tính hợp lý \(\frac{9764}{36615}+\frac{36\cdot85\cdot20}{25\cdot84\cdot34}+2\cdot2+3\frac{19}{133}\)
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Ta có: \(\frac{2}{1.2}+\frac{2}{2.3}+\frac{2}{3.4}+.........+\frac{2}{18.19}+\frac{2}{19.20}\)
= \(\frac{2}{1}-\frac{2}{2}+\frac{2}{2}-\frac{2}{3}+\frac{2}{3}-\frac{2}{4}+.......+\frac{2}{18}-\frac{2}{19}+\frac{2}{19}-\frac{2}{20}\)
=\(\frac{2}{1}-\frac{2}{20}=\frac{40}{20}-\frac{2}{20}=\frac{38}{20}=\frac{19}{10}\).
\(A=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{19.20}\)
\(\Rightarrow A=\frac{1}{1}.\frac{1}{2}+\frac{1}{2}.\frac{1}{3}+...+\frac{1}{19}.\frac{1}{20}\)
\(\Rightarrow A=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{19}-\frac{1}{20}\)
\(\Rightarrow A=\frac{1}{1}-\frac{1}{20}=\frac{19}{20}\)
A=1/1x2 +1/2x3 +... +1/18x19 + 1/19x20
Nhận xét 1/1x2 = 1/1 -1/2 ; 1/2x3=1/2-1/3; ... ;1/18x19=1/18-1/19 ; 1/19x20=1/19-1/20
ta có A=1/1 - 1/2 + +1/2 -1/3+1/3- +1/18-1/19+1/19-1/20
A=1/1 - 1/20
A=20/20 - 1/20
A=(20-1)/20
A=19/20
Vậy A=19/20
A =\(\frac{1}{1.2}\)+\(\frac{1}{2.3}\)+\(\frac{1}{3.4}\)+ ...+\(\frac{1}{18.19}\)+\(\frac{1}{19.20}\)
A = 1 - \(\frac{1}{2}\)+\(\frac{1}{2}\)- \(\frac{1}{3}\)+\(\frac{1}{3}\)- \(\frac{1}{4}\)+....+\(\frac{1}{18}\)- \(\frac{1}{19}\)+ \(\frac{1}{19}\)- \(\frac{1}{20}\)
A = 1 - \(\frac{1}{20}\)( Vì đã triệt tiêu )
A = \(\frac{19}{20}\)
Ta có: \(\frac{-3}{1.2.3}+\frac{-3}{2.3.4}+\frac{-3}{3.4.5}+...+\frac{-3}{18.19.20}\)
\(=\frac{-3}{2}\left(\frac{2}{1.2.3}+\frac{2}{2.3.4}+\frac{2}{3.4.5}+...+\frac{2}{18.19.20}\right)\)
\(=\frac{-3}{2}\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{18.19}-\frac{1}{19.20}\right)\)
\(=\frac{-3}{2}\left(\frac{1}{2}-\frac{1}{19.20}\right)=\frac{-3}{2}.\frac{189}{380}=\frac{-567}{760}\)
Lời giải:
Gọi giá trị trên là $A$
$A=\frac{4}{15}+\frac{6}{7}+4+3+\frac{1}{7}$
$=\frac{4}{15}+(4+3)+(\frac{6}{7}+\frac{1}{7})$
$=\frac{4}{15}+7+1=8\frac{4}{15}$