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30 tháng 11 2017

 \(M=\frac{\left(2^3\right)^{20}+\left(2^2\right)^{20}}{\left(2^2\right)+\left(2^6\right)^5}\)

\(M=\frac{2^{60}+2^{40}}{2^{50}+2^{30}}\)

\(M=\frac{2^{40}\cdot2^{20}+2^{40}\cdot1}{2^{30}\cdot2^{20}+2^{30}\cdot1}\)

\(M=\frac{2^{40}\cdot\left(2^{20}+1\right)}{2^{30}\cdot\left(2^{20}+1\right)}\)

\(M=\frac{2^{40}}{2^{30}}\)

\(M=2^{40-30}\)

\(M=2^{10}\)

\(M=1024\)

22 tháng 9 2017

M=820 +420/425+645

M=(23)20+(22)20/(22)25+(25)5

M=260+240/250+225

M=225(235+215)/225(225+1)

M=235+215/225+1

12 tháng 7 2016

\(M=\frac{8^{20}+4^{20}}{4^{25}+64^5}\)

\(M=\frac{\left(2^3\right)^{20}+\left(2^2\right)^{20}}{\left(2^2\right)^{25}+\left(2^6\right)^5}\)

\(M=\frac{2^{60}+2^{40}}{2^{50}+2^{30}}\)

\(M=\frac{2^{40}\left(2^{20}+1\right)}{2^{30}\left(2^{20}+1\right)}\)

\(M=2^{10}\)

\(M=1024\)

22 tháng 7 2016

\(\frac{8^{20}+4^{20}}{4^{25}+64^5}=\frac{\left(2^3\right)^{20}+\left(2^2\right)^{20}}{\left(2^2\right)^{25}+\left(2^6\right)^5}=\frac{2^{60}+2^{40}}{2^{50}+2^{30}}=\frac{2^{40}\times\left(2^{20}+1\right)}{2^{30}\times\left(2^{20}+1\right)}=2^{10}=1024\)

Chúc bạn học tốt ^^

1 tháng 12 2016

- Có thể cho tôi một số bài tập dạng này không?

19 tháng 7 2016

\(M=\frac{\left(2^3\right)^{20}+\left(2^2\right)^{20}}{\left(2^2\right)^{25}+\left(2^6\right)^5}=\frac{2^{60}+2^{40}}{2^{50}+2^{30}}=\frac{2^{40}\left(2^{20}+1\right)}{2^{30}\left(2^{20}+1\right)}=2^{10}\)

19 tháng 7 2016

\(M=\frac{8^{20}+4^{20}}{4^{25}+64^5}\)

     = \(\frac{\left(2^3\right)^{20}+\left(2^2\right)^{20}}{\left(2^2\right)^{25}+\left(2^6\right)^5}=\frac{2^{60}+2^{40}}{2^{50}+2^{30}}=\frac{2^{40}\left(2^{20}+1\right)}{2^{30}\left(2^{20}+1\right)}=2^{10}\)

5 tháng 4 2020

\(M=\frac{4^{20}.\left(2^{20}+1\right)}{4^{15}.\left(4^{10}+1\right)}\)

\(M=4^5\)

\(M=1024\)

Chúc bạn học tốt cho mik k nha.Thanks

19 tháng 8 2018

\(M=\frac{8^{20}+4^{20}}{4^{25}+64^5}\)

\(=\frac{\left(2^3\right)^{20}+\left(2^2\right)^{20}}{\left(2^2\right)^{25}+\left(2^6\right)^5}\)

\(=\frac{2^{60}+2^{40}}{2^{50}+2^{30}}\)

\(=\frac{2^{40}\left(2^{20}+1\right)}{2^{30}\left(2^{20}+1\right)}\)

\(=\frac{2^{40}}{2^{30}}=2^{10}\)

19 tháng 8 2018

\(\frac{8^{20}+4^{20}}{4^{25}+64^5}\)

\(=\frac{\left(2^3\right)^{20}+\left(2^2\right)^{20}}{\left(2^2\right)^{25}+\left(2^6\right)^5}\)

\(=\frac{2^{60}+2^{40}}{2^{25}+2^{30}}\)

\(=\frac{2^{40}\left(2^{20}+1\right)}{2^{25}\left(1+2^5\right)}\)

\(=\frac{2^{15}\left(2^{20}+1\right)}{1+2^5}\)

\(=\frac{2^{35}+2^{15}}{1+2^5}\)

30 tháng 8 2016

\(M=\frac{8^{20}+4^{20}}{4^{25}+64^5}=\frac{4^{20}.\left(2^{20}+1\right)}{4^{25}+\left(4^3\right)^5}=\frac{4^{20}.\left(2^{20}+1\right)}{4^{25}+4^{15}}\)

                                                                      \(=\frac{4^{20}.\left(4^{10}+1\right)}{4^{25}.\left(4^{10}+1\right)}=\frac{1}{4^5}=\frac{1}{1024}\)

11 tháng 12 2016

\(\frac{8^{20}+4^{20}}{4^{25}+64^5}\)=\(\frac{\left(2^3\right)^{20}+\left(2^2\right)^{20}}{\left(2^2\right)^{25}+\left(2^6\right)^5}\)=\(\frac{2^{60}+2^{40}}{2^{50}+2^{30}}\)=\(\frac{2^{40}\left(2^{20}+1\right)}{2^{30}\left(2^{20}+1\right)}\)=\(\frac{2^{40}}{2^{30}}\)= 210

30 tháng 10 2020

1. \(x^{10}=25x^8\Leftrightarrow x^{10}:x^8=25\Leftrightarrow x^2=25=5^2\Leftrightarrow x=5\)

2. \(\frac{8^{20}+4^{20}}{4^{25}+64^5}=\frac{\left(2^3\right)^{20}+\left(2^2\right)^{20}}{\left(2^2\right)^{25}+\left(2^6\right)^5}=\frac{2^{60}+2^{40}}{2^{50}+2^{30}}=\frac{2^{40}\left(2^{20}+1\right)}{2^{30}\left(2^{20}+1\right)}=\frac{2^{40}}{2^{30}}=2^{10}\)

1)\(x^{10}=25x^8\)

\(\Rightarrow x^{10}:x^8=25\)

\(\Rightarrow x^2=5^2\)

\(\Rightarrow\orbr{\begin{cases}x=5\\x=-5\end{cases}}\)

2)\(\frac{8^{20}+4^{20}}{4^{25}+64^5}=\frac{\left(2^3\right)^{20}+\left(2^2\right)^{20}}{\left(2^2\right)^{25}+\left(2^6\right)^5}=\frac{2^{60}+2^{40}}{2^{50}+2^{30}}=\frac{2^{40}\left(2^{20}+1\right)}{2^{30}\left(2^{20}+1\right)}=2^{10}\)

\(2^5\).\(9^5\).\(2^8\).\(9^8\)

=(\(2^5\).\(2^8\)).(\(9^5\).\(9^8\))

=\(^{2^{13}}\).\(9^{13}\)

=\(^{2.9^{13}}\)

=\(18^{13}\)