-3/2:(1/5+(1/2^3)x32/5) tính nhanh nếu có thể
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a: =16*20=320
b: =2/3+1/3*1/6:2/3
=2/3+1/18*3/2
=2/3+3/36
=2/3+1/12
=9/12=3/4
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(\frac{-5}{3}+\frac{3}{5}\right):\left|\frac{-1}{2}-0,6\right|\)
= \(\left(\frac{-25}{15}+\frac{9}{15}\right):\left|\frac{-1}{2}-\frac{6}{10}\right|.\)
= \(\frac{-16}{15}:\left|\frac{-5}{10}-\frac{6}{10}\right|.\)
= \(\frac{-16}{15}:\left|\frac{-11}{10}\right|.\)
= \(\frac{16}{15}:\frac{11}{10}.\)
= \(\frac{16}{15}\cdot\frac{10}{11}.\)
= \(\frac{32}{33}.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
(2/9.3/5+1/3.3/5).(1/3-5/8)
(6/35+1/5).(1/3-5/8
(6/35+7/35).(1/3-5/8
13/35.(1/3-5/8)
13/35.-7/24
-91/840
\(\left(\frac{2}{9}:\frac{5}{3}+\frac{1}{3}:\frac{5}{3}\right).\left(\frac{1}{3}-\frac{5}{8}\right)\)
\(=\left[\left(\frac{2}{9}+\frac{1}{3}\right).\frac{3}{5}\right].\frac{-7}{24}\)
\(=\left(\frac{5}{9}.\frac{3}{5}\right).\frac{-7}{24}\)
\(=\frac{1}{3}.\frac{-7}{24}\)
\(=\frac{-7}{72}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(a.20-\left[30-\left(5-1\right)^2\right]\) \(b.75-\left(3.5^2-4.2^3\right)\)
\(=20-\left[30-4^2\right]\) \(=75-\left(75-4.2^3\right)\)
\(=20-14=6\) \(=75-\left(75-32\right)\)
\(=75-43=32\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a.
\(\left(1\frac{1}{4}+\frac{3}{5}\right):\left(-\frac{11}{12}\right)+\left(\frac{3}{8}-1\frac{2}{5}\right):\left(-\frac{11}{12}\right)\)
\(=\left(\frac{5}{4}+\frac{3}{5}+\frac{3}{8}-\frac{7}{5}\right):\left(-\frac{11}{12}\right)\)
\(=\left(\frac{13}{8}-\frac{4}{5}\right):\left(-\frac{11}{12}\right)\)
\(=\frac{33}{40}:\left(-\frac{11}{12}\right)\)
\(=\frac{33}{40}\cdot\left(-\frac{12}{11}\right)\)
\(=\frac{-9}{10}\)
b.
\(\left(\frac{3}{8}-1\frac{2}{5}\right):\left(-\frac{11}{15}\right)+\left(1\frac{1}{4}+\frac{3}{5}\right):\left(-\frac{11}{15}\right)\)
\(=\left(\frac{3}{8}-\frac{7}{5}+\frac{5}{4}+\frac{3}{5}\right):\left(-\frac{11}{15}\right)\)
\(=\left(\frac{13}{8}-\frac{4}{5}\right):\left(-\frac{11}{15}\right)\)
\(=\frac{33}{40}:\left(-\frac{11}{15}\right)\)
\(=\frac{33}{40}\cdot\left(-\frac{15}{11}\right)\)
\(=\frac{-9}{8}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a)
\(11\dfrac{3}{13}-\left(2\dfrac{4}{7}+5\dfrac{3}{13}\right)\)
\(=\dfrac{146}{13}-\left(\dfrac{18}{7}+\dfrac{68}{13}\right)\)
\(=\dfrac{146}{13}-\dfrac{18}{7}-\dfrac{68}{13}\)
\(=\left(\dfrac{146}{13}-\dfrac{68}{13}\right)-\dfrac{18}{7}\)
\(=6-\dfrac{18}{7}\)
\(=\dfrac{24}{7}\)
b)
\(\dfrac{2}{7}\times5\dfrac{1}{4}-\dfrac{2}{7}\times3\dfrac{1}{4}\)
\(=\dfrac{2}{7}\times\dfrac{21}{4}-\dfrac{2}{7}\times\dfrac{13}{4}\)
\(=\dfrac{2}{7}\times\left(\dfrac{21}{4}-\dfrac{13}{4}\right)\)
\(=\dfrac{2}{7}\times2\)
\(=\dfrac{4}{7}\)
\(a,11\dfrac{3}{13}-\left(2\dfrac{4}{7}+5\dfrac{3}{13}\right)\)
\(=\dfrac{146}{13}-\left(\dfrac{18}{7}+\dfrac{68}{13}\right)\)
\(=\dfrac{146}{13}-\dfrac{68}{13}-\dfrac{18}{7}\)
\(=6-\dfrac{18}{7}\)
\(=\dfrac{24}{7}\)
\(b,\dfrac{2}{7}\times5\dfrac{1}{4}-\dfrac{2}{7}\times3\dfrac{1}{4}\)
\(=\dfrac{2}{7}\times\dfrac{21}{4}-\dfrac{2}{7}\times\dfrac{13}{4}\)
\(=\dfrac{2}{7}\times\left(\dfrac{21}{4}-\dfrac{13}{4}\right)\)
\(=\dfrac{2}{7}\times2\)
\(=\dfrac{4}{7}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
`a)-4/9(5/6*90%-8:0,32)`
`=-4/9(5/6*9/10-8:8/25)`
`=-4/9(3/4-25)`
`=-4/9*(-97)/4=97/9`
`b)(2/5)^2+5 1/2.(4,5-2)+(2^3)/(-4)`
`=4/25+11/2*5/2+8/(-4)`
`=4/25+55/4-2`
`=1191/100`
![](https://rs.olm.vn/images/avt/0.png?1311)
Đáp án:
Giải thích các bước giải:
1-2+3-4+5-6+... + 2009 - 2010 + 2011
=(1-2)+(3-4)+(5-6)+...+(2009-2010)+2011
=[(-1)+(-1)+(-1)+...+(-1)]+2011
=(-1005)+2011
=1006
Ta có: \(1-2+3-4+5-6+...+2009-2010+2011\)
\(=\left(1-2\right)+\left(3-4\right)+\left(5-6\right)+...+\left(2009-2010\right)+2011\)
\(=\left(-1\right)+\left(-1\right)+\left(-1\right)+...+\left(-1\right)+2011\)
\(=-1005+2011\)
\(=1006\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(2\dfrac{1}{3}.3=\dfrac{7}{3}.3=7.\\ \left(\dfrac{2}{5}-\dfrac{3}{4}\right)-\dfrac{2}{5}=\dfrac{2}{5}-\dfrac{3}{4}-\dfrac{2}{5}=-\dfrac{3}{4}.\\ \dfrac{-10}{11}.\dfrac{4}{7}+\dfrac{-10}{11}.\dfrac{3}{7}+1\dfrac{10}{11}.\\ =\dfrac{-10}{11}\left(\dfrac{4}{7}+\dfrac{3}{7}-1\right).\\ =\dfrac{-10}{11}.\left(1-1\right)=0.\)
1) 2\(\dfrac{1}{3}\).3=\(\dfrac{7}{3}\).3=7.
2) (2/5 -3/4) -2/5 = 2/5 -3/4 -2/5 = -3/4.
3) \(\dfrac{-10}{11}.\dfrac{4}{7}+\dfrac{-10}{11}.\dfrac{3}{7}+1\dfrac{10}{11}=\dfrac{1}{11}\left(-\dfrac{40}{7}-\dfrac{30}{7}+21\right)=\dfrac{1}{11}.\left(-10+21\right)=1\).