3.5 – 52.23 : (10^2.2)
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\(3^2.2^4-2^3.4^2-2^3.5^0+4^2.2^2\)
\(=9.16-8.16-8.1+16.4\)
\(=16.\left(9-8\right)-8+64\)
\(=16.1-8+64\)
\(=8+64\)
\(=72\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(5^2x-3\right)-3.5^2=5^2.2\)
<=>\(\left(25x-3\right)-3.25=25.2\)
<=>\(\left(25x-3\right)-75=50\)
<=>\(\left(25x-3\right)=125\)
<=>\(25x-3=125\)
<=>\(x-3=125:25\)
<=>\(x-3=5\)
<=>\(x=8\)
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`#3107.101107`
\(\dfrac{27^2\cdot2^3\cdot5^4}{15^2\cdot6^9}\)
\(=\dfrac{\left(3^3\right)^2\cdot2^3\cdot5^4}{3^2\cdot5^2\cdot2^9\cdot3^9}\)
\(=\dfrac{3^6\cdot2^3\cdot5^4}{3^{11}\cdot5^2\cdot2^9}\)
\(=\dfrac{5^2}{3^5\cdot2^6}\)
\(=\dfrac{25}{15552}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(R=\frac{2.2}{1.3}+\frac{3.3}{2.4}+\frac{4.4}{3.5}+...+\frac{2006.2006}{2005.2007}\)
\(R=\frac{2^2}{1.3}+\frac{3^2}{2.4}+\frac{4^2}{3.5}+...+\frac{2006^2}{2005.2007}\)
\(R=\frac{1.3+1}{1.3}+\frac{2.4+1}{2.4}+\frac{3.5+1}{3.5}+...+\frac{2005.2007+1}{2005.2007}\)
\(R=1+\frac{1}{1.3}+1+\frac{1}{2.4}+1+\frac{1}{3.5}+...+1+\frac{1}{2005.2007}\)
\(R=\left(1+1+...+1\right)+\left(\frac{1}{1.3}+\frac{1}{3.5}+...+\frac{1}{2005.2007}\right)+\left(\frac{1}{2.4}+\frac{1}{4.6}+...+\frac{1}{2004.2006}\right)\)
( có 2005 số 1)
\(R=2005+\frac{1}{2}.\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{2005}-\frac{1}{2007}\right)\)
\(+\frac{1}{2}.\left(\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+...+\frac{1}{2004}-\frac{1}{2006}\right)\)
\(R=2005+\frac{1}{2}.\left(1-\frac{1}{2007}\right)+\frac{1}{2}.\left(\frac{1}{2}-\frac{1}{2006}\right)\)
\(R=2005+\frac{1}{2}\cdot\frac{2006}{2007}+\frac{1}{2}\cdot\frac{501}{1003}\)
\(R=2005+\frac{1003}{2007}+\frac{501}{2006}\)
...
đến đây bn tự tính típ nha!
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\(6^2.2^2.5:\left[3.12-\left(2x-6\right)\right]=2^3.5\)
\(\Rightarrow36.4.5:\left[36-\left(2x-6\right)\right]=8.5\)
\(\Rightarrow720:\left[36-\left(2x-6\right)\right]=40\)
\(\Rightarrow36-\left(2x-6\right)=720:40=18\)
\(\Rightarrow2x-6=36-18=18\)
\(\Rightarrow2x=18+6=24\)
\(\Rightarrow x=24:2=12\)
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A=2(1+3+5+...+97+99)
Số số lẻ trong khoảng từ 1 đến 99 là (99-1):2+1=50(số)
=>Tổng của các số lẻ từ 1 đến 99 là (99+1)*50/2=50*50=2500
=>A=2*2500=5000
B=2(2+4+6+...+98+100)
Số số chẵn trong khoảng từ 2 đến 100 là
(100-2):2+1=50(số)
=>Tổng của các số lẻ từ 2 đến 100 là (100+2)*50/2=50*51=2550
=>B=2*2550=5100
=>A<B
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\(\frac{4^2.2^5+32.125}{2^3.5^2}\) \(=\)\(\frac{4^2.2^5+2^5.5^3}{2^3.5^2}\)
\(=\frac{\left(4^2+5^3\right).2^5}{2^3.5^2}\)
\(=\) \(\frac{\left(4^2+5^3\right).2^2}{5^2}\)
\(=\) \(\frac{564}{25}\)
\(\frac{4^2.2^5+32.125}{2^3.5^2}=\frac{4^2.2^5+2^5.5^3}{2^3.2^5}\)
\(=\frac{(4^2+5^3).2^5}{2^3.2^5}\)
\(=\frac{(4^2+5^3).2^2}{5^2}\)
\(=\frac{564}{25}\)
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\(B=136.25+75.136-6^2.10^2\)
\(=136.\left(75+25\right)-36.100\)
\(=136.100-36.100\)
\(=\left(136-36\right).100\)
\(=100.100=10000\)
\(C=2^3.5^3-\left\{7^2.2^3.5^2.\left[4^3:8+11^2:121-2\left(37-5.7\right)\right]\right\}\)
\(=10^3-\left\{49.8.25.\left[8+1+2.2\right]\right\}\)
\(=1000-\left(49.200.13\right)\)
\(=1000-127400\)
\(=-126400\)
Bài này đơn giản thôi bạn
B= 136.(25+75)-36.100
B= 136. 100-36.100
B= 100.(136-36)
B= 100.100
B= 10000
3.5 - 52.23 : (102 . 2)
15 - 1196 : ( 100 . 2 )
15 - 1196 : 200
15 - 5,98
= 9,02
( -)) giải ra thấy z còn đúng sai thì chịu UwU)
\(=15-1196:200=15-\dfrac{299}{50}=\dfrac{451}{50}\)