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a) 27.(-17)+(-17).73
= -17 ( 27+73)
= -17 . 100
= -1700
b) 512 . ( 2- 128) -128. (-512)
= 512.(2-128) - (-128).512
= 512(2-128+128)
= 512 . 2
= 1024
133+625+27.19-25.15
133+625+513-375
625-375+133+513
250+133+513
383+513=896
a) 67.(-18) + (-33).18
= 67.(-18) + 33.(-18)
= (-18).(67 + 33)
= (-18).100
= (-1800)
b) 34.(-53) - (-66).53 - 68.(-53)
= (-34).53 + 66.53 - (-68).53
= (-34).53 + 66.53 + 68.53
= 53. (-34 + 66 + 68)
= 53.100
= 5300
a) 67.(-18) + (-33).18
= 67.(-18) + 33.(-18)
= (-18).(67 + 33)
= (-18).100
= (-1800)
b) 34.(-53) - (-66).53 - 68.(-53)
= (-34).53 + 66.53 - (-68).53
= (-34).53 + 66.53 + 68.53
= 53. (-34 + 66 + 68)
= 53.100
= 5300
chúc bạn học tốt nhé
\(\text{ -(-23) + (-36) + |57| - (-29)}\)
\(23+\left(-36\right)+57+29\)
\(=\left(23+57\right)+\left(\left(-36\right)+29\right)\)
\(=100+\left(-7\right)\)
\(=93\)
học tốt
-452 - ( -67 + 75 - 425 )
= -452 - ( 8 - 425 )
= 452 - ( -417 )
= -35.
_Học tốt#
\(a,\frac{-7}{25}.\frac{11}{13}+\frac{-7}{25}.\frac{2}{13}-\frac{18}{25}\)
\(=\frac{-7}{25}.\left(\frac{11}{13}+\frac{2}{13}\right)-\frac{18}{25}=\frac{-7}{25}-\frac{18}{25}=-1\)
\(b,\frac{5}{7}.\frac{1}{3}-\frac{5}{7}.\frac{1}{4}-\frac{5}{7}.\frac{1}{12}=\frac{5}{7}.\left(\frac{1}{3}-\frac{1}{4}-\frac{1}{12}\right)=\frac{5}{7}.\left(\frac{4}{12}-\frac{3}{12}-\frac{1}{12}\right)\)
\(=\frac{5}{7}.0=0\)
c)\(5\frac{2}{5}.4\frac{2}{7}+5\frac{5}{7}.5\frac{2}{5}=\frac{27}{5}.\frac{30}{7}+\frac{40}{7}.\frac{27}{5}=\frac{27}{5}.\left(\frac{30}{7}+\frac{40}{7}\right)\)
\(=\frac{27}{5}.10=27.2=54\)
\(d,75\%-1\frac{1}{2}+0,5:\frac{5}{12}-\left(\frac{-1}{2}\right)^2=\frac{3}{4}-\frac{3}{2}+\frac{1}{2}.\frac{12}{5}-\frac{1}{4}\)
\(=\left(\frac{3}{4}-\frac{1}{4}\right)-\frac{3}{2}+\frac{6}{5}=\frac{1}{2}-\frac{3}{2}+\frac{6}{5}=-1+\frac{6}{5}=\frac{-5}{5}+\frac{6}{5}=\frac{1}{5}\)
\(\left[219+\left(-299\right)\right]+12.5\)
= \(\left(-80\right)+60\)
= \(-20\)
Hok tốt
-17.(13+5) - 13.(17-2)
=-17.13+(-17).5-13.17+13.2
=-17.13+(-17).5 + 13 . (-17) + 13.2
=-17.(13+5+13) + 13.2
=-17. 31 +26
=-501