Tìm x : \(\frac{-2}{x}=\frac{-x}{\frac{8}{25}}\)
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a,\(\frac{x}{-15}=\frac{-60}{x}\)=\(x^2\)= [-15 ] . [60] = 900 \(\Rightarrow\)x = + 30
a.
\(\frac{x}{-15}=\frac{-60}{x}=x^2=\left(-15\right):\left(60\right)=900\Rightarrow x=+30\)
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a.
\(\frac{x}{-15}=-\frac{60}{x}\)
\(x\times x=15\times60\)
\(x^2=900\)
\(x^2=\left(\pm30\right)^2\)
\(x=\pm30\)
Vậy \(x=-30\) hoặc \(x=30\)
b.
\(-\frac{2}{x}=\frac{-x}{\frac{8}{25}}\)
\(x\times x=2\times\frac{8}{25}\)
\(x^2=\frac{16}{25}\)
\(x^2=\left(\pm\frac{4}{5}\right)^2\)
\(x=\pm\frac{4}{5}\)
Vậy \(x=\frac{4}{5}\) hoặc \(x=-\frac{4}{5}\)
Chúc bạn học tốt ^^
a/Theo bài ra ta có x.x= (-15).(-60)= \(x^2\)=900 mà 900= \(30^2\)suy ra x=30
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Trả lời:
\(B=\frac{0,75-30\%+\frac{3}{7}+\frac{3}{13}}{2,75-2,2+1\frac{4}{7}+3\frac{2}{3}}\)
\(B=\frac{\frac{3}{4}-\frac{3}{10}+\frac{3}{7}+\frac{3}{13}}{\frac{11}{4}-\frac{11}{5}+\frac{11}{7}+\frac{11}{3}}\)
\(B=\frac{2019}{1820}\div\frac{2431}{420}\)
\(B=\frac{2019}{1820}\times\frac{420}{2431}\)
\(B=\frac{6057}{31603}\)
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2/5.x:7/3.1/8=25/15
2/5.x:7/24=5/3
2/5.x=5/3.7/24
2/5.x=6/34
x=6/34:2/5
x=15/34
\(\frac{2}{5}x:\frac{7}{3}.\frac{1}{8}=\frac{25}{15}\Leftrightarrow\frac{2}{5}x:\frac{7}{3}.\frac{1}{8}=\frac{5}{3}\Leftrightarrow\frac{2}{5}x:\frac{7}{3}=\frac{5}{3}:\frac{1}{8}\Leftrightarrow\frac{2}{5}x:\frac{7}{3}=\frac{5}{3}.8\Leftrightarrow\frac{2}{5}x:\frac{7}{3}=\frac{40}{3}\)
\(\Leftrightarrow\frac{2}{5}x=\frac{40}{3}.\frac{7}{3}\Leftrightarrow\frac{2}{5}x=\frac{280}{3}\Leftrightarrow x=\frac{280}{3}:\frac{2}{5}\Leftrightarrow x=\frac{280}{3}.\frac{5}{2}\Leftrightarrow x=\frac{700}{3}\)
Vậy .........
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\(a,\frac{7+x}{12}=\frac{2}{3}\)
\(=>7+x.3=12.2\)
\(3\left(7+x\right)=24\)
\(\left(7+x\right)=24:3\)
\(7+x=8\)
\(x=8-7\)
\(x=1\)
\(b,\frac{25-x}{8}=\frac{1}{2}\)
\(25-x.2=8.1\)
\(2\left(25-x\right)=8\)
\(25-x=8:2\)
\(25-x=4\)
\(x=25-4\)
\(x=21\)