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a,(72000+18000)-(3x+3000)=12000
90000-(3x+3000)=12000
3x+3000=90000-12000
3x+3000=78000
3x=78000-3000
3x=75000
x=75000:3
x=25000
b,[3.(x+2):7]:4=120
3.(x+2):7=120:4
3.(x+2):7=30
3.(x+2)=30.7
3.(x+2)=210
x+2=210:3
x+2=70
x=70-2
x=68
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nhanh hộ mình với mình sắp đi học rồi.Ai trả lời đc mình cho 1 k nhanh nhanh lên nha, nguy cấp rồi đó
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\(4.\left(x-1\right)+\left[\left(4.750-2150\right)-\left(1750-1160\right)\right]=3000\)
\(\Rightarrow4.\left(x+1\right)+\left[3000-2150\right]-690=3000\)
\(\Rightarrow4.\left(x+1\right)+850-690=3000\)
\(\Rightarrow4.\left(x+1\right)+160=3000\)
\(\Rightarrow4.\left(x+1\right)=3000-160=2840\)
\(\Rightarrow x+1=2840:4=710\)
\(\Rightarrow x=710-1=709\)
Vậy x = 709
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A=1/20+3/40+5/104+7/260+9/580+11/1160
A=1/4.5+3/5.8+5/8.13+7/13.20+9/20.29+11/29.40
A=1/4-1/5+1/5-1/8+1/8-1/13+1/13-1/20+...+1/29-1/40
A=1/4-1/40=9/40
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5\(^{2\text{x}+1}\) . 133 + 13 . 5\(^{2\text{x}-1}\) = 4750
5\(^{2\text{x}-1}\) . 5\(^2\) . 133 + 13 . 5\(^{2\text{x}-1}\) = 4750
5\(^{2\text{x}-1}\) ( 5\(^2\) . 133 + 13 ) = 4750
5\(^{2\text{x}-1}\) . 3338 = 4750
5\(^{x-1}\) = \(\dfrac{2375}{1669}\)
=> Không có giá trị x
\(4\left(x-1\right)+\left[\left(4750-2160\right)-\left(1750-1160\right)\right]=4x-4+4750-2160-1750+1160==4x+1996\)