Tìm x
-15(x+2) + 7(2x-3) = 50
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![](https://rs.olm.vn/images/avt/0.png?1311)
a, -15×(x+2)+7×(2x-3)=-50
-15×x+-30+14×x-21=-50
-15×x+14×x=-50+30+21
-x=1
X=-1
a) -15.(x+2)+7.(2x-3)= (-50)
=>-15x-30+14x-21=-50
=>(-15x+14x)-30-21=-50
=>-x-51=-50
=>-x=1
=>x=-1
b)2(x+1)2=-7+15
=>2(x+1)2=8
=>(x+1)2=4
=>x+1=2 hoặc -2
=>x=1 hoặc -3
![](https://rs.olm.vn/images/avt/0.png?1311)
e: =>2/7-x=2/5
=>7-x=5
=>x=2
f: =>2x+3/3=10/3
=>2x+3=10
=>2x=7
=>x=7/2
g: =>(14+x)/7=15/7
=>x+14=15
=>x=1
h: =>(2x+3)/x=13/x
=>2x+3=13
=>2x=10
=>x=5
![](https://rs.olm.vn/images/avt/0.png?1311)
\(1,3x-7=19\\ \Rightarrow3x=26\\ \Rightarrow x=\dfrac{26}{3}\\ 2,\left(2x+1\right)\left(x-3\right)=0\\ \Rightarrow\left[{}\begin{matrix}2x+1=0\\x-3=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=3\end{matrix}\right.\\ 3,3x+\dfrac{2}{4}+1=5x-\dfrac{1}{3}\\ \Rightarrow5x-\dfrac{1}{3}-3x-\dfrac{2}{4}-1=0\\ \Rightarrow2x-\dfrac{11}{6}=0\\ \Rightarrow2x=\dfrac{11}{6}\\ \Rightarrow x=\dfrac{11}{12}\)
\(4,\dfrac{x}{15}+\dfrac{1}{2}-\dfrac{x}{50}=\dfrac{5}{6}\\ \Rightarrow\dfrac{x}{15}-\dfrac{x}{50}=\dfrac{5}{6}-\dfrac{1}{2}\\ \Rightarrow x\left(\dfrac{1}{15}-\dfrac{1}{50}\right)=\dfrac{1}{3}\\ \Rightarrow\dfrac{7}{150}x=\dfrac{1}{3}\\ \Rightarrow x=\dfrac{50}{7}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a, \(-15\left(x+2\right)+7\left(2x-3\right)=-50\\ -15x-30+14x-21=-50\\ -x-51=-50\\ -x=-50+51\\ -x=1\\ \Rightarrow x=-1\)Vậy \(x=-1\)
b, \(3\left(x+2\right)-6\left(x-5\right)=2\left(5-2x\right)\\ 3x+6-6x+30=10-4x\\ -3x+36=10-4x\\ -3x+4x=10-36\\ x=-26\)Vậy \(x=-26\)
a, −15(x+2)+7(2x−3)=−50−15x−30+14x−21=−50−x−51=−50−x=−50+51−x=1⇒x=−1Vậy x=−1
b, 3(x+2)−6(x−5)=2(5−2x)3x+6−6x+30=10−4x−3x+36=10−4x−3x+4x=10−36x=−26Vậy
![](https://rs.olm.vn/images/avt/0.png?1311)
a,2x - 35 = 15
2x=50
x=25
Vậy x=25
b, -15(x+2) + 7(2x-3)= -50
-15x - 30 + 14x - 21 = -50
-x - 51 = -50
-x=1
x= -1
Vậy......
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\dfrac{3}{4\left(x-5\right)}-\dfrac{15}{2\left(x-5\right)\left(x+5\right)}=\dfrac{-7}{6\left(x+5\right)}\)
\(\Leftrightarrow9\left(x+5\right)-90=-14\left(x-5\right)\)
=>9x+45-90=-14x+70
=>23x=70-45+90=115
hay x=5(loại)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 125 : x + ( 32 + 15 ) = 72
125 : x + 47 = 72
125 : x = 72 - 47
125 : x = 25
x = 125 : 25
x = 5
b) ( 35 + 135 ) - 2 . x = 86
170 - 2 . x = 86
2 . x = 170 - 86
2 . x = 84
x = 84 : 2
x = 42
c) 7 . x - 5 = 65
7 . x = 65 + 5
7 . x = 70
x = 70 : 7
x = 10
A) 125 / x + (32 + 15) = 72
125 / x + 47 = 72
125 / x = 72 - 47
125 / x = 25
x = 125 / 25
x = 5
-15x - 30 + 14x - 21 -50 = 0
-15x + 14x = 50 + 21 + 30
-x = 101
x = -101
Không chắc lắm đâu =))