NQ
3
K
Khách
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NN
1
S
5 tháng 2 2023
\(A=\dfrac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\)
\(=\dfrac{2^{10}.3^8-2.2^9.3^9}{2^{10}.3^8+2^8.3^8.2^2.5}\)
\(=\dfrac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}\)
\(=\dfrac{2^{10}.3^8\left(1-3\right)}{2^{10}.3^8\left(1+5\right)}\)
\(=-\dfrac{2}{6}=-\dfrac{1}{3}\)
NN
0
LM
0
NN
2
24 tháng 6 2016
\(A=\frac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\)
\(=\frac{2^{10}.3^8-2.2^9.3^9}{2^{10}.3^8+2^8.3^8.2^2.5}\)
\(=\frac{2^{10}.3^8-2^{10}.3^9}{2^{10}.2^8+2^{10}.3^8.5}\)
\(=\frac{2^{10}.3^8\left(1-3\right)}{2^{10}.3^8\left(1+5\right)}\)
\(=\frac{-2}{6}=-\frac{1}{3}\)
24 tháng 6 2016
\(A=\frac{\left(2^2\right)^5.\left(3^2\right)^4-2.2^9.3^9}{2^{10}.3^8+2^8.3^8.2^2.5}\)
\(A=\frac{2^{10}.3^8-2^{11}.3^9}{2^{10}.3^8+2^{10}.3^8.5}\)
\(A=\frac{2^{10}.3^8.\left(1-2.3\right)}{2^{10}.3^8.\left(1+5\right)}\)
\(A=\frac{1-6}{6}\)
\(A=\frac{-5}{6}\)
TQ
0
HN
1
28 tháng 2 2016
\(\frac{\left(2^2\right)^5.\left(3^2\right)^4-2.6^8.2.3}{2^{10}.3^8+6^8.2^2.5}\)
\(\frac{2^{10}.3^8-2^2.6^8.3}{2^{10}.3^8+6^8.2^2.5}\)
Rồi sao nữa mình không biết
BB
1
NL
Nguyễn Lê Phước Thịnh
CTVHS
24 tháng 5 2022
\(\dfrac{4^5\cdot9^4-2\cdot6^9}{2^{10}\cdot3^8+6^8\cdot20}=\dfrac{2^{10}\cdot3^8-2\cdot2^9\cdot3^9}{2^{10}\cdot3^8+3^8\cdot2^8\cdot2^2\cdot5}\)
\(=\dfrac{2^{10}\cdot3^8-2^{10}\cdot3^9}{2^{10}\cdot3^8+2^{10}\cdot3^8\cdot5}=\dfrac{2^{10}\cdot3^8\cdot\left(1-3\right)}{2^{10}\cdot3^8\cdot6}\)
\(=\dfrac{-2}{6}=\dfrac{-1}{3}\)
D
1
12 tháng 8 2016
\(\frac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\)
=\(\frac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.5.3^8}=\frac{2^{10}.3^8\left(1-3\right)}{2^{10}.3^8\left(1+5\right)}=-\frac{2}{6}=-\frac{1}{3}\)
K = (4^5 × 9^4 - 2 × 6^9) / (2^10 × 3^8 + 2^8 × 3^8 × 20)
= (2^10 × 3^8 - 2 × 2^9 × 3^9) / (2^10 × 3^8 + 2^8 × 3^8 × 20)
= (2^10 × 3^8 - 2^10 × 3^9) / (2^10 × 3^8 + 2^8 × 3^8 × 20)
= [2^10 × 3^8(1 - 3)] / [2^8 × 3^8(4 + 20)]
= (-2 × 2^10 × 3^8) / (24 × 2^8 × 3^8)
= -8/24
= -1/3
Vậy K = -1/3
K = (4⁵ × 9⁴ - 2 × 6⁹) / (2¹⁰ × 3⁸ + 2⁸ × 3⁸ × 20)
= (2¹⁰ × 3⁸ - 2 × 2⁹ × 3⁹) / (2¹⁰ × 3⁸ + 2⁸ × 3⁸ × 2² × 5)
= [2¹⁰ × 3⁸ × (1 - 3)] / [2¹⁰ × 3⁸ × (1 + 5)]
= -2/6
= -1/3
Ta có: \(4^5\cdot9^4-2\cdot6^9\)
\(=2^{10}\cdot3^8-2\cdot2^9\cdot3^9\)
\(=2^{10}\cdot3^8-2^{10}\cdot3^9\)
\(=2^{10}\cdot3^8\cdot\left(1-3\right)=-2^{11}\cdot3^8\)
Ta có: \(2^{10}\cdot3^8+2^8\cdot3^8\cdot20\)
\(=2^{10}\cdot3^8+2^8\cdot3^8\cdot2^2\cdot5\)
\(=2^{10}\cdot3^8+2^{10}\cdot3^8\cdot5\)
\(=2^{10}\cdot3^8\cdot\left(1+5\right)=2^{10}\cdot3^8\cdot6=2^{11}\cdot3^9\)
Ta có: \(\frac{4^5\cdot9^4-2\cdot6^9}{2^{10}\cdot3^8+2^8\cdot3^8\cdot20}\)
\(=\frac{-2^{11}\cdot3^8}{2^{11}\cdot3^9}=-\frac13\)