Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
\(a,2^4.38-2^4.37=2^4.\left(38-37\right)=2^4.1=16\\ b,4^2.444446-4^3.111111\\ =4^2.\left(444446-4.111111\right)\\ =4^2.2=16.2=32\\ c,\left(2^9.3+2^9.5\right):2^{12}\\ =2^9.\left(3+5\right):2^{12}=2^9.8:2^{12}=2^9.2^3:2^{12}=2^{9+3-12}=2^0=1\\ d,13^2-\left(5^2.4+2^4.15\right)=13^2-5.4.\left(5+4.3\right)\\ =169-20.17\\ =169-340=-171\)
Thế này à:
a, \(\frac{2^{13}+25}{2^{10}}\)
b, \(\frac{21^2.14.125}{35^5.6}\)
c,\(\frac{45^3.20^4.18^2}{180^5}\)
d, \(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
2 mũ 13 ta chia cho 2 mũ 10 ta có là 2 mũ 3 chuyển thành 8 rồi cộng cho 25 ta có là 33
A=5^10 .9+5^10.7 / 5^9.2^4
A=5^10.(9+7) / 5^9.16
A=5^10.16 /5^9.16
A=5^9.5.16/5^9.16
=>A=5/1
=>A=1
B=2^10.55+2^10. 26 / 2^8 . 27
B=2^10.(55+26) / 2^8 .27
B=2^10.81 / 2^8 .27
B=2^8.2^2.81 / 2^8.27
=>B=2^2.81 / 27
=>B=4.81 / 27
=>B=4.3^3.3 / 3^3
=>B=4.3
=>B=12
Cn phần C thì....mik chưa rõ lém nhưng mak nếu ai cko mik là dzui lém òy......ủng hộ nhoa mina
a) \(2^3\cdot4^5=2^3\cdot2^{10}=2^{13}\)
b) \(3^4\cdot27^2=3^4\cdot3^6=3^{10}\)
c) \(16^{10}:8^2=2^{40}:2^6=2^{34}\)
d) \(12^3:3^3=\left(12:3\right)^3=4^3\)
e) \(3^4\cdot2^4=\left(3\cdot2\right)^4=6^4\)
g) \(9^{13}\cdot5^{26}=9^{13}\cdot25^{13}=\left(9\cdot25\right)^{13}=225^{13}\)
=))
\(4^2\cdot120-4^3\cdot17+4^2\cdot34\)
\(=4^2\left(120-4\cdot17+34\right)\)
\(=16\left(120-68+34\right)\)
\(=16\cdot86=1088\)
bài 1) thực hiện phép tính
a) \(4^5-81:3^2=1024-9=1015\)
b) \(3^2.22-3^2.12=3^2.2\left(11-6\right)=18.5=90\)
c) \(2^3.15-\left[115-\left(12-5\right)\right]=120-\left(115-12+5\right)=120-115+12-5=12\)
d) \(3.3^2-19^{21}:19^{20}+2010^0=27-19+1=9\)
e)\(7^{25}:\left(7^{21}.46+7^{21}.3\right)=7^{25}:\left(7^{21}.49\right)=\frac{7^{21}.7^4}{7^{21}.49}=\frac{2401}{49}=49\)
bài 2)Tim x
a) 716 - (x - 143) = 695
<=> x - 143 = 716 - 695
<=> x - 143 = 21
<=> x = 21 + 143
<=> x = 164
vậy x = 164
\(a,\)\(\frac{2^5\times3^{12}\times7^8}{2^7\times3^{10}\times7^9}=\frac{3^2\times\left(2^5\times3^{10}\times7^8\right)}{2^2\times7\times\left(2^5\times3^{10}\times7^8\right)}\)\(=\frac{3^2}{2^2\times7}=\frac{9}{28}\)
\(b,\)Tương tự
a, 20^2 - 6^ 2= 400 - 36 = 364
b,3^3 . 18 - 3^3 . 12 = 3^3 . ( 18-12) = 27 . 6 = 162
c, 39 . 213 + 87 . 39 = ( 213 + 87) . 39 = 300 . 39 = 110700
d, 80 - [ 130 - ( 12 - 4)^2] = 80 - [130 - (3^2) ] = 80 - 130 - 9 = -59
a) 2^4 * 38 - 2^4 * 37 = 16 * 38 - 16 * 37 = 608 - 592 = 16
b) 4^2 * 444446 - 4^3 * 111111 = 16 * 444446 - 64 * 111111 = 7107136 - 7106944 = 192
c) (2^9 * 3 + 2^9 * 5) / 2^12 = (512 * 3 + 512 * 5) / 4096 = (1536 + 2560) / 4096 = 4096 / 4096 = 1
d) 13^2 - (5^2 * 4 + 2^2 * 15) = 169 - (25 * 4 + 4 * 15) = 169 - (100 + 60) = 169 - 160 = 9
Viết lạ vậy em ):)