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ta có: \(\frac{7}{6}-\frac{5}{2}x=\frac{13}{9}+\frac{7}{4}x\)
<=> \(\frac{7}{6}-\frac{13}{9}=\frac{7}{4}x+\frac{5}{2}x\)
<=> \(-\frac{5}{18}=\frac{17}{4}x\)
=> \(x=-\frac{10}{153}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{2}{3}x-\frac{5}{4}=\frac{7}{6}-\frac{1}{2}x\)
\(\frac{2}{3}x+\frac{1}{2}x=\frac{7}{6}+\frac{5}{4}\)
\(\frac{7}{6}x=\frac{29}{12}\)
\(x=\frac{29}{12}:\frac{7}{6}\)
\(x=\frac{29}{14}\)
Ta có: \(\frac{2}{3}x-\frac{5}{4}=\frac{7}{6}-\frac{1}{2}x\)
\(\Rightarrow\frac{2}{3}x-\frac{1}{2}x=\frac{5}{4}+\frac{7}{6}\)
\(\Rightarrow\frac{1}{6}x=\frac{48}{24}=2\)
\(\Rightarrow x=2:\frac{1}{6}=12\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Mình làm như thế này nek
\(\frac{\frac{1}{4}+\frac{3}{7}-\frac{4}{5}}{0,75+\frac{9}{7}-2\frac{2}{5}}+\frac{\frac{3}{14}-\frac{2}{10}+\frac{5}{18}+\frac{7}{66}}{\frac{6}{7}-\frac{4}{5}+\frac{10}{9}+\frac{14}{33}}\)
\(=\frac{\frac{1}{4}+\frac{3}{7}-\frac{4}{5}}{\frac{2}{4}+\frac{9}{7}-\frac{12}{5}}+\frac{\frac{1}{2}\cdot\left(\frac{3}{7}-\frac{2}{5}+\frac{5}{9}+\frac{7}{33}\right)}{2\cdot\left(\frac{3}{7}-\frac{2}{5}+\frac{5}{9}+\frac{7}{33}\right)}\)
\(=\frac{\frac{1}{4}+\frac{3}{7}-\frac{4}{5}}{3\cdot\left(\frac{1}{4}+\frac{3}{7}-\frac{4}{5}\right)}+\frac{\frac{1}{2}}{2}\)
\(=\frac{1}{3}+\frac{1}{4}=\frac{7}{12}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: \(\frac{7}{10}-\frac{5}{8}.x-\frac{7}{6}=\frac{5}{6}.x\)
\(\Rightarrow\frac{7}{10}-\frac{7}{6}=\frac{5}{6}x+\frac{5}{8}x\)
\(\Rightarrow\frac{21}{30}-\frac{35}{30}=\left(\frac{5}{6}+\frac{5}{8}\right)x\)
\(\Rightarrow-\frac{7}{15}=\left(\frac{15}{24}+\frac{20}{24}\right)x\)
\(\Rightarrow-\frac{7}{15}=\frac{35}{24}x\)
\(\Rightarrow x=-\frac{7}{15}:\frac{35}{24}\)
\(\Rightarrow x=-\frac{7}{15}.\frac{24}{35}\)
\(\Rightarrow x=-\frac{8}{25}\)
Vậy \(x=-\frac{8}{25}\)
Chuk bạn hok tốt!
![](https://rs.olm.vn/images/avt/0.png?1311)
\(B=4\cdot\left(-\frac{1}{2}\right)^3:\left(\frac{4}{5}\right)^0\cdot\frac{1}{2}-\frac{\frac{3}{5}-\frac{3}{9}+\frac{3}{13}}{\frac{7}{5}-\frac{7}{9}+\frac{7}{13}}\)
\(=4\cdot\frac{-1}{8}:1\cdot\frac{1}{2}-\frac{3\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{13}\right)}{7\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{13}\right)}\)
\(=-\frac{1}{4}-\frac{3}{7}=-\frac{19}{28}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
ta có: \(\frac{3}{4}x-\frac{5}{6}=\frac{7}{8}\)<=> \(\frac{3}{4}x=\frac{41}{24}\)
=> \(x=\frac{41}{18}\)
Vậy x= \(\frac{41}{18}\)
Ta có: \(\frac{3}{4}x-\frac{5}{6}=\frac{7}{8}\)
\(\Rightarrow\frac{3}{4}x=\frac{7}{8}+\frac{5}{6}\)
\(\Rightarrow\frac{3}{4}x=\frac{21}{24}+\frac{20}{24}\)
\(\Rightarrow\frac{3}{4}x=\frac{41}{24}\)
\(\Rightarrow x=\frac{41}{24}:\frac{3}{4}\)
\(\Rightarrow x=\frac{41}{24}.\frac{4}{3}\)
\(\Rightarrow x=\frac{41}{18}\)
Vậy \(x=\frac{41}{18}\)
Chuk pạn hok tốt!
![](https://rs.olm.vn/images/avt/0.png?1311)
1.\(\left(-\frac{6}{5}+\frac{6}{16}-\frac{6}{23}\right):\left(\frac{9}{5}-\frac{9}{16}+\frac{9}{23}\right)\)
\(=6\left(-\frac{1}{5}+\frac{1}{16}-\frac{1}{23}\right):\left(-9\right)\left(\frac{-1}{5}+\frac{1}{16}-\frac{1}{23}\right)\)
\(=6:\left(-9\right)=-\frac{2}{3}\)
2. \(\frac{\frac{3}{7}-\frac{3}{11}+\frac{3}{13}}{\frac{5}{7}-\frac{5}{11}+\frac{5}{13}}+\frac{0.5-\frac{1}{3}+\frac{1}{4}}{-\frac{3}{2}+1-\frac{3}{4}}\)
\(=\frac{3\left(\frac{1}{7}-\frac{1}{11}+\frac{1}{13}\right)}{5\left(\frac{1}{7}-\frac{1}{11}+\frac{1}{13}\right)}+\frac{\frac{1}{2}-\frac{1}{3}+\frac{1}{4}}{-3\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{4}\right)}\)
\(=\frac{3}{5}-\frac{1}{3}\)
\(=\frac{9}{13}-\frac{5}{15}=\frac{4}{15}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
<=> \(\frac{7}{6}-\frac{13}{9}=\frac{5}{2}x+\frac{7}{4}x\)
<=>\(-\frac{5}{18}=x.\left(\frac{5}{2}+\frac{7}{4}\right)\)
<=>\(-\frac{5}{18}=\frac{17}{4}.x\)
=> \(x=-\frac{5}{18}:\frac{17}{4}\)
\(x=-\frac{10}{153}\)
\(\frac{7}{6}-\frac{5}{2}x\)
nhầm!