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*Sửa lại đề*
A = 21+ 22+ 23+ 24 + .. + 2100
A = (21+22) + (23+ 24) +...+ (299+ 2100)
A = 2.(1+2) + 23.(1+2) + .. + 299. (1+2)
A = 2.3 + 23. 3 + .. + 299.3
A = 3 . (21 + 23 + .... + 299)
Mà 3 chia hết cho 3
=> A chia hết cho 3
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Sửa đề: \(S=2^{100}-2^{99}+2^{98}-...+2^2-2\)
=>\(2\cdot S=2^{101}-2^{100}+2^{99}-...+2^3-2^2\)
=>\(2S+S=2^{100}-2^{99}+2^{98}-...+2^2-2+2^{101}-2^{100}+2^{99}-...+2^3-2^2\)
=>\(3S=2^{101}-2\)
=>\(S=\dfrac{2^{101}-2}{3}\)
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\(4^3\times27-4^3\times23\)
\(=4^3\times\left(27-23\right)\)
\(=64\times4\)
\(=256\)
\(3^4\times71+3^4\times2^9\)
\(=3^4\times\left(71+2^9\right)\)
\(=81\times\left(71+512\right)\)
\(=81\times583\)
\(=47223\)
\(\left(3^3\times5^2-2^4-16\right)\times13\)
\(=\left(27\times25-16-16\right)\times13\)
\(=\left(675-16-16\right)\times13\)
\(=\left(659-16\right)\times13\)
\(=643\times13\)
\(=8359\)
\(35\times273+33\times35\)
\(=35\times\left(273+33\right)\)
\(=35\times306\)
\(=10710\)
\(2^3\times4^2+2^3\times84-40\)
\(=8\times16+8\times84-40\)
\(=8\times\left(16+84\right)-40\)
\(=8\times100-40\)
\(=800-40\)
\(=760\)
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E=1-2-3+4+5-6-7+8+...+21-22-23+24
=0+0+...+0
=0.12
=0
E = 1 - 2 - 3 + 4 + 5 - 6 - 7 + 8 + ... + 21 - 22 - 23 + 24 (có 24 số; 24 chia hết cho 4)
E = (1 - 2 - 3 + 4) + (5 - 6 - 7 + 8) + ... + (21 - 22 - 23 + 24)
E = 0 + 0 + ... + 0
E = 0