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\(B=\frac{7.6^{10}.2^{20}.3^6-2^{19}.6^{15}}{9.6^{19}.2^9-4.3^{17}.2^{26}}\)
\(B=\frac{7.\left(2.3\right)^{10}.2^{20}.3^6-2^{19}.\left(2.3\right)^{15}}{3^2.\left(2.3\right)^{19}.2^9-2^2.3^{17}.2^{26}}\)
\(B=\frac{7.2^{30}.3^{16}-2^{34}.3^{15}}{3^{21}.2^{11}-2^{28}.3^{17}}\)
\(B=\frac{2^{30}.3^{15}.\left(7.3-2^4\right)}{3^{17}.2^{11}.\left(3^4-2^{17}\right)}\)
\(B=\frac{2^{19}.\left(21-2^4\right)}{3^2.\left(3^4-2^{17}\right)}\)
@_@ tự tính!
\(B=\frac{7.\left(2.3\right)^{10}.2^{20}.3^6-2^{19}.\left(2.3\right)^{15}}{3^2.\left(2.3\right)^{19}.2^9-4.3^{17}.2^{26}}\\ B=\frac{7.2^{10}.3^{10}.2^{20}.3^6-2^{19}.2^{15}.3^{15}}{3^2.2^{19}.3^{19}.2^9-2^2.3^{17}.2^{26}}\\ B=\frac{7.2^{30}.3^{16}-2^{34}.3^{15}}{3^{21}.2^{28}-2^{28}.3^{17}}\)
\(B=\frac{7.2^{30}.3.3^{15}-2^{34}.3^{15}}{3^{15}.3^6.2^{28}-2^{28}.3^{15}.3^2}\\ B=\frac{3^{15}.\left(7.2^{30}.3-3^{34}\right)}{3^{15}.\cdot\left(3^6-3^2\right)}\\ B=\frac{7.2^{30}.3-3^{34}}{3^6-3^2}\)
\(B=\frac{7.6^{10}.2^{20}.3^6-2^{19}.6^{15}}{9.6^{19}.2^9-4.3^{17}.2^{26}}\)
\(B=\frac{7.3^{16}.2^{30}-2^{34}.3^{15}}{3^{21}.2^{28}-2^{28}.3^{17}}\)
\(=\frac{3^{15}.2^{30}.\left(7.3-2^4\right)}{3^{17}.2^{28}.\left(3^4-1\right)}=\frac{2^2.\left(21-16\right)}{3^2.\left(81-1\right)}=\frac{2^2.5}{3^2.2^4.5}=\frac{1}{3^2.2^2}=\frac{1}{36}\)
1/ \(\frac{9.5^{20}.27^9-3.9^{15}.25^9}{7.3^{29}.125^6-3.3^9.15^{19}}\)
\(=\frac{5^{20}.3^{29}-3^{31}.5^{18}}{7.3^{29}.5^{18}-3^{29}.5^{19}}=\frac{3^{29}.5^{18}.\left(25-9\right)}{3^{29}.5^{18}.\left(7-5\right)}=\frac{16}{2}=8\)
CÁC BÀI CÒN LẠI TƯƠNG TỰ HẾT NHÉ E
\(A=\frac{7.6^{10}.2^{20}.3^6-2^{18}.6^{15}}{9.6^{19}.2^9-4.3^{17}.2^{26}}=\frac{7.\left(2.3\right)^{10}.2^{20}.3^6-2^{18}.\left(2.3\right)^{15}}{3^2.\left(2.3\right)^{19}.2^9-2^2.3^{17}.2^{26}}\)
\(=\frac{7.2^{10}.3^{10}.2^{20}.3^6-2^{18}.2^{15}.3^{15}}{3^2.2^{19}.3^{19}.2^9-2^2.3^{17}.2^{26}}\)
\(=\frac{7.2^{30}.3^{16}-2^{33}.3^{15}}{2^{28}.3^{21}-2^{28}.3^{17}}\)
\(=\frac{2^{30}.3^{15}.\left(7.3-2^3\right)}{2^{28}.3^{17}.\left(3^4-1\right)}\)
\(=\frac{2^2.13}{3^2.80}=\frac{4.13}{9.80}=\frac{13}{180}\)
\(A=\frac{7\cdot2^{10}\cdot3^{10}\cdot2^{20}\cdot3^6-2^{18}\cdot2^{15}\cdot3^{15}}{3^2\cdot3^{19}\cdot2^{19}\cdot2^9-2^2\cdot3^{17}\cdot2^{26}}=\frac{7\cdot2^{30}\cdot3^{16}-2^{33}\cdot3^{15}}{3^{21}\cdot2^{28}-2^{28}\cdot3^{17}}\)
\(A=\frac{2^{30}\cdot3^{15}\left(7\cdot3-2^3\right)}{2^{28}\cdot3^{17}\left(3^4-1\right)}=\frac{2^{30}\cdot3^{15}\cdot13}{2^{28}\cdot3^{17}\cdot2^4\cdot5}=\frac{13}{2^2\cdot3^2\cdot5}=\frac{13}{180}\)
Chị ko bt có sai ko nx nếu có sai thông cảm chị nha
^-^
c) G = \(\frac{636363.37-373737.63}{1+2+3+...+2017}\)
G = \(\frac{63.10101.37-37.10101.63}{1+2+3+...+2017}\)
G = \(\frac{0}{1+2+3+...+2017}\)
=> G = 0
Vậy G = 0
a) \(E=\frac{1}{1.2.3}+\frac{1}{2.3.4}+...+\frac{1}{48.49.50}\)
\(\Rightarrow E=\frac{1}{2}\left(\frac{2}{1.2.3}+\frac{2}{2.3.4}+...+\frac{2}{48.49.50}\right)\)
\(\Rightarrow E=\frac{1}{2}\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+...+\frac{1}{48.49}-\frac{1}{49.50}\right)\)
\(\Rightarrow E=\frac{1}{2}\left(\frac{1}{1.2}-\frac{1}{49.50}\right)\)
\(\Rightarrow E=\frac{1}{2}.\frac{612}{1225}\)
\(\Rightarrow E=\frac{306}{1225}\)
Vậy...
b) \(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}=\frac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}=\frac{5.2^{30}.3^{18}-2^{29}.3^{20}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}\)
\(=\frac{2^{29}.3^{18}\left(5.2-3^2\right)}{2^{28}.3^{18}\left(5.3-7.2\right)}=\frac{2.1}{1}=2\)
d) Bạn xem lại đề nhé
a) \(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)
\(=\frac{5.2^{30}.3^{18}-2^2.2^{27}.3^{20}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}\)
\(=\frac{2^{29}.3^{18}\left(5.2-3^2\right)}{2^{18}.3^{18}\left(5.3-7.2\right)}\)
\(=\frac{2.1}{1}=2\)
\(\frac{7.6^{10}.2^{20}.3^6-2^{19}.6^{15}}{9.6^{19}.2^9-4.3^{17}.2^{26}}=\frac{7.3^{16}.2^{30}-2^{34}.3^{15}}{3^{21}.2^{28}-2^{28}.3^{17}}=\frac{3^{15}.2^{30}\left(7.3-2^4\right)}{3^{17}.3^{28}\left(3^4-1\right)}\)\(=\frac{3^2\left(21-16\right)}{2^2\left(81-1\right)}=\frac{2^2.5}{3^2.2^4.5}=\frac{1}{3^2.2^2}=\frac{1}{36}\)
Hok tốtt
# owe
