\(\frac{5}{23}....\frac{45}{89}\)
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: \(=\dfrac{17}{7}+\dfrac{2}{9}-\dfrac{10}{7}-\dfrac{5}{3}\cdot9=1+\dfrac{2}{9}-15=-14+\dfrac{2}{9}=-\dfrac{126}{9}+\dfrac{2}{9}=-\dfrac{124}{9}\)
b: \(=\dfrac{-11}{23}\left(\dfrac{6}{7}+\dfrac{8}{7}\right)-\dfrac{1}{23}=\dfrac{-22}{23}-\dfrac{1}{23}=-1\)
c: \(=\left(\dfrac{377}{-231}-\dfrac{123}{89}+\dfrac{34}{791}\right)\cdot\dfrac{4-3-1}{24}=0\)
d: \(=\dfrac{12}{7}\left(19+\dfrac{5}{8}-15-\dfrac{1}{4}\right)=\dfrac{12}{7}\cdot\dfrac{35}{8}=\dfrac{15}{2}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(\frac{5}{12}-\frac{5}{7}-\frac{22}{45}+\frac{7}{12}-\frac{23}{45}\right).\left|x\right|-9=-2\)
\(\left(\frac{12}{12}-\frac{5}{7}-\frac{45}{45}\right).\left|x\right|=-2+9\)
\(\left(1-\frac{5}{7}-1\right).\left|x\right|=7\)
\(\frac{-5}{7}.\left|x\right|=7\)
\(\left|x\right|=7:\left(\frac{-5}{7}\right)\)
\(\left|x\right|=\frac{-49}{5}\)
\(\Rightarrow x\in\varnothing\) vì trị tuyệt đối của 1 số luôn dương
![](https://rs.olm.vn/images/avt/0.png?1311)
Trước hết tính tổng :
\(\frac{11}{12}+\frac{11}{12\times13}+...+\frac{11}{89\times100}=1-\frac{1}{12}+\frac{1}{12}-\frac{1}{13}+...+\frac{1}{89}-\frac{1}{100}\)
\(=1-\frac{1}{100}=\frac{99}{100}\)
Do đó \(\frac{99}{100}+x=\frac{5}{3}\)
Vậy \(x-\frac{5}{3}-\frac{99}{100}=\frac{500-297}{300}=\frac{203}{300}\)
Vậy...
bang 112222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222222233333333333333333333333356152784327152718452314983254623145652186521865216416524
dung ko??
![](https://rs.olm.vn/images/avt/0.png?1311)
1)
\(2.\frac{3}{7}+\left(\frac{2}{9}-1\frac{3}{7}\right)-\frac{5}{3}:\frac{1}{9}\)
\(=\frac{6}{7}+\frac{2}{9}-\frac{10}{7}-\frac{5}{3}.9\)
\(=\left(\frac{6}{7}-\frac{10}{7}\right)+\frac{2}{9}-15\)
\(=\frac{-4}{7}+\frac{2}{9}-\frac{15}{1}\)
\(=\frac{-36}{63}+\frac{14}{63}-\frac{945}{63}\)
\(=\frac{-967}{63}\)
2)
\(-\frac{11}{23}.\frac{6}{7}+\frac{8}{7}.\frac{-11}{23}-\frac{1}{23}\)
\(=\frac{-11}{23}\left(\frac{6}{7}+\frac{8}{7}\right)-\frac{1}{23}\)
\(=\frac{-11}{23}.2-\frac{1}{23}\)
\(=\frac{-22}{23}-\frac{1}{23}\)
\(=\frac{-23}{23}\)
\(=-1\)
3)
\(\left(\frac{377}{-231}-\frac{123}{89}+\frac{34}{791}\right).\left(\frac{1}{6}-\frac{1}{8}-\frac{1}{24}\right)\)
\(=\left(\frac{377}{-231}-\frac{123}{89}+\frac{34}{791}\right).\left(\frac{4}{24}-\frac{3}{24}-\frac{1}{24}\right)\)
\(=\left(\frac{377}{-231}-\frac{123}{89}+\frac{34}{791}\right).\frac{0}{24}\)
\(=\left(\frac{377}{-231}-\frac{123}{89}+\frac{34}{791}\right).0\)
\(=0\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a) \(\frac{-3}{7}+\frac{15}{26}-\left(\frac{2}{13}-\frac{3}{7}\right)=\frac{-3}{7}+\frac{15}{26}-\frac{2}{13}+\frac{3}{7}=\left(\frac{-3}{7}+\frac{3}{7}\right)+\left(\frac{15}{26}-\frac{2}{13}\right)\)
\(=\frac{15-4}{26}=\frac{11}{26}\)
c) \(\frac{-11}{23}.\frac{6}{7}+\frac{8}{7}.\frac{-11}{23}-\frac{1}{23}=\frac{-11}{23}.\left(\frac{6}{7}+\frac{8}{7}\right)-\frac{1}{23}\)
\(=\frac{-11}{23}.2-\frac{1}{23}=\frac{-22-1}{23}=\frac{-23}{23}=-1\)
![](https://rs.olm.vn/images/avt/0.png?1311)
1.(11/12+11/23+11/23+11/24+...+11/89+11/100)+x=5/3
1.(11/12+11/100)+x=5/3
77/75+x=5/3
x=5/3-77/75
x=16/25
de ot
=> ( 11/12+ 1/12- 1/23+ 1/23- 1/34+...+ 1/89-1/100 ) +x=5/3
=> (11/12+ 1/12-1/100 ) + x=5/3
=> (11/12+ 11/150) + x=5/3
=>99/100 +x = 5/3
=> x = 5/3 - 99/100
=> x= 203 / 300
K dung NHA
\(\frac{5}{23}\)<\(\frac{45}{89}\)
<