\)
\(\frac{43}{82}:\frac{5}{3}=\frac{43}{82}x\frac{3}{5}=\frac{129}{410}\)
\(\frac{192}{410}\)