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Bài 1)
\(\dfrac{9}{12}+\dfrac{10}{12}=\dfrac{12}{19}\)
\(\dfrac{50}{54}=\dfrac{27}{25}\)
\(\dfrac{16}{24}-\dfrac{9}{24}=\dfrac{7}{24}\)
\(\dfrac{8}{5}x\dfrac{4}{3}=\dfrac{32}{15}\)
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Bài 2)
a) \(x=\dfrac{5}{2}-\dfrac{2}{7}\)
\(x=\dfrac{31}{14}\)
b) \(x=\dfrac{6}{7}x\dfrac{4}{5}\)
\(x=\dfrac{24}{35}\)
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![](https://rs.olm.vn/images/avt/0.png?1311)
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chọn đáp án A
giải
ta có S hóa trị thường là II nên S2 sẽ có hóa trị là 4
\(\dfrac{2xII}{1}=IV\)
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Diện tích hình vuông ABCD là :
30 x 30 = 900 (cm2)
Diện tích hình tam giác BMN là :
30 x 40 : 2 = 60 (cm2)
Diện tích hình đó là :
900 + 60 = 960 (cm2)
Đáp số : 960 cm2
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{2}{3}\left(\dfrac{2}{10}+\dfrac{3}{10}+\dfrac{5}{10}\right)=\dfrac{2}{3}+\dfrac{10}{10}=\dfrac{2}{3}+1=\dfrac{5}{3}\)
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nửa chu vi của hình tròn là :
50 x 3,14 : 2 = 78,5 ( m )
Chu vi của sân vận động là :
2 x 78,5 + 2 x 110 = 377 ( m )
Đáp số: 377m.
Chu vi phần hcn là : ( 50 + 110 ) x2 = 320 ( m )
Chi vi phần hình tròn là : 50 x 3,14 = 157 (m )
Chu vi sân vận động là : 320 + 157 = 477 ( m )
Đ/S : ,.................
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