3x-(-18)=3^3
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5|-3x - 3| = 4|3x + 3| - 18 : (-3)
5(3x + 3) = 4(3x + 3) + 6
15x + 15 = 12x + 12 + 6
15x - 12x = 18 - 15
3x = 3
x = 1
a: =>5x=25
hay x=5
b: =>6x=21
hay x=7/2
c: =>2x=4
hay x=2
\(\dfrac{x+3}{x^2-3x}+\dfrac{3}{x^2+3x}+\dfrac{2x-18}{x^2-9}\\ =\dfrac{x^2+6x+9+3x-9+2x^2-18x}{x\left(x-3\right)\left(x+3\right)}=\dfrac{3x^2-9x}{x\left(x-3\right)\left(x+3\right)}\\ =\dfrac{3x\left(x-3\right)}{x\left(x-3\right)\left(x+3\right)}=\dfrac{3}{x+3}\)
\(=\dfrac{x+3}{x\left(x-3\right)}+\dfrac{3}{x\left(x+3\right)}+\dfrac{2x-18}{\left(x-3\right)\left(x+3\right)}\)
\(=\dfrac{x^2+6x+9+3x-9+4x-36}{x\left(x+3\right)\left(x-3\right)}=\dfrac{x^2+13x-36}{x\left(x+3\right)\left(x-3\right)}\)
\(\frac{x^3-9x}{18-6x}=\frac{-x^3-3x}{6}\)
\(\frac{x\left(x^2-9\right)}{6\left(3-x\right)}=\frac{-x\left(x^2+3\right)}{6}\)
\(\frac{x\left(x-3\right)\left(x+3\right)}{-6\left(x-3\right)}=\frac{-x\left(x^2+3\right)}{6}\)
\(\frac{-x\left(x+3\right)}{6}=\frac{-x\left(x^2+3\right)}{6}\)
\(\Rightarrow-x^2-3x=-x^3-3x\)
\(\Rightarrow-x^2-3x+x^3+3x=0\)
\(\Rightarrow x^3-x^2=0\)
\(\Rightarrow x^2\left(x-1\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x^2=0\\x-1=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=0\\x=1\end{cases}}\)
vậy \(\orbr{\begin{cases}x=0\\x=1\end{cases}}\)
1)\(10-2\left(4-3x\right)=-4\)
\(\Rightarrow2\left(4-3x\right)=10-\left(-4\right)\)
\(\Rightarrow2\left(4-3x\right)=14\)
\(\Rightarrow4-3x=7\)
\(\Rightarrow3x=-3\)
\(\Rightarrow x=-1\)
Vậy x=-1
2)????
3)\(24:\left(3x-2\right)=-3\)
\(\Rightarrow3x-2=-8\)
\(\Rightarrow3x=-6\)
\(\Rightarrow x=-2\)
Vậy x=-2
4)\(-45:5\left(-3-2x\right)=3\)
\(\Rightarrow5\left(-3-2x\right)=-15\)
\(\Rightarrow-3-2x=-3\)
\(\Rightarrow2x=0\)
\(\Rightarrow x=0\)
Vậy x=0
_Học tốt_
3x- (-18) = 27
3x = 27 + (-18)
3x = 9
x = 9 : 3 = 3