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4047991- 2010 . 2009 / 4050000 - 2011 . 2009
=9901/9901
=1
![](https://rs.olm.vn/images/avt/0.png?1311)
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2011 × 2010 - 1 / 2009 × 2011 + 2010
=2011 × 2009 + 2011 - 1 / 2009 × 2011 + 2010
= 2011 × 2009 + (2011 - 1) / 2009 × 2011 + 2010
= 2011 × 2009 + 2010 / 2009 × 2011 + 2010
= 1
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`(2011xx2020-1)/(2009xx2011+2010)`
`=((2009+1)xx2011-1)/(2009xx2011+2010)`
`=(2009xx2011+2011-1)/(2009xx2011+2010)`
`=(2009xx2011+2010)/(2009xx2011+2010)`
`=1`
\(\dfrac{2011.2010-1}{2009.2011+2010}\)
= \(\dfrac{2011.2009+2011-1}{2009.2011+2010}\)
= \(\dfrac{2011.2009+2010}{2009.2011+2010}\)
= 1
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Dễ thấy:
\(\frac{2008}{2009}>\frac{2008}{2009+2010+2011}\)
\(\frac{2009}{2010}>\frac{2009}{2009+2010+2011}\)
\(\frac{2010}{2011}>\frac{2010}{2009+2010+2011}\)
=>\(\frac{2008}{2009}+\frac{2009}{2010}+\frac{2010}{2011}>\frac{2008}{2009+2010+2011}+\frac{2009}{2009+2010+2011}+\frac{2010}{2009+2010+2011}\)
Hay \(\frac{2008}{2009}+\frac{2009}{2010}+\frac{2010}{2011}>\frac{2008+2009+2010}{2009+2010+2011}\)
Vậy A > B
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a. 26-|x+9|=-13
=> |x+9|=26-(-13)
=> |x+9|=39
=> x+9 = 39 hoặc x+9 = -39
=> x=30 hoặc x = -48
Vậy, x thuộc {30, -48}
b. 2011-|x|=2009
=> |x| = 2011-2009
=> |x|=2
=> x = 2 hoặc x = -2
Vậy, x thuộc {2, -2}
c.|x+2010|=2011
=> x + 2010 = 2011 hoặc x + 2010 = -2011
=> x = 2011 - 2010 hoặc x= -2011 - 2010
=> x = 1 hoặc x= -4021
Vậy, x thuộc {1, -4021}
\(A=\frac{4047991-2010.2009}{4050000-2011.2009}\)
\(\Rightarrow A=\frac{404791-2010.2009}{4047911+2009-2011.2009}\)
\(\Rightarrow A=\frac{4047911-2010.2009}{4047911-2010.2009}\)
\(\Rightarrow A=1\)
Vậy A = 1
~Study well~
#๖ۣۜNamiko#
#)Giải :
\(A=\frac{4047991-2010.2009}{4050000-2011.2009}=\frac{407991-2010.2009}{4047991+2009-2011-2009}=\frac{407991-2010.2009}{407991-2010.2009}=1\)
#~Will~be~Pens~#