A = 50 + { 30 - 2 [ 14 - 48 : 4^2]}
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![](https://rs.olm.vn/images/avt/0.png?1311)
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\(A=50+\left\{30-2\left[14-48:\left(5-1\right)^2\right]\right\}\)
\(=50+\left\{30-2\left[ơ14-48:4^2\right]\right\}\)
\(=50+\left\{30-2\left[14-48:16\right]\right\}\)
\(=50+\left\{30-2\left[14-3\right]\right\}\)
=\(50+\left\{30-2\left[14-11\right]\right\}\)
\(=50+\left\{30-2.11\right\}\)
\(=50+\left\{30-22\right\}\)
\(=50+8\)
\(=58\)
=50+{30-2[14-48:16]}
=50+{30-2[14-3]}
=50+{30-2.11}
=50+{30-22}
=50+8
=58
![](https://rs.olm.vn/images/avt/0.png?1311)
Bạn ơi cái bài tìm x kiểu gì vậy
Cái ý b đề bài sai rồi
![](https://rs.olm.vn/images/avt/0.png?1311)
\(=45-\left(3^2+2^4\right)=45-\left(9+16\right)=45-25=20\)
b)\(=50+\left(30-2\left(14-3\right)\right)=50+\left(30-22\right)=50+8=58\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Tính nhanh
a) 100 :4 – 50 : 2 + 100
= 25 – 25 + 100
= 0 + 100
= 100
b) (6 × 8 – 48) : (10 + 11 + 12 + 13 + 14)
= (48 – 48) : (10 + 11 + 12 + 13 + 14)
= 0 : (10 + 11 + 12 + 13 + 14)
= 0
c) 10000 × 2 + 60000
= 10000 × 2 + 10000 × 6
= 10000 × (2 + 6)
= 10000 × 8
= 80000
d) (7000 – 3000) × 2 = 4000 × 2 = 8000
![](https://rs.olm.vn/images/avt/0.png?1311)
\(x+14⋮7\)
Ta có: \(14⋮7\) => \(x⋮7\) => \(x=7n\) (x < 1200)
\(x-16⋮8\)
Ta có: \(16⋮8\) => \(x⋮8\) => \(x=8n\) (x < 1200)
\(54-x⋮9\)
Ta có \(54⋮9\) => \(x⋮9\) => \(x=9n\) (x < 1200)
![](https://rs.olm.vn/images/avt/0.png?1311)
( 2x + 1 / 2 ) * ( 3 / 4 - x ) = 0
=> 2x + 1 / 2 = 0 hoặc 3 / 4 - x = 0
2x = - 1 / 2 x = 3 / 4
x = - 1 / 4
Vậy x = -1 / 4 hoặc x = 3 / 4
2 / 10 * 12 + 2 / 12 * 14 + 2 / 14 * 16 + ... + 2 / 48 * 50
= 1 / 10 - 1 / 12 + 1 / 12 - 1 / 14 + 1 / 14 + 1 / 16 + .... + 1 / 48 - 1/ 50
= 1 / 10 - 1 / 50
= 2 / 25
Tìm x : \(\left(2x+\frac{1}{2}\right)\left(\frac{3}{4}-x\right)=0\)
\(\Rightarrow\orbr{\begin{cases}2x+\frac{1}{2}=0\\\frac{3}{4}-x=0\end{cases}\Rightarrow\orbr{\begin{cases}x=\frac{-1}{2}\\x=\frac{3}{4}\end{cases}}}\)
Tính nhanh : \(\frac{2}{10.12}+\frac{2}{12.14}+...+\frac{2}{48.50}\)
\(=2\left(\frac{1}{10.12}+\frac{1}{12.14}+...+\frac{1}{48.50}\right)\)
\(=2.\frac{1}{2}\left(\frac{1}{10}-\frac{1}{12}+\frac{1}{12}-\frac{1}{14}+...+\frac{1}{48}-\frac{1}{50}\right)\)
\(=\frac{1}{10}-\frac{1}{50}\)
\(=\frac{2}{25}\)