a )210 - 5 ( x-10)=200
b) [3.(70- x)+5]:2=46
c) 230 +[2^4+(x-5)]=315.2018^0
d)707 : [(2^x -5)+74] = 4^2-3^2
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T
25 tháng 6 2021
d , ( x : 7 + 15 ) . 23 + 391 => Đề thiếu
e , ( 19 . x + 2 . 52 ) : 14 = ( 13 - 8 ) 2 - 42
=> ( 19 . x + 2 . 52 ) : 14 = 52 - 16
=> ( 19 . x + 2 . 52 ) : 14 = 25 - 16 = 9
=> 19 . x + 2 . 52 = 9 x 14 = 126
=> 19 . x + 2 . 25 = 126
=> 19 . x + 50 = 126
=> 19 . x = 126 - 50 = 76
=> x = 76 : 19 = 4
NN
29 tháng 11 2017
a) \(\left(-396\right)+2016+189+\left(-604\right)-109\)
\(=-396+2016+189-604-109\)
\(=-\left(396-2016\right)+189-604-109\)
\(=-\left(-1620\right)+189-604-109\)
\(=1620+189-604-109\)
\(=1809-604-109\)
\(=1205-109\)
\(=1096\)
b) \(10-\left|x+3\right|=-8-10\)
\(\Leftrightarrow10-\left|x+3\right|=-\left(8+10\right)\)
\(\Leftrightarrow10-\left|x+3\right|=-18\)
\(\Leftrightarrow\left|x+3\right|=10-\left(-18\right)\)
\(\Leftrightarrow\left|x+3\right|=10+18\)
\(\Leftrightarrow\left|x+3\right|=28\)
Xét trường hợp 1: \(x+3=28\)
\(\Rightarrow x=28-3\)
\(\Rightarrow x=25\)
Xét trường hợp 2: \(x+3=-28\)
\(\Rightarrow x=-28-3\)
\(\Rightarrow x=-\left(28+3\right)\)
\(\Rightarrow x=-31\)
Vậy \(x=25\) hoặc \(x=-31\)
12 tháng 8 2018
3x : 3 = 9
3x = 9 . 3
3x = 27
3x = 33
=> x = 3
c. 42x - 1 : 22 = 16
42x - 1 = 16 . 22
42x - 1 = 64
42x - 1 = 43
=> 2x - 1 = 3
=> 2x = 3 + 1
=> 2x = 4
=> x = 2
17 tháng 12 2022
a: \(\Leftrightarrow4^{x-5}\cdot17=68\)
=>4^x-5=4
=>x-5=1
=>x=6
b: \(\Leftrightarrow\dfrac{1}{3}:\left|2x-1\right|=\dfrac{1}{3}+\dfrac{2}{3}=1\)
=>|2x-1|=1/3
=>2x-1=1/3 hoặc 2x-1=-1/3
=>x=2/3 hoặc x=1/3
c: =>|2x-2|=|3x+15|
=>3x+15=2x-2 hoặc 3x+15=-2x+2
=>x=-17 hoặc x=-13/5
14 tháng 10 2020
a
\(230+\left[16+\left(y-5\right)\right]=315\cdot1\)
\(230+\left[16+\left(y-5\right)\right]=315\)
\(16+\left(y-5\right)=315-230\)
\(16+\left(y-5\right)=85\)
\(y-5=85-16\)
\(y-5=69\)
\(y=69+5\)
\(y=74\)
b
\(707:\left[\left(2^y-5\right)+74\right]=16-9\)
\(707:\left[\left(2^y-5\right)+74\right]=7\)
\(\left(2^y-5\right)+74=707:7\)
\(\left(2^y-5\right)+74=101\)
\(2^y-5=101-74\)
\(2^y-5=27\)
\(2^y=27+5\)
\(2^y=32\)
\(2^y=2^5\)
\(\Rightarrow y=5\)
12 tháng 3 2020
a) 210 -5.x= 200
<=> 5.x = 210 - 200
<=> 5.x = 10
<=> x = 10 : 5
<=> x = 2
Vậy x = 2
b) 210 - 5 . ( x-10 ) = 200
<=> 5. (x-10) = 210 - 200
<=> 5.(x-10) = 10
<=> x -10 = 10 : 5
<=> x - 10 = 2
<=>x = 12
Vậy x = 12
d)350 : x + 10 = 20
<=> 350 : x = 20 - 10
<=> 350 : x = 10
<=> x = 350 : 10
<=> x = 35
Vậy x = 35
e)36 : ( x - 5 ) = 22
<=> 36 : ( x-5) = 4
<=> x - 5 = 36 : 4
<=> x - 5 = 9
<=> x = 9 + 5
<=> x = 14
Vậy x =14
e) [3 . (70-x) + 5 ] : 2 = 46
<=> [3 . (70-x) + 5 ] = 46 . 2
<=> [3 . (70-x) + 5 ] = 92
<=> 210 - 3.x + 5 = 92
<=>210- 3.x = 92 - 5
<=> 210 - 3.x = 87
<=> 3.x = 210 - 87
<=> 3.x = 123
<=> x = 123 : 3
<=> x = 41
Vậy x = 41
5 tháng 3 2022
\(a,6x-4=5x\\ \Leftrightarrow x-4=0\\ \Leftrightarrow x=4\\ b,\dfrac{2x+3}{3}=\dfrac{5-4x}{2}\\ \Leftrightarrow2\left(2x+3\right)=3\left(5-4x\right)\\ \Leftrightarrow4x+6=15-12x\\ \Leftrightarrow16x-9=0\\ \Leftrightarrow x=\dfrac{9}{16}\\ c,\left(x+7\right)\left(x-10\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x+7=0\\x-10=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=-7\\x=10\end{matrix}\right.\)
d, ĐKXĐ:\(x\ne\pm3\)
\(\dfrac{2}{x-3}+\dfrac{3}{x+3}=\dfrac{3x+5}{x^2-9}\\ \Leftrightarrow\dfrac{2\left(x+3\right)}{\left(x+3\right)\left(x-3\right)}+\dfrac{3\left(x-3\right)}{\left(x+3\right)\left(x-3\right)}-\dfrac{3x+5}{\left(x+3\right)\left(x-3\right)}=0\\ \Leftrightarrow\dfrac{2x+6+3x-9-3x-5}{\left(x+3\right)\left(x-3\right)}=0\\ \Rightarrow2x-8=0\\ \Leftrightarrow x=4\left(tm\right)\)
5 tháng 3 2022
a.6x-4=5x <=> x=4
b.\(\dfrac{2x+3}{3}=\dfrac{5-4x}{2}\)
\(\Leftrightarrow\dfrac{2\left(2x+3\right)}{6}=\dfrac{3\left(5-4x\right)}{6}\)
\(\Leftrightarrow2\left(2x+3\right)=3\left(5-4x\right)\)
\(\Leftrightarrow4x+6=15-12x\)
\(\Leftrightarrow16x=11\)
\(\Leftrightarrow x=\dfrac{11}{16}\)
c.(x+7)(x-10)=0
\(\Leftrightarrow\left[{}\begin{matrix}x+7=0\\x-10=0\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=-7\\x=10\end{matrix}\right.\)
d.\(ĐK:x\ne\pm3\)
\(\Rightarrow\dfrac{2}{x-3}+\dfrac{3}{x+3}=\dfrac{3x+5}{\left(x-3\right)\left(x+3\right)}\)
\(\Leftrightarrow\dfrac{2\left(x+3\right)+3\left(x-3\right)}{\left(x-3\right)\left(x+3\right)}=\dfrac{3x+5}{\left(x-3\right)\left(x+3\right)}\)
\(\Leftrightarrow2\left(x+3\right)+3\left(x-3\right)=3x+5\)
\(\Leftrightarrow2x+6+3x-9-3x-5=0\)
\(\Leftrightarrow2x-8=0\)
\(\Leftrightarrow2x=8\)
\(\Leftrightarrow x=4\left(tm\right)\)
a) \(\Rightarrow5\left(x-10\right)=10\)
\(\Rightarrow x-10=2\Rightarrow x=12\)
b) \(\Rightarrow3\left(70-x\right)+5=92\)
\(\Rightarrow3\left(70-x\right)=87\)
\(\Rightarrow70-x=29\Rightarrow x=41\)
c) \(\Rightarrow230+\left[16+\left(x-5\right)\right]=315\)
\(\Rightarrow11+x=85\Rightarrow x=74\)
d) \(\Rightarrow707:\left(2^x-5+74\right)=7\)
\(\Rightarrow2^x-5+74=101\Rightarrow2^x-5=27\)
\(\Rightarrow2^x=32\Rightarrow x=5\)