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Ta có:
\(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+.....+\frac{2}{99.101}\)
\(=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+....+\frac{1}{99}-\frac{1}{101}\)
\(=1-\frac{1}{101}=\frac{100}{101}< 1\)
Vậy \(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{99.101}< 1\)
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a) 2x + 37 = 45
=> 2x = 45 - 37 = 8
=> x = 4
b) 35 - ( 5 . ( x - 1 ) = 10
=> 5 . ( x - 1 ) = 35 - 10 = 25
=> x - 1 = 25 : 5 = 5
=> x = 6
c) 4 . 2x - 3 = 125
=> 4 . 2x = 128
=> 2x = 128 : 4 = 32
=> 2x = 25
=> x = 5
d) 32 ⁝ x
=> x ∈ Ư(32) = { 1 ; 2 ; 4 ; 8 ; 16 ; 32 }
A)2X+17=45
=>2X=28
=>X=14
B)35 - 5(X-1)=10
=>5(7-X+1)=10
=>8-X=2
=>X=6
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\(150-5\left(x-2\right)^2=25\)
\(5\left(x-2\right)^2=150-25=125\)
\(\left(x-2\right)^2=125:5=25\)
\(\Rightarrow\orbr{\begin{cases}x-2=5\\x-2=-5\end{cases}\Rightarrow\orbr{\begin{cases}x=7\\x=-3\end{cases}}}\)
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trả lời nhanh ạ