Question

[Nguyễn Hữu Minh]

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Answer 1

[Member lỗi thời :>>]

8.

\(\frac{4^5+4^5+4^5+4^5}{3^5+3^5+3^5}.\frac{6^5+6^5+6^5+6^5+6^5+6^5}{2^5+2^5}=2^n\)

\(\Rightarrow\frac{4^5.4}{3^5.3}.\frac{6^5.6}{2^5.2}=2^n\)\(\Rightarrow\frac{4^6}{3^6}.\frac{6^6}{2^6}=2^n\)

\(\Rightarrow\frac{\left(2^2\right)^6.\left(2.3\right)^6}{3^6.2^6}=2^n\)\(\Rightarrow\frac{2^{12}.3^6.2^6}{3^6.2^6}=2^n\)

\(\Rightarrow2^{12}=2^n\)=> n = 12

Answer 2

[Member lỗi thời :>>]

9.

\(\frac{1}{4}.\frac{2}{6}.\frac{3}{8}.....\frac{31}{64}=2^n\)

\(\Rightarrow\frac{1}{2.2}.\frac{2}{2.3}.\frac{3}{2.4}.....\frac{31}{2.32}=2^n\)

\(\Rightarrow\frac{1}{2^{16}}.\left(\frac{1}{2}.\frac{2}{3}.\frac{3}{4}.....\frac{31}{32}\right)=2^n\)

\(\Rightarrow2^{-16}.\left(\frac{1.2.3.....31}{2.3.4.....32}\right)=2^n\)

\(\Rightarrow2^{-16}.\frac{1}{32}=2^n\)

\(\Rightarrow2^{-16}.\frac{1}{2^5}=2^n\)

\(\Rightarrow2^{-16}.2^{-5}=2^n\)

\(\Rightarrow2^{-21}=2^n\)

=> n = -21