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Ta có: \(\frac{7}{10}-\frac{5}{8}.x-\frac{7}{6}=\frac{5}{6}.x\)
\(\Rightarrow\frac{7}{10}-\frac{7}{6}=\frac{5}{6}x+\frac{5}{8}x\)
\(\Rightarrow\frac{21}{30}-\frac{35}{30}=\left(\frac{5}{6}+\frac{5}{8}\right)x\)
\(\Rightarrow-\frac{7}{15}=\left(\frac{15}{24}+\frac{20}{24}\right)x\)
\(\Rightarrow-\frac{7}{15}=\frac{35}{24}x\)
\(\Rightarrow x=-\frac{7}{15}:\frac{35}{24}\)
\(\Rightarrow x=-\frac{7}{15}.\frac{24}{35}\)
\(\Rightarrow x=-\frac{8}{25}\)
Vậy \(x=-\frac{8}{25}\)
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{2}{3}x-\frac{5}{4}=\frac{7}{6}-\frac{1}{2}x\)
\(\frac{2}{3}x+\frac{1}{2}x=\frac{7}{6}+\frac{5}{4}\)
\(\frac{7}{6}x=\frac{29}{12}\)
\(x=\frac{29}{12}:\frac{7}{6}\)
\(x=\frac{29}{14}\)
Ta có: \(\frac{2}{3}x-\frac{5}{4}=\frac{7}{6}-\frac{1}{2}x\)
\(\Rightarrow\frac{2}{3}x-\frac{1}{2}x=\frac{5}{4}+\frac{7}{6}\)
\(\Rightarrow\frac{1}{6}x=\frac{48}{24}=2\)
\(\Rightarrow x=2:\frac{1}{6}=12\)
![](https://rs.olm.vn/images/avt/0.png?1311)
ta có: \(\frac{7}{6}-\frac{5}{2}x=\frac{13}{9}+\frac{7}{4}x\)
<=> \(\frac{7}{6}-\frac{13}{9}=\frac{7}{4}x+\frac{5}{2}x\)
<=> \(-\frac{5}{18}=\frac{17}{4}x\)
=> \(x=-\frac{10}{153}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
<=> \(\frac{7}{6}-\frac{13}{9}=\frac{5}{2}x+\frac{7}{4}x\)
<=>\(-\frac{5}{18}=x.\left(\frac{5}{2}+\frac{7}{4}\right)\)
<=>\(-\frac{5}{18}=\frac{17}{4}.x\)
=> \(x=-\frac{5}{18}:\frac{17}{4}\)
\(x=-\frac{10}{153}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: \(-\frac{5}{8}-x=-\frac{3}{20}-\left(-\frac{1}{6}\right)\)
\(\Rightarrow-\frac{5}{8}-x=-\frac{3}{20}+\frac{1}{6}\)
\(\Rightarrow x=-\frac{5}{8}-\left(-\frac{3}{20}+\frac{1}{6}\right)\)
\(\Rightarrow x=-\frac{5}{8}+\frac{3}{20}-\frac{1}{6}\)
\(\Rightarrow x=\frac{-75}{120}+\frac{18}{120}-\frac{20}{120}\)
\(\Rightarrow x=-\frac{77}{120}\)
Vậy \(x=-\frac{77}{120}\)
Chúc bạn hok tốt!
<=> x=\(-\frac{5}{8}+\frac{3}{20}-\frac{1}{6}=-\frac{77}{120}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có: \(\frac{7}{8}-\frac{1}{3}x=\frac{7}{10}+\frac{2}{3}x\)
<=> \(\frac{7}{8}-\frac{7}{10}=\frac{2}{3}x+\frac{1}{3}x\)
<=>\(\frac{7}{40}=x\)
Vậy x=7/40
\(\frac{7}{8}-\frac{1}{3}x=\frac{7}{10}+\frac{2}{3}\)
\(\Leftrightarrow-\frac{1}{3}x-\frac{2}{3}x=\frac{7}{10}-\frac{7}{8}\)
\(\Leftrightarrow-x=-\frac{7}{40}\)
\(\Leftrightarrow x=\frac{7}{40}=0,175\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\frac{4}{5}-\frac{3}{2}.x=\frac{7}{15}\)
\(\Leftrightarrow-\frac{3}{2}x=\frac{7}{15}-\frac{4}{5}=-\frac{1}{3}\)
\(\Leftrightarrow x=-\frac{1}{3}:\left(-\frac{3}{2}\right)=\frac{2}{9}\)
vậy x=\(\frac{2}{9}\)
\(\frac{4}{5}-\frac{3}{2}.x=\frac{7}{15}\)
\(\frac{3}{2}x=\frac{4}{5}-\frac{7}{15}\)
\(\frac{3}{2}x=\frac{1}{3}\)
\(x=\frac{1}{3}:\frac{3}{2}\)
\(x=\frac{2}{9}\)
ta có: \(\frac{3}{4}x-\frac{5}{6}=\frac{7}{8}\)<=> \(\frac{3}{4}x=\frac{41}{24}\)
=> \(x=\frac{41}{18}\)
Vậy x= \(\frac{41}{18}\)
Ta có: \(\frac{3}{4}x-\frac{5}{6}=\frac{7}{8}\)
\(\Rightarrow\frac{3}{4}x=\frac{7}{8}+\frac{5}{6}\)
\(\Rightarrow\frac{3}{4}x=\frac{21}{24}+\frac{20}{24}\)
\(\Rightarrow\frac{3}{4}x=\frac{41}{24}\)
\(\Rightarrow x=\frac{41}{24}:\frac{3}{4}\)
\(\Rightarrow x=\frac{41}{24}.\frac{4}{3}\)
\(\Rightarrow x=\frac{41}{18}\)
Vậy \(x=\frac{41}{18}\)
Chuk pạn hok tốt!![vui vui](/media/olmeditor/plugins/smiley/images/vui.png)