7 phần ? nhân 5 =3 và 1/2 nhanh nha mình cần luôn
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kí hiệu /:phần,kí hiệu'."nhân
a)5/4-5/8+-2/3=30/24+15/24+(-16/24)=29/24
b)7/19.8/11+7/19.3/11+12/19
=7/19.(8/11+3/11)+12/19
=7/19.11/11+12/19
=7/19.1+12/19
=7/19+2/19=9/19
chúc học tốt!
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\(\dfrac{4}{3}-x=\dfrac{2}{5}\\ x=\dfrac{4}{3}-\dfrac{2}{5}\\ x=\dfrac{14}{15}\)
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1/5 * 2/6 * 3/7 * 4 = 1/5 * 1/3 * 3/7 * 4
= 1/5 * 1/7 * 4
= 1/35 * 4
= 1/140
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a) 5 : 3/4 - 4 4/5 : 3/4
= 5 . 4/3 - 24/5 . 4/3
= (5 - 24/5) . 4/3
= 1/5 × 4/3
= 4/15
b) -3/5 . 2/7 + (-3/7) . 3/5 + (-3/7)
= (-3/7) . (2/5 + 3/5 + 1)
= (-3/7) . 2
= -6/7
c) [(-4 2/7) . 7/11 + 7/11 . (5 1/3)] . 5 - 5 2/3
= (-30/7 . 7/11 + 7/11 . 16/3) . 5 - 17/3
= (-30/11 + 112/33) . 5 - 17/3
= 2/3 . 5 - 17/3
= 10/3 - 17/3
= -7/3
d) 5/39 . [(7 4/5) . (1 2/3) + (8 1/3) . (7 4/5)]
= 5/39 . (39/5 . 5/3 + 25/3 . 39/5)
= 5/39 . 39/5 . (5/3 + 25/3)
= 1 . 10
= 10
=
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a,1/5+4/11+4/5+7/11
=(1/5+4/5)+(4/11+7/11)
=1+1
=2
Chọn B
1367.54+1367.45+1367
=1367.(54+45+1)
=1367.100
=136700
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\(a) {4\over12}={4.5\over12.5}={20\over60}\)
\({1\over5}={1.12\over5.12}={12\over60}\)
\({-4\over15}={-4.4\over15.5}={-16\over60}\)
b)\({-7\over10}={-7.3\over10.3}={-21\over20}\)
\({1\over2}={1.15\over2.15}={15\over30}\)
\({-4\over15}={-4.2\over15.2}={-8\over30}\)
c)\({-5\over14}={-5.30\over14.30}={-150\over420}\)
\({3\over20}={3.21\over20.21}={63\over420}\)
\({-4\over21}={-4.20\over21.20}={-80\over420}\)
d)\({4\over18}={4.5\over18.5}={20\over90}\)
\({1\over18}={1.18\over5.18}={18\over90}\)
\({-6\over15}={-6.6\over15.6}={-36\over90}\)
Nói lời giữ lời nha ^_^..........Mệt wá........
a)4/12=1.5/12.5=5/60
1/5=1.12/5.12=5/60
-4/15=-4.4/15.4=-16/60
b)-7/10=-7.3/10.3=-21/30
1/2=1.15/2.15=15/30
-4/15=-4.2/15.2=-8/30
c)-5/14=-5.30/14/30=150/420
3/20=3.21/20.21=63/420
-4/21=-4.20/21.20=-80/420
d)4/18=4.5/18.5=20/90
1/5=1.18/5.18=18/90
-6/15=-6.6/15.6=-36/90
\(\frac{7}{x}\times5=3\frac{1}{2}\)
\(\frac{7}{x}\times5=\frac{7}{2}\)
\(\frac{7}{x}=\frac{7}{2}\div5\)
\(\frac{7}{x}=\frac{7}{10}\)
\(\Rightarrow\)\(x=10\)
\(\frac{7}{x}\cdot5=3\frac{1}{2}\)
=> \(\frac{35}{x}=\frac{7}{2}\)
=> \(7x=35\cdot2\)
=> \(7x=70\)
=> \(x=70:7\)
=> \(x=10\)