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mik ko ghi lại đề nhé!
\(A=\left(\frac{18}{15}.\frac{1}{4}.3\right)+\left(-\frac{47}{60}\right).\frac{24}{47}\)
\(A=\frac{8}{5}+\left(-\frac{2}{5}\right)\)
\(A=\frac{6}{5}\)
\(B=\frac{3}{4}.\frac{28}{15}-\left(\frac{8}{15}+\frac{1}{4}\right).\frac{24}{47}-\frac{17}{13}\)
\(B=\frac{7}{5}-\frac{47}{60}.\frac{24}{47}-\frac{17}{13}\)
\(B=\frac{7}{5}-\frac{2}{5}-\frac{17}{13}\)
\(B=1-\frac{17}{13}\)
\(B=-\frac{4}{13}\)
THANKS
![](https://rs.olm.vn/images/avt/0.png?1311)
\(1\dfrac{13}{15}\cdot0,75\cdot\left(\dfrac{8}{15}+0.25\right)\cdot\dfrac{24}{47}\)
= \(\dfrac{28}{15}\cdot\dfrac{3}{4}\cdot\left(\dfrac{8}{15}+\dfrac{1}{4}\right)\cdot\dfrac{24}{47}\)
= \(\dfrac{7}{5}\cdot\dfrac{47}{60}\cdot\dfrac{24}{47}\)
\(=\dfrac{329}{300}\cdot\dfrac{24}{47}\)
\(=\dfrac{14}{25}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
mik ko hiểu chỗ 1 19/60 và 1 23/24 là s bạn có f vầy ko :( sau thì ib để mik sửa ạ
\(B=\frac{13}{15}\cdot0,25\cdot3+\left(\frac{8}{15}-1\frac{19}{60}\right):1\frac{23}{24}\)
\(B=\frac{13}{15}\cdot0,25\cdot3+\left(\frac{8}{15}-\frac{79}{60}\right):\frac{47}{24}\)
\(B=\frac{13}{15}\cdot\frac{1}{4}\cdot\frac{3}{1}+\left(\frac{8}{15}-\frac{79}{60}\right):\frac{47}{24}\)
\(B=\frac{39}{60}+\left(\frac{8}{15}-\frac{79}{60}\right):\frac{47}{24}\)
\(B=\frac{13}{20}+\left(\frac{32}{60}-\frac{79}{60}\right):\frac{47}{24}\)
\(B=\frac{13}{20}+\left(-\frac{47}{60}\right):\frac{47}{24}\)
\(B=\frac{13}{20}+\left(-\frac{2}{5}\right)\)
\(B=\frac{13}{20}+\left(-\frac{8}{20}\right)\)
\(B=\frac{5}{20}=\frac{1}{4}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{28}{15}\times\frac{1}{4}\times3+\left(\frac{8}{15}-\frac{79}{60}\right)\times\frac{24}{47}\)
=\(\frac{7}{15}\times3+\left(\frac{32}{60}-\frac{79}{60}\right)\times\frac{24}{47}\)
=\(\frac{7}{5}+\frac{47}{60}\times\frac{24}{47}\)
=\(\frac{7}{5}+\frac{2}{5}\)
=\(\frac{5}{5}\)
=\(1\)
\(\frac{28}{15}\)x\(\frac{1}{4}\)x3+(\(\frac{8}{15}\)+\(\frac{-79}{60}\))x\(\frac{24}{47}\)=
=\(\frac{28}{15}\)x\(\frac{1}{4}\)x3+(\(\frac{32}{60}\)+\(\frac{-79}{60}\))x\(\frac{24}{47}\)
=\(\frac{28}{15}\)x\(\frac{1}{4}\)x3+\(\frac{-47}{60}\)x\(\frac{24}{47}\)
=\(\frac{7}{15}\)x3+\(\frac{-47}{60}\)x\(\frac{24}{47}\)
=\(\frac{7}{5}\)+\(\frac{-2}{5}\)
=\(\frac{5}{5}\)=1
![](https://rs.olm.vn/images/avt/0.png?1311)
Bài 1 :
A = \(\left(\frac{-2}{3}+\frac{5}{4}-\frac{1}{6}\right)-\frac{24}{10}=\frac{-2}{3}+\frac{5}{4}-\frac{1}{6}+\frac{-24}{10}\)\(=\frac{7}{12}+\frac{-1}{6}+\frac{-12}{5}=\frac{5}{12}+\frac{-12}{5}=\frac{-119}{60}\)
B = \(\frac{13}{15}\cdot0,25\cdot3+\left(\frac{8}{15}-\frac{79}{60}:\frac{47}{24}\right)\)\(=\frac{13}{60}\cdot3+\left(\frac{8}{15}-\frac{158}{235}\right)=\frac{13}{20}+\frac{-98}{705}=\frac{1441}{2820}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
a: =-79+47+52-20
=99-99
=0
b: \(=67-19-48-15=-15\)
c: \(=\left(-8\right)\cdot14+17\cdot3=-112+51=-61\)
d: \(=37+48-72-30=7-24=-17\)
Ta có:
\(B=\frac{13}{15}.0,25.3+\left(\frac{8}{15}-\frac{79}{60}\right):\frac{47}{24}\)
\(=\frac{13}{5}.\frac{1}{4}+\left(\frac{32}{60}-\frac{79}{60}\right).\frac{24}{47}\)
\(=\frac{13}{20}+\frac{-47}{60}.\frac{24}{47}\)
\(=\frac{13}{20}+\frac{-2}{5}=\frac{13}{20}+\frac{-8}{20}=\frac{5}{20}=\frac{1}{4}\)
bn phải chỉ co mình cách giải chứ