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a) \(\frac{13+x}{20}=\frac{3}{4}\)
\(\Rightarrow\frac{13+x}{20}=\frac{15}{20}\)
\(\Rightarrow13+x=15\)
\(\Rightarrow\) \(x=15-13\)
\(\Rightarrow\)\(x=2\)
b)\(\frac{23-x}{25}=\frac{4}{5}\)
\(\Rightarrow\frac{23-x}{25}=\frac{20}{25}\)
\(\Rightarrow23-x=20\)
\(\Rightarrow\) \(x=23-20\)
\(\Rightarrow\) \(x=3\)
a, 13+x/20= 3/4
Suy ra: ( 13+x). 4= 20.3
Suy ra: (13+x).4=60
Suy ra: 13+x=60:4
Suy ra: 13+x=15
Suy ra: x=15-13
Suy ra: x=2
Vậy x=2
![](https://rs.olm.vn/images/avt/0.png?1311)
b) \(23-\frac{x}{25}=\frac{4}{5}\)
\(\frac{x}{25}=23-\frac{4}{5}\)
\(\frac{x}{25}=\frac{111}{5}=\frac{555}{25}\)
=> x = 555
![](https://rs.olm.vn/images/avt/0.png?1311)
`(13+x)/20 = 3/4`
`(13+x) xx4=3xx20`
`(13+x)xx4=60`
`13+x=60:4`
`13+x=15`
`x=15-13`
`x=2`
__
`(23-x)/25 =4/5`
`(23-x)xx5=4xx25`
`(23-x)xx5=100`
`23-x=100:5`
`23-x=20`
`x=23-20`
`x=3`
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Câu 1 sai đề.
Câu 2:
\(23-\frac{x}{25}=\frac{4}{5}\)
\(\frac{x}{25}=\frac{111}{5}\)
\(x=555\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 2:
a, \(\dfrac{5}{23}\) \(\times\) \(\dfrac{17}{26}\) + \(\dfrac{5}{23}\) \(\times\) \(\dfrac{9}{26}\)
= \(\dfrac{5}{23}\) \(\times\) ( \(\dfrac{17}{26}\) + \(\dfrac{9}{26}\))
= \(\dfrac{5}{23}\) \(\times\) \(\dfrac{26}{26}\)
= \(\dfrac{5}{23}\)
b, \(\dfrac{3}{4}\) \(\times\) \(\dfrac{7}{9}\) + \(\dfrac{7}{4}\) \(\times\) \(\dfrac{3}{9}\)
= \(\dfrac{7}{12}\) + \(\dfrac{7}{12}\)
= \(\dfrac{14}{12}\)
= \(\dfrac{7}{6}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(13+\frac{x}{20}=\frac{3}{4}\Leftrightarrow\frac{x}{20}=\frac{3}{4}-13\Leftrightarrow\frac{x}{20}=-12\frac{1}{4}\)
\(\Leftrightarrow\frac{x}{20}=-\frac{49}{4}\Leftrightarrow4x=20\cdot\left(-49\right)\Leftrightarrow4x=-980\)
\(\Leftrightarrow x=\left(-980\right):4\Leftrightarrow x=-245\)
\(23-\frac{x}{25}=\frac{4}{5}\Leftrightarrow\frac{x}{25}=23-\frac{4}{5}\Leftrightarrow\frac{x}{25}=22\frac{1}{5}\)
\(\Leftrightarrow\frac{x}{25}=\frac{111}{5}\Leftrightarrow5x=25\cdot111\Leftrightarrow5x=2775\)
\(\Leftrightarrow x=2775:5\Leftrightarrow x=555\)
a)13+x/20=3/4 b)23-x/25=4/5
x/20=3/4-13 x/25=23-4/5
x/20=-12,25 x/25=22,2
x=-245 x=555
![](https://rs.olm.vn/images/avt/0.png?1311)
13+\(\frac{x}{20}\)=\(\frac{3}{4}\)
=>\(\frac{x}{20}\)=\(\frac{3}{4}-13\)
=>\(\frac{x}{20}=\frac{3}{4}-\frac{52}{4}=-\frac{49}{4}=-\frac{245}{20}\)
=>x=-245
\(23-\frac{x}{25}=45\)
\(=>\frac{x}{25}=23-45=-22=-\frac{550}{25}\)
=>x=-550
![](https://rs.olm.vn/images/avt/0.png?1311)
a) 120 - 20 : x = 110
20:x= 120 - 110
20:x= 10
x= 20:10=2
b) 213 - ( x - 13 ) = 1442 : 14
213 - (x-13)=103
x-13= 213 - 103
x-13=110
x=110+13
x=123
c) 2550 : [ 120 - ( x - 5 ) ] = 25
120 - (x-5) = 2550:25
120 - (x-5)=102
x-5 = 120 - 102
x-5= 18
x=18+5
x=23
![](https://rs.olm.vn/images/avt/0.png?1311)
a) x + 40*25 = 2000
x + 1000 = 2000
x = 2000 - 1000
x = 1000.
b) (x + 40)*25 = 2000
x + 40 = 2000 : 25
x + 40 = 80
x = 80 - 40
x = 40.
c) (x - 10)*5 = 100 - 20*4
(x - 10)*5 = 100 - 80
(x - 10)*5 = 20
x - 10 = 20 : 5
x - 10 = 4
x = 4 + 10
x = 14.
d) Các số hạng x + 2; x + 4; ... ; x + 1996 lập thành một dãy số cách đều với khoảng cách bằng 2.
Từ x + 2 đến x + 1996 có:
(1996 - 2) : 2 + 1 = 998 số hạng.
Tổng các số hạng ở vế trái là:
(x + 2) + (x + 4) + ... + (x + 1996) = (x + 1996 + x + 2)*998 : 2 = (2*x + 1998)*998 : 2
Vậy ta có:
(2*x + 1998)*998 : 2 = 998000
(2*x + 1998)*998 = 998000*2
2*x + 1998 = 998000*2 : 998
2*x + 1998 = 2000
2*x = 2000 - 1998
2*x = 2
x = 2 : 2
x = 1.
ủng hộ nha
Ta có: a) \(x+40.25=2000\)
\(\Rightarrow x+1000=2000\)
\(\Rightarrow x=2000-1000=1000\)
b) \(\left(x+40\right).25=2000\)
\(\Rightarrow x+40=2000:25=80\)
\(\Rightarrow x=80-40=40\)
c) \(\left(x-10\right).5=100-20.4\)
\(\Rightarrow\left(x-10\right).5=100-80\)
\(\Rightarrow\left(x-10\right).5=20\)
\(\Rightarrow x-10=20:5=4\)
\(\Rightarrow x=10+4=14\)
d) \(\left(x+2\right)+\left(x+4\right)+....+\left(x+1996\right)=998000\)
\(\Rightarrow\left(x+x+...+x\right)+\left(2+4+..+1996\right)=998000\)
\(\Rightarrow998x+997002=998000\)
\(\Rightarrow998x=998000-996002=998\)
\(\Rightarrow x=998:998=1\)
Ủng hộ nha m.n ^_^
13 + \(\dfrac{x}{20}\)= \(\dfrac{3}{4}\)
⇔ \(\dfrac{x}{20}\) = \(\dfrac{3}{4}\) - 13
⇔ \(\dfrac{x}{20}\) = \(\dfrac{-49}{4}\)
⇔ x = \(\dfrac{-49}{4}\) x 20
x = - 245
b, 23 - \(\dfrac{x}{25}\)= \(\dfrac{4}{5}\)
\(\dfrac{x}{25}\) = 23 - \(\dfrac{4}{5}\)
\(\dfrac{x}{45}\) = \(\dfrac{115}{5}\)
x = \(\dfrac{115}{5}\) x 45
x = 999
13 + \dfrac{x}{20}20x= \dfrac{3}{4}43
⇔ \dfrac{x}{20}20x = \dfrac{3}{4}43 - 13
⇔ \dfrac{x}{20}20x = \dfrac{-49}{4}4−49
⇔ x = \dfrac{-49}{4}4−49 x 20
x = - 245
b, 23 - \dfrac{x}{25}25x= \dfrac{4}{5}54
\dfrac{x}{25}25x = 23 - \dfrac{4}{5}54
\dfrac{x}{45}45x = \dfrac{115}{5}5115
x = \dfrac{115}{5}5115 x 45
x = 999