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a: \(\Leftrightarrow\left(a^2-3\right)\left(a^2-10\right)< 0\)
\(\Leftrightarrow3< a^2< 10\)
\(\Leftrightarrow\left[{}\begin{matrix}\sqrt{3}< a< \sqrt{10}\\-\sqrt{10}< a< -\sqrt{3}\end{matrix}\right.\)
d: \(\Leftrightarrow\left(a-3\right)\left(a+1\right)< 0\)
hay -1<a<3
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Bài 2:
a: =>x=0 hoặc x+3=0
=>x=0 hoặc x=-3
b: =>x-2=0 hoặc 5-x=0
=>x=2 hoặc x=5
c: =>x-1=0
hay x=1
![](https://rs.olm.vn/images/avt/0.png?1311)
Câu 2:
a: \(\Leftrightarrow x+2\in\left\{3;9\right\}\)
hay \(x\in\left\{1;7\right\}\)
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a, 3 + x = 8
x = 8 - 3
x = 5
b, x + 4 = 0
x = 0 - 4
x = - 4
c x + 8 = 3
x = 3 - 8
x = -5
d 2 + x = -10
x = -10 - 2
x = - 12
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a. 2x+\(\dfrac{4}{5}\)=0 hoặc 3x-\(\dfrac{1}{2}\)=0
2x=- 4/5 hoặc 3x=1/2
x=-2/5 hoặc x=\(\dfrac{1}{6}\)
b. x-\(\dfrac{2}{5}\)=0 hoặc x+\(\dfrac{4}{7}\)=0
x=2/5 hoặc x=-\(\dfrac{4}{7}\)
d. x(1+5/8-12/16)=1
\(\dfrac{7}{8}\)x=1=> x=8/7
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\(a,x\in\left\{-6;-5;...;2;3\right\}\\ b,x\in\left\{-2;-1;...;8;9\right\}\\ c,x\in\left\{-4;-3;-2;-1\right\}\\ d,x\in\left\{-10;-9;...;3;4\right\}\\ e,x\in\varnothing\\ f,x\in\left\{-1;0;1\right\}\)
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a) (x - 140) : 7 = 33 - 23 . 3
(x - 140) : 7 = 27 - 8 . 3 = 27 - 24 = 3
x - 140 = 3 x 7 = 21
x = 21 + 140 = 161
b) x3 . x2 = 28 : 23
x5 = 25
=> x = 2
c) (x + 2) . ( x - 4) = 0
x = -2 hoặc 4
d) 3x-3 - 32 = 2 . 32 =
3x-3 - 9 = 2 . 9 = 18
3x-3 = 18 + 9 = 27
3x-3 = 33
=> x - 3 = 3
x = 3 + 3 = 6