3 nhân(x-1/6) -2 nhân (x-1/3)= 2/3
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GH
0
KT
0
8 tháng 7 2019
a, \(3\left(x-1\right)-\left(2x+3\right)=5\)
\(\Rightarrow3x-3-2x-3=5\)
\(\Rightarrow x-6=5\)
\(\Rightarrow x=11\)
b, \(\frac{6}{13}=\frac{x}{7}\)
\(\Rightarrow x=\frac{6}{13}.7\)
\(\Rightarrow x=\frac{42}{13}\)
c, \(|x|=4\)
\(\Rightarrow x=4\)hoặc \(x=-4\)
d,, \(|x-2|+5=10\)
\(Th1:x-2>0\)
\(\Rightarrow x-2+5=10\)
\(\Rightarrow x+3=10\)
\(\Rightarrow x=7\)
\(Th2;x-2< 0\)
\(\Rightarrow2-x+5=10\)
\(\Rightarrow7-x=10\)
\(\Rightarrow x=-3\)
e, \(3|x-1|-6=9\)
\(Th1:x-1>0\)
\(\Rightarrow3\left(x-1\right)-6=9\)
\(\Rightarrow3x-3-6=9\)
\(\Rightarrow3x-9=9\)
\(\Rightarrow3x=18\)
\(\Rightarrow x=6\)
\(Th2:x-1< 0\)
\(\Rightarrow3\left(1-x\right)-6=9\)
\(\Rightarrow3-3x-6=9\)
\(\Rightarrow-3x-3=9\)
\(\Rightarrow-3x=12\)
\(\Rightarrow x=-4\)
NH
1
AH
26 tháng 9 2016
1 / 5 + x = 3 / 7 + 1 / 3
1 / 5 + x = 16 /21
x = 16 / 21 - 1 / 5
x = 59 / 105
x - 1 / 2 = 2 / 3 - 1 / 5
x - 1 / 2 = 7 / 15
x = 7 / 15 + 1 / 2
x = 29 / 30
3 / 5 * x = 2 / 7+ 1 / 4
3 / 5 * x = 15 / 28
x = 15 / 28 : 3 / 5
x = 25 / 28
7 / 8 : x = 1 / 6 * 2 / 3
7 / 8 : x = 1 / 9
x = 7 / 8 : 1 / 9
x = 63 / 8
TP
1
4 tháng 12 2023
1: \(x\left(x-1\right)+\left(1+x\right)^2\)
\(=x^2-x+x^2+2x+1\)
\(=2x^2+x+1\)
Đa thức này ko phân tích được nha bạn
2: \(\left(x+1\right)^2-3\left(x+1\right)\)
\(=\left(x+1\right)\cdot\left(x+1\right)-\left(x+1\right)\cdot3\)
\(=\left(x+1\right)\left(x+1-3\right)\)
\(=\left(x+1\right)\left(x-2\right)\)
3: \(2x\cdot\left(x-2\right)-\left(x-2\right)^2\)
\(=2x\left(x-2\right)-\left(x-2\right)\cdot\left(x-2\right)\)
\(=\left(x-2\right)\left(2x-x+2\right)\)
\(=\left(x-2\right)\left(x+2\right)\)
4: \(3x\left(x-1\right)^2-\left(1-x\right)^3\)
\(=3x\left(x-1\right)^2+\left(x-1\right)^3\)
\(=3x\left(x-1\right)^2+\left(x-1\right)^2\cdot\left(x-1\right)\)
\(=\left(x-1\right)^2\cdot\left(3x+x-1\right)\)
\(=\left(x-1\right)^2\cdot\left(4x-1\right)\)
5: \(3x\left(x+2\right)-5\left(x+2\right)^2\)
\(=\left(x+2\right)\cdot3x-\left(x+2\right)\cdot\left(5x+10\right)\)
\(=\left(x+2\right)\left(3x-5x-10\right)\)
\(=\left(-2x-10\right)\left(x+2\right)\)
\(=-2\left(x+5\right)\left(x+2\right)\)
6: \(4x\left(x-y\right)+3\left(y-x\right)^2\)
\(=4x\left(x-y\right)+3\left(x-y\right)^2\)
\(=\left(x-y\right)\cdot4x+\left(x-y\right)\left(3x-3y\right)\)
\(=\left(x-y\right)\cdot\left(4x+3x-3y\right)\)
\(=\left(x-y\right)\left(7x-3y\right)\)
\(3\left(x-\dfrac{1}{6}\right)-2\left(x-\dfrac{1}{3}\right)=\dfrac{2}{3}\)
\(\Leftrightarrow3x-\dfrac{1}{2}-2x+\dfrac{2}{3}=\dfrac{2}{3}\)
\(\Leftrightarrow x=\dfrac{1}{2}\)
Vậy \(x=\dfrac{1}{2}\)
Bài bạn sai rồi!
Cẩn thận về dấu kìa :))