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Tui là Huỳnh Quốc Hữu nè, cái bài đó giải như sau:
x=-24; y=-10; z=-120.
Cách giải thì như trong vở nhá!
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a) - 4 \(\ge\)x < -3 => x = - 4
A = {-4}
b) - 9 < x \(\le\)3 => x = -8, -7, -6, -5 , -4, -3, -2, -1, 0, 1 , 2, 3
A = {-8, -7, -6, -5 , -4, -3, -2, -1, 0, 1 , 2, 3}
![](https://rs.olm.vn/images/avt/0.png?1311)
a) Ta có: \(\left(-12\right)-\left|13-x\right|=-21\)
\(\Leftrightarrow-\left|x-13\right|-12=-21\)
\(\Leftrightarrow-\left|x-13\right|=-9\)
\(\Leftrightarrow\left|x-13\right|=9\)
\(\Leftrightarrow\left[{}\begin{matrix}x-13=9\\x-13=-9\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=22\\x=4\end{matrix}\right.\)
Vậy: \(x\in\left\{22;4\right\}\)
b) Ta có: \(8\le\left|x\right|< 9\)
\(\Leftrightarrow\left|x\right|=8\)
\(\Leftrightarrow x\in\left\{8;-8\right\}\)
Vậy: \(x\in\left\{8;-8\right\}\)
c) Ta có: \(x-\left(-25+x\right)=13-x\)
\(\Leftrightarrow x+25-x-13+x=0\)
\(\Leftrightarrow x+12=0\)
hay x=-12
Vậy: x=-12
d) Ta có: \(\left(15-30\right)+x=x-\left(27-\left|-8\right|\right)\)
\(\Leftrightarrow x-15=x-\left(27-8\right)\)
\(\Leftrightarrow x-15-x+19=0\)
\(\Leftrightarrow-4=0\)(vô lý)
Vậy: \(x\in\varnothing\)
![](https://rs.olm.vn/images/avt/0.png?1311)
x.3,7+x.6,3=120b,x.3,7+x.6,3=120
x(3,7+6,3)=120x(3,7+6,3)=120
10x=12010x=120
x=120:10x=120:10
x=12(tm)
(15×24-x):0.25=100 : 1/4
(15×24-x):0.25 = 400
(15x24-x) = 100
360-x =100
x=260
(8.75+1.25 +5+1) x X=20
16 x X=20
X=20 :16
X=1.25
![](https://rs.olm.vn/images/avt/0.png?1311)
\(x-\left(27-x\right)=x-17\)
\(\Leftrightarrow x-27+x=x-17\)
\(\Leftrightarrow x+x-x=-17+27\)
\(\Leftrightarrow x=10\)
Vậy ...
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a,(-12).x= 60-12
(-12).x=48
x=48:(-12)
x = -4
b,(-5).x + 5 = -24+6
(-5).x + 5 = 30
(-5).x = 30-5
(-5).x = 25
x = 25 : (-5)
x = -5
c,
\(\left(27-x\right)+\left(15+x\right)=x-24\)
\(27-x+15+x=x-24\)
\(-x+x-x=-24-27-15\)
\(-x=-66\)
\(x=66\)
(27-x) +(15+x)=x-24
<=>\(27-x+15+x=x-24\)
<=>\(\left(-x\right)+x-x=-2-15-27\)
<=>\(-x=-44\)
<=>\(x=44\)
Vậy x=44