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\(\left(2x+1\right)^2=\dfrac{1}{9}\)
⇒ \(\left[{}\begin{matrix}2x+1=\dfrac{1}{3}\\2x+1=-\dfrac{1}{3}\end{matrix}\right.\)
⇒ \(\left[{}\begin{matrix}x=-\dfrac{1}{3}\\x=-\dfrac{2}{3}\end{matrix}\right.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(\Rightarrow9\left(x-1\right)^2-2=\dfrac{1}{4}\\ \Rightarrow9\left(x-1\right)^2=\dfrac{9}{4}\\ \Rightarrow\left(x-1\right)^2=4\\ \Rightarrow\left[{}\begin{matrix}x-1=2\\1-x=2\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=3\\x=-1\end{matrix}\right.\)
![](https://rs.olm.vn/images/avt/0.png?1311)
\(2x-\dfrac{3}{4}=x+\dfrac{1}{3}\cdot\dfrac{-9}{2}\)
\(\Rightarrow2x-x=\dfrac{1}{3}\cdot\dfrac{-9}{2}+\dfrac{3}{4}\)
\(\Rightarrow x=-\dfrac{3}{2}+\dfrac{3}{4}\)
\(\Rightarrow x=-\dfrac{6}{4}+\dfrac{3}{4}=-\dfrac{3}{4}\)
#\(Toru\)
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9/13 x 7/12 + 9/13 x 5/12 - 9/13
= 9/13 x (7/12 + 5/12 - 1)
= 9/13 x 0
= 0
4/13 x 5/12 + 4/13 x 7/12 - 4/3
= 4/13 x (5/12 + 7/12) - 4/3
= 4/13 x 1 - 4/3
= 4/13 - 4/3
= -40/39
dễ :>>
\(x+\frac{4}{9}=\frac{1}{2}\)
\(x=\frac{1}{2}-\frac{4}{9}\)
\(x=\frac{9}{18}-\frac{8}{18}\)
\(x=\frac{1}{18}\)