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`(-3 .7^4 + 7^3)/(7^5 .6 -7^3 .2)`
`=(7^3 .(-3.7 +1))/(7^3 (7^2 .6 -2))`
`=(-20)/292=-5/73`
Giải:
\(\dfrac{-3.7^4+7^3}{7^5.6-7^3.2}\)
\(=\dfrac{-3.7.7^3+7^3}{7^3.7^2.6-7^3.2}\)
\(=\dfrac{7^3.\left(-3.7+1\right)}{7^3.\left(7^2.6-2\right)}\)
\(=\dfrac{-21+1}{49.6-2}\)
\(=\dfrac{-20}{294-2}\)
\(=\dfrac{-20}{292}=\dfrac{-5}{73}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
ta có
\(-\frac{3^7\cdot2^8}{6^7}=-\frac{3^7\cdot2^7\cdot2}{6^7}=-\frac{6^7\cdot2}{6^7}=-2\)2
\(B=-\frac{3\cdot7^4+7^3}{7^5\cdot6-7^3\cdot2}=-\frac{3\cdot7^3\cdot7+7^3}{7^3\cdot7^2\cdot6-7^3\cdot2}=-\frac{7^3\cdot\left(3\cdot7+1\right)}{7^3\cdot\left(7^2\cdot6-2\right)}=-\frac{5}{73}\)
![](https://rs.olm.vn/images/avt/0.png?1311)
x2 - 4x + 4
= x2 - 2.2x + 22
= x2 - 22
mà x2 - 22 = 0
=> x2 - 4 = 0
=> x2 = 4
=> x2 = 22
=> x = 2
x2 - 4x + 4
= x2 - 2.2x + 22
= x2 - 22
mà x2 - 22 = 0
=> x2 - 4 = 0
=> x2 = 4
=> x2 = 22
=> x = 2
![](https://rs.olm.vn/images/avt/0.png?1311)
(-19,95 - 45,75) + (4,95 + 5,75)
=[(-19,95)+4,95]+[(-45,75)+5,75]
=(-15)+(-40)
=-55
![](https://rs.olm.vn/images/avt/0.png?1311)
Ta có :
5x + 1 - ( 5x - x2 )
= 5x + 1 - 5x + x2
= x2 + 1
vì x2 \(\ge\)0 nên x2 + 1 > 0
Vậy đa thức trên không có nghiệm