Cho mình hỏi 13:5=? và 5x6=? nha!
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cách tính : bạn tính trong từng ngoặc tròn trc nhé. rồi bạn tính như bth thôi ạ!
= ( 2/15 - 4/9 ) : ( 1/3 + 4/15 )
= -14/45 : 3/5
= -14/27
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a, 3/5 - 1/15 x 10/13
= 3/5 - 2/39
= 117/195 - 10/195
= 107/195
b, (3/5 - 3/20) x 4/5
= (12/20 - 3/20) x 4/5
= 9/20 x 4/5
= 9/25
Chúc bạn học tốt
![](https://rs.olm.vn/images/avt/0.png?1311)
=1/3-1/4+1/4-1/5+...+1/2005-1/2006
=1/3-1/2006
=2006/6018-3/6018
=2003/6018
Nếu đúng thì giữ lời hứa nhé
![](https://rs.olm.vn/images/avt/0.png?1311)
mk chỉnh lại đề nhé, có lẽ bn ghi thiếu:
\(\frac{5^2}{1.6}+\frac{5^2}{6.11}+\frac{5^2}{11.16}+\frac{5^2}{16.21}+\frac{5^2}{21.26}+\frac{5^2}{26.31}+\frac{5^2}{31.36}\)
\(=5\left(\frac{5}{1.6}+\frac{5}{6.11}+\frac{5}{11.16}+...+\frac{5}{26.31}+\frac{5}{31.36}\right)\)
\(=5\left(1-\frac{1}{6}+\frac{1}{6}-\frac{1}{11}+\frac{1}{11}-\frac{1}{16}+...+\frac{1}{26}-\frac{1}{31}+\frac{1}{31}-\frac{1}{36}\right)\)
\(=5\left(1-\frac{1}{36}\right)=5.\frac{35}{36}=\frac{175}{36}\)
Đề đúng:
\(\frac{5^2}{1.6}+\frac{5^2}{6.11}+\frac{5^2}{11.16}+\frac{5^2}{16.21}+\frac{5^2}{21.26}+\frac{5^2}{26.31}+\frac{5^2}{31.36}\)
\(=5\left(\frac{5}{1.6}+\frac{5}{6.11}+\frac{5}{11.16}+\frac{5}{16.21}+\frac{5}{21.26}+\frac{5}{26.31}+\frac{5}{31.36}\right)\)
\(=5\left(1-\frac{1}{6}+\frac{1}{6}-\frac{1}{11}+\frac{1}{11}-\frac{1}{16}+\frac{1}{16}-\frac{1}{21}+\frac{1}{21}-\frac{1}{26}+\frac{1}{26}-\frac{1}{31}+\frac{1}{31}-\frac{1}{36}\right)\)
\(=5\left(1-\frac{1}{36}\right)\)
\(=5\left(\frac{36}{36}-\frac{1}{36}\right)\)
\(=5.\frac{35}{36}\)
\(=\frac{175}{36}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1,
a, \(x\)x 124= 4829-365
\(x\)x 124 = 4464
\(x\)= 4464 :124
\(x\)= 36.
b,\(x\)x 137 = 25 x 3
\(x\)x 137 = 75
\(x\)= \(\frac{75}{137}\)
2,
\(\frac{4}{5}\)x\(\frac{3}{7}+\frac{4}{5}\)x\(\frac{6}{7}-\frac{4}{5}\)x\(\frac{4}{10}\)
=\(\frac{4}{5}\)x\(\left(\frac{3}{7}+\frac{6}{7}-\frac{4}{10}\right)\)=\(\frac{4}{5}\)x\(\frac{31}{35}\)\(\frac{124}{175}\)
\(\text{Bài }1\text{ : Tìm }x\text{ : }\)
\(a,\text{ }x\text{ x }124=4829-365\)
\(x\text{ x }124=4464\)
\(x=4464\text{ : }124\)
\(x=36\)
\(b,\text{ }x\text{ x }137=25\text{ x }3\)
\(x\text{ x }137=75\)
\(x=75\text{ : }137\)
\(x=\frac{75}{137}\)
\(\text{Bài }2\text{ : Tính bằng cách thuận tiện nhất : }\)
\(\frac{4}{5}\text{ x }\frac{3}{7}+\frac{4}{5}\text{ x }\frac{6}{7}-\frac{4}{5}\text{ x }\frac{4}{10}\)
\(=\frac{4}{5}\text{ x }\left(\frac{3}{7}+\frac{6}{7}-\frac{4}{10}\right)\)
\(=\frac{4}{5}\text{ x }\left(\frac{9}{7}-\frac{4}{10}\right)\)
\(=\frac{4}{5}\text{ x }\frac{31}{35}\)
\(=\frac{124}{175}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
B x 3 = 1x2x3 + 2x3x3 + 3x4x3 + 4x5x3 + ... + 99x100x3
= 1x2x3 + 2x3x(4-1) + 3x4x(5-2) + 4x5x(6-3) + ... + 99x100x(101-98)
= 1x2x3 + 2x3x4 - 1x2x3 + 3x4x5 - 2x3x4 + 4x5x6 - 3x4x5 + ... + 99x100x101 - 98x99x100.
= 99x100x101
B = 99x100x101 : 3
= 333300
nhanh k minh
B= 1x2+3x4+5x6+...+99x100
=> Bx3= 1x2x3 + 2x3x3 + 3x4x3 + 4x5x3 + ...+ 99x100x3
=> Bx3= 1x2x3 + 2x3x(4-1) + 3x4x(5-2) + 4x5x(6-3)+...+99x100x(101-98)
=> Bx3= 1x2x3 + 2x3x4 - 1x2x3 + 3x4x5 - 2x3x4 +4x5x6 - 3x4x5 +...+ 99x100x101 - 98x99x100
=> Bx3= 99x100x101
=> B= 99x100x101:3
=> B= 333300
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{5}{5}\)x \(\frac{6}{8}\)= \(\frac{5}{5}\)x \(\frac{3}{4}\) = \(\frac{5x3}{5x4}\) = \(\frac{15}{20}\) = \(\frac{3}{4}\)
\(\frac{5}{5}\)x \(\frac{6}{8}\) = 1 x \(\frac{6}{8}\) = \(\frac{6}{8}\) = \(\frac{3}{4}\)
\(\frac{5}{5}\)x \(\frac{6}{8}\) = 1 x \(\frac{3}{4}\) = \(\frac{3}{4}\)
Trả lời :
13 : 5 = 2 ( dư 3 )
5 x 6 = 30
~HT~
#sad
@neuthaydungchoxinmotk
13÷5=2 dư pa
5×6 ba mưi
HT