(3x-2⁴)÷7³=2×7⁴
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( 3x - 24). 73 = 2.74
3x - 24 = 2.74 : 73
3x - 16 = 2.7
3x - 16 = 14
3x = 14 + 16
3x = 30
x = 30 : 3
x = 10
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(3x-2^4\right).7^3=2.7^4\)
\(\Leftrightarrow3x-2^4=2.7^4\div7^3\)
\(\Leftrightarrow3x-2^4=2.7\)
\(\Leftrightarrow3x-16=14\)
\(\Leftrightarrow3x=14+16\)
\(\Leftrightarrow3x=30\)
\(\Leftrightarrow x=10\)
\(\left(3x-2^4\right).7^3=2.7^4\)
\(3x-2^4=2.7^4:7^3\)
\(3x-16=14\)
\(3x=30\)
\(x=10\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\Leftrightarrow3x-16=2.7^4+7^3=5145\Leftrightarrow3x=5161\Leftrightarrow x=\dfrac{5161}{3}\)
\(\left(3x-2^4\right)-7^3=2.7^4\\ \Leftrightarrow\left(3x-16\right)=2.7^4+7^3\\ \Leftrightarrow3x-16=5145\\ \Leftrightarrow3x=5145+16=5161\\ \Leftrightarrow x=\dfrac{5161}{3}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
219 - 7(x + 1) = 10²
7(x + 1) = 219 - 10²
7(x + 1) = 219 - 100
7(x + 1) = 119
x + 1 = 119 : 7
x + 1 = 17
x = 17 - 1
x = 16
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(3x - 2⁴) . 7³ = 2.7⁴
(3x - 16).7³ = 2.7⁴
3x - 16 = 2.7⁴:7³
3x - 16 = 2.7
3x - 16 = 14
3x = 14 + 16
3x = 30
x = 30 : 3
x = 10
![](https://rs.olm.vn/images/avt/0.png?1311)
Lời giải:
$10+2x=4^5:4^3=4^2=16$
$2x=16-10=6$
$x=6:2=3$
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$2x-6^2:18=3.2^2$
$2x-2=12$
$2x=14$
$x=14:2=7$
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$70-5(x-3)=3.2^5=96$
$5(x-3)=70-3.2^5=-26$
$x-3=\frac{-26}{5}$
$x=3+\frac{-26}{5}=\frac{-11}{5}$
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$19-7(x+1)=10^2=100$
$7(x+1)=19-100=-81$
$x+1=\frac{-81}{7}$
$x=\frac{-81}{7}-1=\frac{-88}{7}$
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$(3x-2^4).7^3=2.7^4$
$3x-16=2.7^4:7^3=2.7=14$
$3x=14+16=30$
$x=30:3=10$
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(3x-2^4\right).7^3=2.7^4\\ \Leftrightarrow3x-16=2.7^4:7^3\\ \Leftrightarrow3x=14+16\\ \Leftrightarrow3x=30\\ \Leftrightarrow x=10\)
Vậy...
\(\left(2x-2^4\right).7^3=2.7^4\)
\(\Leftrightarrow\left(2x-2^4\right)=2.7^4:7^3\)
\(\Leftrightarrow2x-2^4=2.7\)
\(\Leftrightarrow2x-16=14\)
\(\Leftrightarrow2x=30\)
\(\Leftrightarrow x=15\)
Vậy ..
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(3x-2^4\right).7^3=2.7^4\)
\(\left(3x-2^4\right)=2.7^4\div7^3\)
\(3x-2^4=2.7\)
\(3x-2^4=14\)
\(3x=14+2^4\)
\(3x=30\)
`=>` \(x=30\div3\)
`=> x=10`
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\left(3x-2^4\right).7^3=2.7^4\)
=> \(\left(3x-2^4\right)=2.7^4:7^3\)
=> \(\left(3x-2^4\right)=2.7^1\)
=> \(\left(3x-2^4\right)=14\)
=> \(3x=14+2^4\)
=> 3x = 14 + 16
3x = 30
x=30 : 3
x = 10
Vậy x = 10
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