Tìm số nguyên x biết: -7/5 < x < 8/5
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1)<=>5|x-8|x=5x|x-8|
=>5x|x-8|=-1
=>x=\(4-\frac{9}{\sqrt{5}}\)
2)TH1:|x|-5=0
=>x=±5
TH2:x-38=0
=>x=38=6561
TH3:|x-7|=0
=>x=7
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 8 - |x + 2| = 5
-|x + 2| = 5 - 8
-|x + 2| = -3
|x + 2| = 3
x + 2 = 3; -3
x + 2 = 3 hoặc x + 2 = -3
x = 3 - 2 x = -3 - 2
x = 1 x = -5
=> x = 1 hoặc x = -5
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c) (-8).x = (-7).(-6) - 2
-8.x = 42 - 2
-8x = 40
x = 40 : (-8)
x = -5
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a,x+21=6\\ \Rightarrow x=-15\\ b,x-10=-8\\ \Rightarrow x=2\\ c,\left(-8\right)x=\left(-7\right)\left(-6\right)\\ \Rightarrow\left(-8\right)x=42\\ \Rightarrow x=-4\\ d,20+8\left(x+3\right)=5^2.4\\ \Rightarrow20+8\left(x+3\right)=25.4\\ \Rightarrow20+8\left(x+3\right)=100\\ \Rightarrow8\left(x+3\right)=80\\ \Rightarrow x+3=10\\ \Rightarrow x=7\)
\(a.x+21=6\\ x=6-21\\ x=-15\\ b.x-10=-8\\ x=-8+10\\ x=2\\ c.-8x=-7.\left(-6\right)-2\\ -8x=42-2\\ -8x=40\\ x=40:\left(-8\right)\\ x=-5\)
\(d.20+8\left(x+3\right)=5^2.4\\ 20+8x+24=25.4\\ 44+8x=100\\ 8x=100-44\\ 8x=56\\ x=56:8\\ x=7\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có:
\(\frac{x}{32}=\frac{7}{4}-\frac{5}{8}\)
\(\Leftrightarrow\frac{x}{32}=\frac{9}{8}\)
\(\Leftrightarrow x.8=32.9\)
\(\Leftrightarrow x.8=288\)
\(\Rightarrow x=288:8\)
\(\Rightarrow x=36\)
Vậy \(x=36\)
#Mạt Mạt#
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có \(7.\left(x+10\right)-8.\left(x-5\right)=118\)
\(\Rightarrow7x+70-8x+40=118\)
\(\Rightarrow-x+110=118\)
\(\Rightarrow-x=8\)
\(\Rightarrow x=-8\)
7(x+10)-8(x-5)=118
<=>7x+70-8x+40=118
<=>110-x=118
<=>-x=118-110
<=>-x=8
<=>x=-8
Vậy x=-8