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`(5+8/17):x+(-4/17):x+(3+1/7):(17+1/3)=4/11`
`(5+8/17)xx1/x-4/17xx1/x+22/7:52/17=4/11`
`(5+4/17)xx1/x+187/182=4/11`
`89/17xx1/x=-1329/2002`
`x=-118281/34034`
Số to quá ;-;
\(\left(5+\dfrac{8}{17}\right):x+\left(\dfrac{-4}{17}\right):x+\left(3+\dfrac{1}{17}\right):\left(17+\dfrac{1}{3}\right)=\dfrac{4}{11}\)
\(\left(\dfrac{93}{17}+\dfrac{-4}{17}\right):x+\dfrac{52}{17}:\dfrac{52}{3}=\dfrac{4}{11}\)
\(\dfrac{89}{17}:x+\dfrac{3}{17}=\dfrac{4}{11}\)
\(\dfrac{89}{17}:x=\dfrac{4}{11}-\dfrac{3}{17}\)
\(\dfrac{89}{17}:x=\dfrac{35}{187}\)
\(x=\dfrac{89}{17}:\dfrac{35}{187}\)
\(x=\dfrac{979}{35}\)
Mk thấy đề bài thế này mới đúng nếu sai thì nhắc mk nha!
1) Ta có: \(\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{7}{25}\cdot\dfrac{5}{7}\right)\)
\(=\left(\dfrac{3}{4}\cdot\dfrac{5}{97}+\dfrac{1}{9}\cdot\dfrac{13}{47}\right)\cdot\left(\dfrac{1}{5}-\dfrac{1}{5}\right)\)
=0
2) Ta có: \(\dfrac{8}{17}\cdot\dfrac{4}{15}+\dfrac{8}{17}\cdot\dfrac{22}{15}-\dfrac{8}{15}\cdot\dfrac{9}{17}\)
\(=\dfrac{8}{17}\left(\dfrac{4}{15}+\dfrac{22}{15}-\dfrac{9}{15}\right)\)
\(=\dfrac{8}{17}\cdot\dfrac{15}{15}=\dfrac{8}{17}\)
3) Ta có: \(\dfrac{2021}{2}\cdot\dfrac{1}{3}+\dfrac{4042}{4}\cdot\dfrac{1}{5}+\dfrac{6063}{3}\cdot\dfrac{22}{15}\)
\(=\dfrac{2021}{2}\left(\dfrac{1}{3}+\dfrac{1}{5}\right)+2021\cdot\dfrac{22}{15}\)
\(=\dfrac{2021}{2}\cdot\dfrac{8}{15}+\dfrac{2021}{2}\cdot\dfrac{44}{15}\)
\(=\dfrac{2021}{2}\cdot\dfrac{52}{15}\)
\(=\dfrac{52546}{15}\)
4) Ta có: \(\dfrac{4}{7}\cdot\dfrac{2}{13}+\dfrac{8}{13}:\dfrac{7}{4}+\dfrac{4}{7}:\dfrac{13}{2}+\dfrac{4}{7}\cdot\dfrac{1}{13}\)
\(=\dfrac{4}{7}\left(\dfrac{2}{13}+\dfrac{8}{13}+\dfrac{2}{13}+\dfrac{1}{13}\right)\)
\(=\dfrac{4}{7}\)
\(\frac{3}{4}:x=\frac{17}{8}\)
\(x=\frac{3}{4}:\frac{17}{8}\)
\(x=\frac{51}{32}\)
3/4 : x = 17/8
x = 3/4 : 17/8
x = 6/17
-HT-