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a: =>4/3x=7/9-4/9=1/3
=>x=1/4
b: =>5/2-x=9/14:(-4/7)=-9/8
=>x=5/2+9/8=29/8
c: =>3x+3/4=8/3
=>3x=23/12
hay x=23/36
d: =>-5/6-x=7/12-4/12=3/12=1/4
=>x=-5/6-1/4=-10/12-3/12=-13/12
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a) =-5/7 +7/8-2/7+1/8- -1/12+ -13/12
=(-5/7-2/7)+(7/8+1/8)-(-1/12--13/12)
=-7/7+8/8 - 12/12
= -1+1+1
=1
b)= ( -3/8+11/8)-(12/11+ -1/11)+(-3/5- 2/5)
= 1- 1 + (-1)
=-1
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\(\frac{-4}{11}.\frac{2}{5}+\frac{6}{11}.\frac{-3}{10}\)
=\(\frac{2}{11}.\left(-2\right).\frac{2}{5}+\frac{2}{11}.3.\frac{-3}{10}\)
=\(\frac{2}{11}.\frac{-4}{5}+\frac{2}{11}.\frac{-9}{10}\)
=\(\frac{2}{11}.\left(\frac{-4}{5}+\frac{-9}{10}\right)\)
=\(\frac{2}{11}.\frac{-17}{10}\)
=\(\frac{-17}{55}\)
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\(A=\frac{\left(23\frac{11}{15}-26\frac{13}{20}\right)}{12^2+5^2}\cdot\frac{1-\frac{1}{30}-\frac{1}{42}-\frac{1}{56}}{3^2.13.2-13.5}-\frac{19}{37}\)
\(A=\frac{\left(23+\frac{11}{15}-26+\frac{13}{20}\right)}{144+25}\cdot\frac{1-\frac{1}{5.6}-\frac{1}{6.7}-\frac{1}{7.8}}{9.13.2-13.5}-\frac{19}{37}\)
\(A=\frac{\left(23+26+\frac{11}{15}-\frac{13}{20}\right)}{169}\cdot\frac{1-\left(\frac{1}{5}-\frac{1}{6}\right)-\left(\frac{1}{6}-\frac{1}{7}\right)-\left(\frac{1}{7}-\frac{1}{8}\right)}{13.\left(9.2-5\right)}-\frac{19}{37}\)
\(A=\frac{49+\frac{44}{60}-\frac{39}{60}}{169}\cdot\frac{1-\frac{1}{5}+\frac{1}{6}-\frac{1}{6}+\frac{1}{7}-\frac{1}{7}+\frac{1}{8}}{13.13}-\frac{19}{37}\)
\(A=\frac{49+\frac{1}{20}}{169}\cdot\frac{1-\frac{1}{5}+\frac{1}{8}}{169}-\frac{19}{37}\)
\(A=\frac{49\frac{1}{20}}{169}\cdot\frac{\frac{4}{5}+\frac{5}{40}}{169}-\frac{19}{37}\)
\(A=\frac{981}{169}\cdot\frac{\frac{32}{40}+\frac{5}{40}}{169}-\frac{19}{37}\)
\(A=\frac{981}{169}\cdot\frac{\frac{37}{40}}{169}-\frac{19}{37}\)
\(A=\frac{981.\frac{37}{40}}{169^2}-\frac{19}{37}\)
\(A=\frac{\frac{36297}{40}}{28561}-\frac{19}{37}\)
\(A=\frac{907,425}{28561}-\frac{19}{37}\)
\(A=\frac{33574,725}{1056757}-\frac{542659}{1056757}\)
\(A=\frac{-509084,275}{1056757}=-0,04604282...\)
Mik chỉ làm đc thế này thôi, ôn thi học kì II tốt nha bạn!
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<=> 3 - 1/6 + x = 2/3
<=> 17/6 + x = 2/3
<=> x = 2/3 - 17/6
=> x = -13/6
Vậy x = -13/6
\(3-\left(\frac{1}{6}-x\right)=\frac{2}{3}\)
\(\Rightarrow\frac{1}{6}-x=3-\frac{2}{3}\)
\(\Rightarrow\frac{1}{6}-x=\frac{7}{3}\)
\(\Rightarrow x=\frac{1}{6}-\frac{7}{3}\)
\(\Rightarrow x=\frac{-13}{6}\)
\(\frac{5}{6}-x=\frac{-7}{12}+\frac{2}{3}\)
\(\frac{5}{6}-x=\frac{-7}{12}+\frac{8}{12}\)
\(\frac{5}{6}-x=\frac{1}{12}\)
\(x=\frac{5}{6}-\frac{1}{12}\)
\(x=\frac{10}{12}-\frac{1}{12}\)
\(x=\frac{9}{12}\) \(=\frac{3}{4}\)
<=> 5/6 - x = 1/12
<=> -x = 1/12 - 5/6
<=> -x = -3/4
=> x = 3/4
Vậy x = 3/4