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\(\frac{x}{-15}=\frac{-60}{x}\)
=>x.x=(-15).(-60)
=>x2=900=302=(-30)2
=>x=30,-30
Vậy x=30,-30
\(\frac{x}{-15}=\frac{-60}{x}\)
<=> (-15).(-60) = x.x
<=> 900 = x2
=> x2 = 302 = (-30)2
=> x \(\in\){30; -30}
![](https://rs.olm.vn/images/avt/0.png?1311)
x/-15=-60/x
=> x.x = [-15]. [-60]
=> x^2 = 900
=> x= 30 hoặc -30
-2/x = -x/8
=> -x^2 = -16
=> x^2 = 16
=> x= -4 hoặc 4
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\(-\frac{x}{15}=\frac{-60}{x}\)
(=) \(\frac{x}{-15}=\frac{-60}{x}\)
(=) \(x^2=-15.-60\)
(=) \(x^2=900\)
=> \(\orbr{\begin{cases}x=30\\x=-30\end{cases}}\)
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x(x - 1)(x - 1) = (x - 2)xx(x - 1)
<=> x(x - 1)x(x - 1) - (x - 2)xx(x - 1) = (x - 2)xx(x - 1) - (x - 2)xx(x - 1)
<=> x(x - 1)x(x - 1) - (x - 2)xx(x - 1) = 0
<=> x2(x - 1) = 0
<=> x = 0
<=> x - 1 = 0
x = 0 + 1
x = 1
=> x = 0 hoặc 1
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\(\dfrac{x-1}{-15}=\dfrac{-60}{x-1}\\ \Rightarrow\left(x-1\right)^2=-15\cdot\left(-60\right)\\ \Rightarrow\left(x-1\right)^2=900\\ \Rightarrow\left[{}\begin{matrix}x-1=30\\x-1=-30\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=31\\x=-29\end{matrix}\right.\)
bn nên ghi rõ r. Bn vt thế này mk ko hiểu bn vt cái j cả
\(\frac{x-1}{15}=\frac{-60}{1-x}\)
\(x-1=\frac{900}{1-x}\)
\(\left(x-1\right)\left(1-x\right)=-900\)
\(x-x^2-1+x=-900\)
\(2x-x^2-1=-900\)
\(2x-x^2-1+900=0\)
\(2x-x^2-899=0\)
\(\left(x-31\right)\left(x+29\right)=0\)
\(\orbr{\begin{cases}x-31=0\\x+29=0\end{cases}}\)
\(\orbr{\begin{cases}x=31\\x=-29\end{cases}}\)