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\(10-2\left(4-3x\right)=-4\)
\(\Leftrightarrow10-8+6x=-4\)
\(\Leftrightarrow2+6x=-4\)
\(\Leftrightarrow6x=-4-2\)
\(\Leftrightarrow6x=-6\)
\(\Leftrightarrow x=\frac{-6}{6}\)
\(\Leftrightarrow x=-1\)
\(\text{Vậy }x=-1\)
10 - 2(4 - 3x)= -4
=> 10 - 8 + 6x = -4
=> 6x = -4 + 8 -10
=> 6x = -6
=> x = -1.
Vậy x = -1
![](https://rs.olm.vn/images/avt/0.png?1311)
\(2\left(x-1\right)+3\left(3x-2\right)=x-4\)
\(2x-2+9x-6=x-4\)
\(2x+9x-x-2-6=-4\)
\(10x-2-6=-4\)
\(10x-2=2\)
\(10x=4\)
\(x=\frac{2}{5}\)
Vậy \(x=\frac{2}{5}\)
\(3\left(4-x\right)-2\left(x-1\right)=x+20\)
\(12-3x-2x+2=x+20\)
\(12-5x+2=x+20\)
\(12-5x-x+2=20\)
\(12-6x+2=20\)
\(12-6x=18\)
\(6x=-6\)
\(x=-1\)
Vậy \(x=-1.\)
\(4\left(2x+7\right)-3\left(3x-2\right)=24\)
\(8x+28-9x+6=24\)
\(8x-9x+28+6=24\)
\(-x+34=24\)
\(-x=-10\)
\(x=10\)
Vậy \(x=10\)
\(3\left(x-2\right)+2x=10\)
\(3x-6+2x=10\)
\(3x+2x-6=10\)
\(5x=16\)
\(x=\frac{16}{5}\)
Vậy \(x=\frac{16}{5}\)
2(x-1)+3(3x-2)=x-4
=>2x-2=9x-6-x+4=0
=>10x-4=0
=>x=\(\frac{2}{5}\)
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4(x - 10) - (-3x + 4) = -2(x + 5) - (-4x +20)
=> 4x - 40 + 3x - 4 = -2x - 10 + 4x - 20
=> 7x - 44 = 2x - 30
=> 7x - 2x = -30 + 44
=> 5x = 14
=> x = 14 : 5
=> x = 14/5
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a)(4-x)2+15=40
(4-x)2=40-15
(4-x)2=25
(4-x)2=52
=>4-x=5
x=5-4
x=1
a) ( 4 - x )2 + 15 = 40
( 4 - x )2 = 40 - 15
( 4 - x )2 = 25
( 4 - x )2 = 52
4 - x = 5
x = 4 - 5
x = ( - 1 )
b, ( 3x - 2 )10 = ( 3x - 2 )4
=> x \(\in\left\{0;1\right\}\)
c, X = 1 + 4 + 42 + ......... + 42017
4X = 4 + 41 + ......... + 42018
4X - X = ( 4 + 41 + ........ + 42018 ) - ( 1 + 4 + 42 + ......... + 42017 )
4X - X = 4 + 41 + ......... + 42018 - 1 - 4 - 42 - ......... - 42017
=> 3X = 42018 - 1
=> X = \(\frac{4^{2018}-1}{3}\)
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a) x/7 = 6/21
x/7 = 2/7
=>x=2
b)2/3x -1/2=1/10
2/3x = 1/10+1/2
2/3x = 3/5
x=3/5:2/3
x=9/10
c)1/4+1/3 : x = -5
d)3x+17=2
đ)2/3x +1/4 =7/12
2x+3/10= 11/6 . 6/11
x : 4 1/3 = -2,5
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a) 2x + 1 = 3
2x = 2
x = 1
b) ( 2x - 5 ) + 17 = 6
( 2x - 5 ) = 6 - 17
( 2x - 5 ) = -11
2x = -11 + 5
2x = -6
x = -3
c) 10 - 2 x ( 4 - 3x ) = -4
2 x ( 4 - 3x ) = 14
4 - 3x = 7
3x = -3
x = -1
![](https://rs.olm.vn/images/avt/0.png?1311)
10-2(4-3x)=-4
<=>10-8+6x=-4
<=>2+6x=-4
<=>6x=-6
<=>x=-1
Vậy x=-1
3 -12+3(-x+7)=-18
<=> 3-12-3x+21=-18
<=>12-3x=-18
<=>3x=30
<=>x=10
Vậy x=10
\(10-2\left(4-3x\right)=4\Leftrightarrow10-\left(8-6x\right)=4\)
\(\Leftrightarrow8-6x=10-4=6\Leftrightarrow6x=8-6=2\Leftrightarrow x=\frac{2}{6}=\frac{1}{3}\)
\(3-12+3\left[\left(-x\right)+7\right]=-18\Leftrightarrow\left(-9\right)+\left(-3x\right)+21=18\)
\(\Leftrightarrow\left(-3x\right)+12=18\Leftrightarrow-3x=18-12=6\Leftrightarrow x=6\div\left(-3\right)=-2\)
\(4.24\div\left(3x-2\right)=-3\Leftrightarrow96\div\left(3x-2\right)=-3\Leftrightarrow3x-2=96\div\left(-3\right)=-32\)
\(\Leftrightarrow3x=\left(-32\right)+2=-30\Leftrightarrow x=\left(-30\right)\div3=-10\)
=> 2(4-3x)=10-(-4)
=> 2(4-3x)=14
=> 4-3x=14:2
=> 4-3x=7
=> 3x=4-7
=> 3x=-3
=> x=(-3):3
=> x=(-1)
2(4-3x)=14
4-3x=7
3x=-3
x=-1