24:x:26:x=5
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: -26-(x-7)=0
=>x-7=-26
=>x=-26+7=-19
b: \(24-\left(30+x\right)=-7\)
=>\(30+x=24-\left(-7\right)\)
=>\(x+30=24+7=31\)
=>x=31-30=1
c: \(3-\left(17-x\right)=-12\)
=>\(17-x=3-\left(-12\right)\)
=>\(17-x=3+12=15\)
=>x=17-15=2
d: \(\left(5-x\right)-7=-15\)
=>\(5-x=-15+7=-8\)
=>\(x=5-\left(-8\right)=5+8=13\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(96-7\left(x+1\right)=14^4:14^3\)
\(\Rightarrow96-7\left(x+1\right)=14^{4-3}\)
\(\Rightarrow96-7\left(x+1\right)=14\)
\(\Rightarrow7\left(x+1\right)=96-14\)
\(\Rightarrow7\left(x+1\right)=82\)
\(\Rightarrow x+1=\dfrac{82}{7}\)
\(\Rightarrow x=\dfrac{82}{7}-1\)
\(\Rightarrow x=\dfrac{75}{7}\)
b) \(\left(5x+3^4\right)\cdot2^4=2^6\cdot7^2\)
\(\Rightarrow5x\cdot2^4+3^4\cdot2^4=2^6\cdot7^2\)
\(\Rightarrow5x\cdot2^4+6^4=\left(2^3\cdot7\right)^2\)
\(\Rightarrow80x+1296=3136\)
\(\Rightarrow80x=1840\)
\(\Rightarrow x=\dfrac{1840}{80}\)
\(\Rightarrow x=23\)
a: =>96-7(x+1)=14
=>7(x+1)=82
=>x+1=82/7
=>x=75/7
b =>5x+81=2^2*7^2=196
=>5x=115
=>x=23
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 5 x 7 + 14
= 35 + 14
= 49
b) 48 : 6 + 13
= 8 +13
= 21
c) 6 x 8 – 26
= 48 – 26
= 22
d) 24 - 4 x 5
= 24 – 20
= 4
![](https://rs.olm.vn/images/avt/0.png?1311)
( 12 x 13 + 14 x 15 + ... + 24 x 25 + 26 x 27 ) x ( 14 + 6 - 10 + 5 - 3 x 5 )
= ( 12 x 13 + 14 x 15 + ... + 24 x 25 + 26 x 27 ) x 0
= 0
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(14^{26}.\frac{5^{24}}{2^{25}}.35^{24}\)
\(=14^{26}.35^{24}.\frac{5^{24}}{3^{25}}\)
\(=14^{26}.\frac{35^{24}.5^{24}}{3^{25}}\)
\(=14^{26}.\frac{\left(35.5\right)^{24}}{3^{25}}\)
\(=14^{26}.\frac{175^{24}}{3^{25}}\)
b) \(\left(\frac{3}{5}\right)^{2018}.x=\left(\frac{3}{5}\right)^{2016}\)
\(\Leftrightarrow x=\left(\frac{3}{5}\right)^{2016}:\left(\frac{3}{5}\right)^{2018}\)
\(\Leftrightarrow x=\left(\frac{3}{5}\right)^{-2}\)
\(\left(\frac{3}{5}\right)^{2018}.x=\left(\frac{3}{5}\right)^{2016}\)
\(\Rightarrow x=\left(\frac{3}{5}\right)^{2016}:\left(\frac{3}{5}\right)^{2018}\)
\(\Rightarrow x=\left(\frac{3}{5}\right)^{-2}\)
\(\Rightarrow x=\frac{25}{9}.\)
Vậy \(x=\frac{25}{9}.\)
Chúc bạn học tốt!
![](https://rs.olm.vn/images/avt/0.png?1311)
1) Ta có: \(\left(x+2\right)^2+\left(x-3\right)^2\)
\(=x^2+4x+4+x^2-6x+9\)
\(=2x^2-2x+13\)
2) Ta có: \(\left(4-x\right)^2-\left(x-3\right)^2\)
\(=\left(4-x-x+3\right)\left(4-x+x-3\right)\)
\(=-2x+7\)
3) Ta có: \(\left(x-5\right)\left(x+5\right)-\left(x+5\right)^2\)
\(=x^2-25-x^2-10x-25\)
=-10x-50
4) Ta có: \(\left(x-3\right)^2-\left(x-4\right)\left(x+4\right)\)
\(=x^2-6x+9-x^2+16\)
=-6x+25
5) Ta có: \(\left(y^2-6y+9\right)-\left(y-3\right)^2\)
\(=y^2-6y+9-y^2+6y-9\)
=0
6) Ta có: \(\left(2x+3\right)^2-\left(2x-3\right)\left(2x+3\right)\)
\(=4x^2+12x+9-4x^2+9\)
=12x+18