Question

[le nguyen khanh chi]

giúp mình giải sbt toán lớp 6  câu 15 bai số đo góc

Answer 1

[ʚ๖ۣۜKɦáηɦ ๖ۣۜHυүềηɞ‏]

Giải

$\begin{array}{c}15,{25}^o=15\frac{1^o}{4}={15}^o{15}^{\prime }={915}^{\prime }\\ 30,5^o=30\frac{1^o}{2}={30}^o{30}^{\prime }={1830}^{\prime }\\ 60,{75}^o=60\frac{3^o}{4}={60}^o{45}^{\prime }={3645}^{\prime }\\ 90,2^o=90\frac{1^o}{5}={90}^o{12}^{\prime }={5412}^{\prime }\\ 45,{15}^o=45\frac{3^o}{20}={45}^o{9}^{\prime }={2709}^{\prime }\end{array}$

Answer 2

[ʚ๖ۣۜKɦáηɦ ๖ۣۜHυүềηɞ‏]

Để đây mik viết rõ ra nhé !!!

30,5o = 30(1/2)o = 30o30’ = 1830’

60,75o = 60(3/4)o = 60o45’ = 3645’

90,2o = 90(1/5)o = 90o12’ = 5412’

45,15o = 45(3/20)o = 45o9’ = 2709’