3x-1+5.3x-1=162
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3^x- 1 +5*3^x-1=162
=>3x-1.(1+5)=162
=> x-1=3
=> x=3+1
=> x=4
Vậy x=4
![](https://rs.olm.vn/images/avt/0.png?1311)
\(3^{x-1}+5.3^{x-1}=162\)
\(3^{x-1}.1+5.3^{x-1}=162\)
\(3^{x-1}.\left(1+5\right)=162\)
\(3^{x-1}.6=162\)
\(3^{x-1}=162:6\)
\(3^{x-1}=27\)
\(3^{x-1}=3^3\)
\(\Rightarrow x-1=3\)
\(x=3+1\)
\(x=4\)
Vậy \(x=4\)
Ý bạn là \(\left(3^x-1+5\right)\left(3^x-1\right)\)
Hay \(\left(3^{x-1}+5\right)\left(3^{x-1}\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Lời giải:
$3^{-1}.3^x+5.3^{x-1}=162$
$3^{x-1}+5.3^{x-1}=162$
$3^{x-1}(1+5)=162$
$3^{x-1}.6=162$
$3^{x-1}=27=3^3$
$\Rightarrow x-1=3$
$\Rightarrow x=4$
![](https://rs.olm.vn/images/avt/0.png?1311)
3x-1+5.3x-1=162
<=>3x-1.(1+5)=162
=>3x-1.6=162
=>3x-1=162:6
=>3x-1=27
=>3x-1=33
=>x-1=3
=>x=3+1
=>x=4
Chúc bạn học giỏi nha!!!
K cho mik với nhé Nguyễn Trần Thanh Vy
3X-1 + 5 * 3X-1 = 162
3X-1 * (5+1) = 162
3X-1 * 6 = 162
3X-1 = 27
=> 3X-1 = 33
=>X-1=3
=>X=4
![](https://rs.olm.vn/images/avt/0.png?1311)
a)5x+5x+2=650
2*5x+2=650
2(5x+1)=650
5x+1=650/2
5x+1=325
5x=325-1
5x=324
=>x \(\in\phi\)
b)3x-1+5*3x-1=162
3x-1(1+5)=162
3x-1=162/6
3x-1=27=33
=>x-1=3
x=3+1
x=4
c)(2x-1)6=(1-2x)8
(2x-1)6=(-2x-1)8=(2x-1)8=(2x-1)6*(2x-1)2
=>(2x-1)2=1
2x-1=1
2x=1+1
2x=2
x=2/2
x=1
*)2x-1=0
2x=0+1
2x=1
x=1/2
![](https://rs.olm.vn/images/avt/0.png?1311)
3n-1 + 5.3n-1 = 162
3n-1.6 = 162
3n-1 = 27 = 33
=> n-1 = 3
n = 4
3n - 1 + 5.3n - 1 = 162
=> 3n - 1(1 + 5) = 162
=> 3n - 1.6 = 162
=> 3n - 1 = 27
=> 3n - 1 = 33
=> n - 1 = 3
=> n = 2
vậy_
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
3x-1+5.3x-1=162
=>3x-1.(1+5)=162
=>3x-1.6=162=>3x-1=162:6=27=33
=>x-1=3=>x=4
5x+5x+2=650
=>5x+5x.52=650
=>5x.(1+25)=650
=>5x.26=650=>5x=650:26=25=52
=>x=2
3x-1+5.3x-1=162
3x-1 .(5 + 1)=162
3x-1 . 6 =162
3x-1 =162:6
3x-1 =27
3x-1 =3\(^3\)
x - 1 = 3
x = 3 + 1
x = 4
3x-1+5.3x-1=162
3x-1.1+5.3x-1=162
3x-1.(1+5)=162.Suy ra:3x-1=162:6=27
3x:3=27.Suy ra:3x=3.27=81=34(81=34)
Vậy x=4
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