3/5 - 1/4 : x =25/100
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{3}{5}-\frac{1}{4}:x=\frac{25}{100}\)
\(\frac{1}{4}:x=\frac{3}{5}-\frac{25}{100}\)
\(\frac{1}{4}:x=\frac{7}{20}\)
\(x=\frac{1}{4}:\frac{7}{20}\)
\(x=\frac{5}{7}\)
Vậy : \(x=\frac{5}{7}\)
k mik nha bn
3/5-1/4:x=25/100
1/4:x=3/5-25/100
1/4:x=7/20
x=1/4:7/20
x=5/7
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{3}{5}-\frac{1}{4}\div x=\frac{25}{100}\)
\(\frac{3}{5}-\frac{1}{4}\div x=\frac{1}{4}\)
\(\frac{1}{4}\div x=\frac{3}{5}-\frac{1}{4}\)
\(\frac{1}{4}\div x=\frac{7}{20}\)
\(x=\frac{1}{4}\div\frac{7}{20}\)
\(x=\frac{5}{7}\)
Ta có: 3/5 - 1/4 : x = 25/100
=> 1/4 : x = 3/5 - 25/100
=> 1/4 : x = 7/20
=> x = 1/4 : 7/20
=> x = 5/7
Vậy x = 5/7
![](https://rs.olm.vn/images/avt/0.png?1311)
3/5-1/4:x=25/100
1/4:x=25/100+3/5
1/4:x=17/20
x=17/20x1/4
x=17/80
Vậy x=17/80
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{3}{5}-\frac{1}{4}:x=\frac{25}{100}\)
\(\frac{3}{5}-\frac{1}{4}:x=\frac{1}{4}\)
\(\frac{1}{4}:x=\frac{3}{5}-\frac{1}{4}\)
\(\frac{1}{4}:x=\frac{7}{20}\)
\(x=\frac{1}{4}:\frac{7}{20}\)
\(x=\frac{5}{7}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
bg:
3/5-1/4:x =25/100
1/4:x =3/5-25/100
1/4:x =7/20
x = 1/4:7/20
x =5/7
![](https://rs.olm.vn/images/avt/0.png?1311)
\(=\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{13}{4}+\dfrac{3}{4}-\dfrac{1}{20}=4+\left(\dfrac{1}{4}-\dfrac{1}{5}-\dfrac{1}{20}\right)=4+0=4\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{3}{5}-\frac{1}{4}:x=\frac{25}{100}\)
\(\frac{3}{5}-\frac{1}{4}:x=\frac{1}{4}\)
\(\frac{1}{4}:x=\frac{3}{5}-\frac{1}{4}\)
\(\frac{1}{4}:x=\frac{7}{20}\)
\(x=\frac{1}{4}:\frac{7}{20}\)
\(x=\frac{1}{4}.\frac{20}{7}\)
\(x=\frac{5}{7}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
b: \(\Leftrightarrow\left(\dfrac{29-x}{21}+1\right)+\left(\dfrac{27-x}{23}+1\right)+\left(\dfrac{25-x}{25}+1\right)+\left(\dfrac{23-x}{27}+1\right)+\left(\dfrac{21-x}{29}+1\right)=0\)
=>50-x=0
hay x=50
c: \(\Leftrightarrow\dfrac{x-2}{2001}+1=\dfrac{x-1}{2002}+\dfrac{x}{2003}\)
\(\Leftrightarrow\left(\dfrac{x-2}{2001}-1\right)=\left(\dfrac{x-1}{2002}-1\right)+\left(\dfrac{x}{2003}-1\right)\)
=>x-2003=0
hay x=2003
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{3}{5}-\frac{1}{4}:x=\frac{25}{100}\)
\(\frac{1}{4}:x=\frac{3}{5}-\frac{25}{100}\)
\(\frac{1}{4}:x=\frac{7}{20}\)
\(x=\frac{5}{7}\)
Vậy \(x=\frac{5}{7}\)
3/5-1/4:x=25/100
1/4:x=3/5-25/100
1/4:x=7/20
x=1/4:7/20
x=5/7
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