Tìm số nguyên x, biết:
3x - 47.2 + x = -29 + -9
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
3x – 47.2 + x = - 29 + (-9)
3x – 47.2 + x = -38
3x – 94 + x = -38
3x – 94 = -38 - x
3x + x = -38 + 94
4x = 56
x = 56 : 4
x = 14
Vậy x = 14
![](https://rs.olm.vn/images/avt/0.png?1311)
a) Vì 29 là số nguyên tố nên :
(x-9).(y-18)=1.29=29.1
+)Nếu (x-9)(y-18)=1.29
\(\hept{\begin{cases}\\\end{cases}}\begin{cases}x-9=1\\y-18=29\end{cases}\)
\(\Leftrightarrow\hept{\begin{cases}\\\end{cases}}\begin{cases}x=10\\y=47\end{cases}\)
+)Nếu (x-9)(y-18)=29.1
\(\hept{\begin{cases}\\\end{cases}}\begin{cases}x-9=29\\y-18=1\end{cases}\)
\(\Rightarrow\hept{\begin{cases}\\\end{cases}}\begin{cases}x=38\\y=19\end{cases}\)
Vậy...
Câu b làm tương tự nhé bạn
![](https://rs.olm.vn/images/avt/0.png?1311)
|3x - 2| + 5 = 9 - x
|3x - 2| = 4 - x
3x - 2 = 4 - x hoặc 3x - 2 = x - 4
3x + x = 4 + 2 hoặc 3x - x = - 4 + 2
4x = 6 hoặc 2x = - 2
x = 1,5 hoặc x = - 1
mà x \(\in\) Z nên x = - 1
![](https://rs.olm.vn/images/avt/0.png?1311)
a) x = 4
b) x = -8
c) | x | - 9 = -2 + 17
| x | = 15 + 9
| x | = 24
x = 24 hoặc x = -24
d) |x – 9| = -2 + 17
|x – 9| = 15
x – 9 = 15 hoặc x – 9 = -15
x = 24 hoặc x = -6
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,0,5x-\frac{2}{3}x=\frac{7}{12}\Rightarrow\frac{1}{2}x-\frac{2}{3}x=\frac{7}{12}\)
\(\Rightarrow x\left(\frac{1}{2}-\frac{2}{3}\right)=\frac{7}{12}\Rightarrow x\cdot\left(\frac{3}{6}-\frac{4}{6}\right)=\frac{7}{12}\)
\(\Rightarrow x\cdot\left(-1\right)=\frac{7}{12}\Rightarrow x=\frac{7}{12}:\left(-1\right)=\frac{7}{-12}\)
\(c,\frac{\left(x-5\right)}{12}\cdot\frac{9}{29}=\frac{-6}{29}\Rightarrow\frac{\left(x-5\right)}{12}=\frac{-6}{29}:\frac{9}{26}\)
\(\frac{\Rightarrow\left(x-5\right)}{12}=\frac{-6}{9}=\frac{-2}{3}\Rightarrow x-5=-\frac{2}{3}\cdot12\)
\(\Rightarrow x-5=\frac{-24}{3}=-8\Rightarrow x=-8+5=-3\)
\(a,0,5x-\frac{2}{3}x=\frac{7}{12}\)
\(\Rightarrow\frac{1}{2}x-\frac{2}{3}x=\frac{7}{12}\)
\(\Rightarrow-\frac{1}{6}x=\frac{7}{12}\)
\(\Rightarrow x=-\frac{7}{2}\)
\(c,\frac{x-5}{12}\cdot\frac{9}{29}=-\frac{6}{29}\)
\(\Rightarrow\frac{x-5}{12}=-\frac{2}{3}\)
\(\Rightarrow x-5=12.\left(-\frac{2}{3}\right)\)
\(\Rightarrow x-5=-8\)
\(\Rightarrow x=-3\)
![](https://rs.olm.vn/images/avt/0.png?1311)
`\color{grey}\text{#071931}`
`(4 + 2x) * (9 - 3x) = 0`
TH1: `4 + 2x = 0 => 2x = -4 => x = -2`
TH2: `9 - 3x = 0 => 3x = 9 => x = 3`
Vậy, `x \in {-2; 3}`
____
`(3x - 19)^3 = 125`
`=> (3x - 19)^3 = 5^3`
`=> 3x - 19 = 5`
`=> 3x = 24`
`=> x = 8`
Vậy, `x = 8.`
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,3x-75=45+3.\left(-25\right)\)
\(3x-75=-30\)
\(3x=45\)
\(x=15\)
\(b,2.\left(-7\right)-11=6x+17\)
\(-14-11-17=6x\)
\(-42=6x\)
\(-7=x\Leftrightarrow x=-7\)
\(d,-4.|x-3|=-48\)
\(|x-3|=12\)
\(\Rightarrow\orbr{\begin{cases}x-3=12\\x-3=-12\end{cases}\Rightarrow\orbr{\begin{cases}x=15\\x=-9\end{cases}}}\)
=>4x-94=-38
=>4x=56
hay x=14
x = 14